Anonymous user
Talk:Sum digits of an integer: Difference between revisions
→Input base: Doesn't matter.
(→Input base: yes it does) |
(→Input base: Doesn't matter.) |
||
Line 15:
Does the input base matter at all? No matter what the base is, the digit 1 has value 1, 2 means 2, ... a means 10, ... z means 35. Unless we're expected to throw an error if the input contains a digit that is not valid for the given base, I don't see the point of specifying one? --[[User:Markjreed|Markjreed]] ([[User talk:Markjreed|talk]]) 02:10, 30 January 2015 (UTC)
:10 in binary does not equal 10 in hexadecimal, so unless the input is a single digit, yes, it does need to be specified. -- [[User:Eriksiers|Erik Siers]] ([[User talk:Eriksiers|talk]]) 03:38, 30 January 2015 (UTC)
::But the sum of the '''binary''' ''digits' 10 expressed as a decimal is the sum of ''digits'' 10 in ''any'' valid base when expressed as a decimal, i.e. a one plus a zero equals one! --[[User:Paddy3118|Paddy3118]] ([[User talk:Paddy3118|talk]]) 06:59, 30 January 2015 (UTC)
| |||