Strange unique prime triplets: Difference between revisions
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:* (stretch goal) Show the <u>count</u> (only) of all the triplets of strange unique primes in which '''n, m,''' and '''p''' are all less than '''1,000'''. |
:* (stretch goal) Show the <u>count</u> (only) of all the triplets of strange unique primes in which '''n, m,''' and '''p''' are all less than '''1,000'''. |
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<br><br> |
<br><br> |
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=={{header|11l}}== |
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{{trans|Python}} |
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<lang 11l>F primes_upto(limit) |
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V is_prime = [0B] * 2 [+] [1B] * (limit - 1) |
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L(n) 0 .< Int(limit ^ 0.5 + 1.5) |
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I is_prime[n] |
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L(i) (n * n .< limit + 1).step(n) |
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is_prime[i] = 0B |
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R enumerate(is_prime).filter((i, prime) -> prime).map((i, prime) -> i) |
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F strange_triplets(Int mx = 30) |
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[(Int, Int, Int)] r |
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V primes = Array(primes_upto(mx)) |
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V primes3 = Set(primes_upto(3 * mx)) |
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L(n) primes |
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V i = L.index |
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L(m) primes[i + 1 ..] |
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V j = L.index + i + 1 |
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L(p) primes[j + 1 ..] |
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I n + m + p C primes3 |
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r.append((n, m, p)) |
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R r |
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L(n, m, p) strange_triplets() |
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print(‘#2: #2+#2+#2 = #.’.format(L.index + 1, n, m, p, n + m + p)) |
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V mx = 1'000 |
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print("\nIf n, m, p < #. finds #.".format(mx, sum(strange_triplets(mx).map(_ -> 1))))</lang> |
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{{out}} |
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<pre> |
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1: 3+ 5+11 = 19 |
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2: 3+ 5+23 = 31 |
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3: 3+ 5+29 = 37 |
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4: 3+ 7+13 = 23 |
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5: 3+ 7+19 = 29 |
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6: 3+11+17 = 31 |
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7: 3+11+23 = 37 |
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8: 3+11+29 = 43 |
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9: 3+17+23 = 43 |
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10: 5+ 7+11 = 23 |
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11: 5+ 7+17 = 29 |
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12: 5+ 7+19 = 31 |
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13: 5+ 7+29 = 41 |
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14: 5+11+13 = 29 |
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15: 5+13+19 = 37 |
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16: 5+13+23 = 41 |
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17: 5+13+29 = 47 |
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18: 5+17+19 = 41 |
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19: 5+19+23 = 47 |
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20: 5+19+29 = 53 |
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21: 7+11+13 = 31 |
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22: 7+11+19 = 37 |
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23: 7+11+23 = 41 |
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24: 7+11+29 = 47 |
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25: 7+13+17 = 37 |
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26: 7+13+23 = 43 |
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27: 7+17+19 = 43 |
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28: 7+17+23 = 47 |
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29: 7+17+29 = 53 |
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30: 7+23+29 = 59 |
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31: 11+13+17 = 41 |
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32: 11+13+19 = 43 |
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33: 11+13+23 = 47 |
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34: 11+13+29 = 53 |
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35: 11+17+19 = 47 |
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36: 11+19+23 = 53 |
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37: 11+19+29 = 59 |
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38: 13+17+23 = 53 |
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39: 13+17+29 = 59 |
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40: 13+19+29 = 61 |
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41: 17+19+23 = 59 |
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42: 19+23+29 = 71 |
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If n, m, p < 1000 finds 241580 |
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</pre> |
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=={{header|ALGOL W}}== |
=={{header|ALGOL W}}== |
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| Line 109: | Line 187: | ||
Found 241580 strange unique prime triplets up to 1000 |
Found 241580 strange unique prime triplets up to 1000 |
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</pre> |
</pre> |
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=={{header|AWK}}== |
=={{header|AWK}}== |
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<lang AWK> |
<lang AWK> |
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Revision as of 23:14, 4 June 2021
Strange unique prime triplets is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.
Primes n, m, and p are strange unique primes if n, m, and p are unique and their sum n + m + p is also prime. Assume n < m < p.
- Task
-
- Find all triplets of strange unique primes in which n, m, and p are all less than 30.
- (stretch goal) Show the count (only) of all the triplets of strange unique primes in which n, m, and p are all less than 1,000.
11l
<lang 11l>F primes_upto(limit)
V is_prime = [0B] * 2 [+] [1B] * (limit - 1)
L(n) 0 .< Int(limit ^ 0.5 + 1.5)
I is_prime[n]
L(i) (n * n .< limit + 1).step(n)
is_prime[i] = 0B
R enumerate(is_prime).filter((i, prime) -> prime).map((i, prime) -> i)
F strange_triplets(Int mx = 30)
[(Int, Int, Int)] r
V primes = Array(primes_upto(mx))
V primes3 = Set(primes_upto(3 * mx))
L(n) primes
V i = L.index
L(m) primes[i + 1 ..]
V j = L.index + i + 1
L(p) primes[j + 1 ..]
I n + m + p C primes3
r.append((n, m, p))
R r
L(n, m, p) strange_triplets()
print(‘#2: #2+#2+#2 = #.’.format(L.index + 1, n, m, p, n + m + p))
V mx = 1'000 print("\nIf n, m, p < #. finds #.".format(mx, sum(strange_triplets(mx).map(_ -> 1))))</lang>
- Output:
1: 3+ 5+11 = 19 2: 3+ 5+23 = 31 3: 3+ 5+29 = 37 4: 3+ 7+13 = 23 5: 3+ 7+19 = 29 6: 3+11+17 = 31 7: 3+11+23 = 37 8: 3+11+29 = 43 9: 3+17+23 = 43 10: 5+ 7+11 = 23 11: 5+ 7+17 = 29 12: 5+ 7+19 = 31 13: 5+ 7+29 = 41 14: 5+11+13 = 29 15: 5+13+19 = 37 16: 5+13+23 = 41 17: 5+13+29 = 47 18: 5+17+19 = 41 19: 5+19+23 = 47 20: 5+19+29 = 53 21: 7+11+13 = 31 22: 7+11+19 = 37 23: 7+11+23 = 41 24: 7+11+29 = 47 25: 7+13+17 = 37 26: 7+13+23 = 43 27: 7+17+19 = 43 28: 7+17+23 = 47 29: 7+17+29 = 53 30: 7+23+29 = 59 31: 11+13+17 = 41 32: 11+13+19 = 43 33: 11+13+23 = 47 34: 11+13+29 = 53 35: 11+17+19 = 47 36: 11+19+23 = 53 37: 11+19+29 = 59 38: 13+17+23 = 53 39: 13+17+29 = 59 40: 13+19+29 = 61 41: 17+19+23 = 59 42: 19+23+29 = 71 If n, m, p < 1000 finds 241580
ALGOL W
Based on
<lang algolw>begin % find some strange unique primes - triplets of primes n, m, p %
% where n + m + p is also prime and n =/= m =/= p %
% sets p( 1 :: n ) to a sieve of primes up to n %
procedure Eratosthenes ( logical array p( * ) ; integer value n ) ;
begin
p( 1 ) := false; p( 2 ) := true;
for i := 3 step 2 until n do p( i ) := true;
for i := 4 step 2 until n do p( i ) := false;
for i := 3 step 2 until truncate( sqrt( n ) ) do begin
integer ii; ii := i + i;
if p( i ) then for pr := i * i step ii until n do p( pr ) := false
end for_i ;
end Eratosthenes ;
% we need to find the strange unique prime triplets below 1000 %
integer MAX_PRIME;
MAX_PRIME := 1000;
begin
% the sum of the triplets could be (roughly) 3 x the largest prime %
logical array p ( 1 :: MAX_PRIME * 3 );
integer sCount, c30;
% construct a sieve of primes up to MAX_PRIME * 3 %
Eratosthenes( p, MAX_PRIME * 3 );
% count the nice prime triplets whose members are less than 1000 %
% and prime the first 30 %
sCount := c30 := 0;
% 2 cannot be one of the primes as the sum would be even otherwise %
for n := 3 step 2 until MAX_PRIME - 5 do begin
if p( n ) then begin
for m := n + 2 step 2 until MAX_PRIME - 3 do begin
if p( m ) then begin
for l := m + 2 STEP 2 until MAX_PRIME do begin
if p( l ) then begin
integer s;
s := n + m + l;
if p( s ) then begin
sCount := sCount + 1;
if l <= 30 and m <= 30 and n <= 30 then begin
c30 := c30 + 1;
write( i_w := 3, s_w := 0, c30, ": ", n, " + ", m, " + ", l, " = ", s )
end if_l_m_n_le_30
end if_p_s
end if_p_l
end for_l
end if_p_m
end for_m
end if_p_n
end for_n ;
write( i_w := 3, s_w := 0, "Found ", c30, " strange unique prime triplets up to 30" );
write( i_w := 3, s_w := 0, "Found ", sCount, " strange unique prime triplets up to 1000" );
end
end.</lang>
- Output:
1: 3 + 5 + 11 = 19 2: 3 + 5 + 23 = 31 3: 3 + 5 + 29 = 37 4: 3 + 7 + 13 = 23 5: 3 + 7 + 19 = 29 6: 3 + 11 + 17 = 31 7: 3 + 11 + 23 = 37 8: 3 + 11 + 29 = 43 9: 3 + 17 + 23 = 43 10: 5 + 7 + 11 = 23 11: 5 + 7 + 17 = 29 12: 5 + 7 + 19 = 31 13: 5 + 7 + 29 = 41 14: 5 + 11 + 13 = 29 15: 5 + 13 + 19 = 37 16: 5 + 13 + 23 = 41 17: 5 + 13 + 29 = 47 18: 5 + 17 + 19 = 41 19: 5 + 19 + 23 = 47 20: 5 + 19 + 29 = 53 21: 7 + 11 + 13 = 31 22: 7 + 11 + 19 = 37 23: 7 + 11 + 23 = 41 24: 7 + 11 + 29 = 47 25: 7 + 13 + 17 = 37 26: 7 + 13 + 23 = 43 27: 7 + 17 + 19 = 43 28: 7 + 17 + 23 = 47 29: 7 + 17 + 29 = 53 30: 7 + 23 + 29 = 59 31: 11 + 13 + 17 = 41 32: 11 + 13 + 19 = 43 33: 11 + 13 + 23 = 47 34: 11 + 13 + 29 = 53 35: 11 + 17 + 19 = 47 36: 11 + 19 + 23 = 53 37: 11 + 19 + 29 = 59 38: 13 + 17 + 23 = 53 39: 13 + 17 + 29 = 59 40: 13 + 19 + 29 = 61 41: 17 + 19 + 23 = 59 42: 19 + 23 + 29 = 71 Found 42 strange unique prime triplets up to 30 Found 241580 strange unique prime triplets up to 1000
AWK
<lang AWK>
- syntax: GAWK -f STRANGE_UNIQUE_PRIME_TRIPLETS.AWK
- converted from Go
BEGIN {
main(29,1) main(999,0) exit(0)
} function main(n,show, count,i,j,k,s) {
for (i=3; i<=n-4; i+=2) {
if (is_prime(i)) {
for (j=i+2; j<=n-2; j+=2) {
if (is_prime(j)) {
for (k=j+2; k<=n; k+=2) {
if (is_prime(k)) {
s = i + j + k
if (is_prime(s)) {
count++
if (show == 1) {
printf("%2d + %2d + %2d = %d\n",i,j,k,s)
}
}
}
}
}
}
}
}
printf("Unique prime triples 2-%d which sum to a prime: %'d\n\n",n,count)
} function is_prime(x, i) {
if (x <= 1) {
return(0)
}
for (i=2; i<=int(sqrt(x)); i++) {
if (x % i == 0) {
return(0)
}
}
return(1)
} </lang>
- Output:
3 + 5 + 11 = 19 3 + 5 + 23 = 31 3 + 5 + 29 = 37 3 + 7 + 13 = 23 3 + 7 + 19 = 29 3 + 11 + 17 = 31 3 + 11 + 23 = 37 3 + 11 + 29 = 43 3 + 17 + 23 = 43 5 + 7 + 11 = 23 5 + 7 + 17 = 29 5 + 7 + 19 = 31 5 + 7 + 29 = 41 5 + 11 + 13 = 29 5 + 13 + 19 = 37 5 + 13 + 23 = 41 5 + 13 + 29 = 47 5 + 17 + 19 = 41 5 + 19 + 23 = 47 5 + 19 + 29 = 53 7 + 11 + 13 = 31 7 + 11 + 19 = 37 7 + 11 + 23 = 41 7 + 11 + 29 = 47 7 + 13 + 17 = 37 7 + 13 + 23 = 43 7 + 17 + 19 = 43 7 + 17 + 23 = 47 7 + 17 + 29 = 53 7 + 23 + 29 = 59 11 + 13 + 17 = 41 11 + 13 + 19 = 43 11 + 13 + 23 = 47 11 + 13 + 29 = 53 11 + 17 + 19 = 47 11 + 19 + 23 = 53 11 + 19 + 29 = 59 13 + 17 + 23 = 53 13 + 17 + 29 = 59 13 + 19 + 29 = 61 17 + 19 + 23 = 59 19 + 23 + 29 = 71 Unique prime triples 2-29 which sum to a prime: 42 Unique prime triples 2-999 which sum to a prime: 241,580
C#
Just for fun, <30 sorted by sum, instead of order generated. One might think one should include the sieve generation time, but it is orders of magnitude smaller than the permute/sum time for these relatively low numbers. <lang csharp>using System; using System.Collections.Generic; using static System.Console; using System.Linq; using DT = System.DateTime;
class Program { static void Main(string[] args) { string s;
foreach (int lmt in new int[]{ 90, 300, 3000, 30000, 111000 }) {
var pr = PG.Primes(lmt).Skip(1).ToList(); DT st = DT.Now;
int d, f = 0; var r = new List<string>();
int i = -1, m, h = (m = lmt / 3), j, k, pra, prab;
while (i < 0) i = pr.IndexOf(h--); k = (j = i - 1) - 1;
for (int a = 0; a <= k; a++) { pra = pr[a];
for (int b = a + 1; b <= j; b++) { prab = pra + pr[b];
for (int c = b + 1; c <= i; c++) {
if (PG.flags[d = prab + pr[c]]) continue; f++;
if (lmt < 100) r.Add(string.Format("{3,5} = {0,2} + {1,2} + {2,2}", pra, pr[b], pr[c], d)); } } }
s = "s.u.p.t.s under "; r.Sort(); if (r.Count > 0) WriteLine("{0}{1}:\n{2}", s, m, string.Join("\n", r));
if (lmt > 100) WriteLine("Count of {0}{1,6:n0}: {2,13:n0} {3} sec", s, m, f, (DT.Now - st).ToString().Substring(6)); } } }
class PG { public static bool[] flags;
public static IEnumerable<int> Primes(int lim) {
flags = new bool[lim + 1]; int j = 2;
for (int d = 3, sq = 4; sq <= lim; j++, sq += d += 2)
if (!flags[j]) { yield return j;
for (int k = sq; k <= lim; k += j) flags[k] = true; }
for (; j <= lim; j++) if (!flags[j]) yield return j; } }</lang>
- Output:
Timings from tio.run
s.u.p.t.s under 30: 19 = 3 + 5 + 11 23 = 3 + 7 + 13 23 = 5 + 7 + 11 29 = 3 + 7 + 19 29 = 5 + 7 + 17 29 = 5 + 11 + 13 31 = 3 + 5 + 23 31 = 3 + 11 + 17 31 = 5 + 7 + 19 31 = 7 + 11 + 13 37 = 3 + 5 + 29 37 = 3 + 11 + 23 37 = 5 + 13 + 19 37 = 7 + 11 + 19 37 = 7 + 13 + 17 41 = 5 + 7 + 29 41 = 5 + 13 + 23 41 = 5 + 17 + 19 41 = 7 + 11 + 23 41 = 11 + 13 + 17 43 = 3 + 11 + 29 43 = 3 + 17 + 23 43 = 7 + 13 + 23 43 = 7 + 17 + 19 43 = 11 + 13 + 19 47 = 5 + 13 + 29 47 = 5 + 19 + 23 47 = 7 + 11 + 29 47 = 7 + 17 + 23 47 = 11 + 13 + 23 47 = 11 + 17 + 19 53 = 5 + 19 + 29 53 = 7 + 17 + 29 53 = 11 + 13 + 29 53 = 11 + 19 + 23 53 = 13 + 17 + 23 59 = 7 + 23 + 29 59 = 11 + 19 + 29 59 = 13 + 17 + 29 59 = 17 + 19 + 23 61 = 13 + 19 + 29 71 = 19 + 23 + 29 Count of s.u.p.t.s under 100: 891 00.0000243 sec Count of s.u.p.t.s under 1,000: 241,580 00.0054753 sec Count of s.u.p.t.s under 10,000: 74,588,542 01.8159964 sec Count of s.u.p.t.s under 37,000: 2,141,379,201 55.0369689 sec
C++
<lang cpp>#include <iomanip>
- include <iostream>
- include <vector>
std::vector<bool> prime_sieve(size_t limit) {
std::vector<bool> sieve(limit, true);
if (limit > 0)
sieve[0] = false;
if (limit > 1)
sieve[1] = false;
for (size_t i = 4; i < limit; i += 2)
sieve[i] = false;
for (size_t p = 3; ; p += 2) {
size_t q = p * p;
if (q >= limit)
break;
if (sieve[p]) {
size_t inc = 2 * p;
for (; q < limit; q += inc)
sieve[q] = false;
}
}
return sieve;
}
void strange_unique_prime_triplets(int limit, bool verbose) {
std::vector<bool> sieve = prime_sieve(limit * 3);
std::vector<int> primes;
for (int p = 3; p < limit; p += 2) {
if (sieve[p])
primes.push_back(p);
}
size_t n = primes.size();
size_t count = 0;
if (verbose)
std::cout << "Strange unique prime triplets < " << limit << ":\n";
for (size_t i = 0; i + 2 < n; ++i) {
for (size_t j = i + 1; j + 1 < n; ++j) {
for (size_t k = j + 1; k < n; ++k) {
int sum = primes[i] + primes[j] + primes[k];
if (sieve[sum]) {
++count;
if (verbose) {
std::cout << std::setw(2) << primes[i] << " + "
<< std::setw(2) << primes[j] << " + "
<< std::setw(2) << primes[k] << " = " << sum
<< '\n';
}
}
}
}
}
std::cout << "\nCount of strange unique prime triplets < " << limit
<< " is " << count << ".\n";
}
int main() {
strange_unique_prime_triplets(30, true); strange_unique_prime_triplets(1000, false); return 0;
}</lang>
- Output:
Strange unique prime triplets < 30: 3 + 5 + 11 = 19 3 + 5 + 23 = 31 3 + 5 + 29 = 37 3 + 7 + 13 = 23 3 + 7 + 19 = 29 3 + 11 + 17 = 31 3 + 11 + 23 = 37 3 + 11 + 29 = 43 3 + 17 + 23 = 43 5 + 7 + 11 = 23 5 + 7 + 17 = 29 5 + 7 + 19 = 31 5 + 7 + 29 = 41 5 + 11 + 13 = 29 5 + 13 + 19 = 37 5 + 13 + 23 = 41 5 + 13 + 29 = 47 5 + 17 + 19 = 41 5 + 19 + 23 = 47 5 + 19 + 29 = 53 7 + 11 + 13 = 31 7 + 11 + 19 = 37 7 + 11 + 23 = 41 7 + 11 + 29 = 47 7 + 13 + 17 = 37 7 + 13 + 23 = 43 7 + 17 + 19 = 43 7 + 17 + 23 = 47 7 + 17 + 29 = 53 7 + 23 + 29 = 59 11 + 13 + 17 = 41 11 + 13 + 19 = 43 11 + 13 + 23 = 47 11 + 13 + 29 = 53 11 + 17 + 19 = 47 11 + 19 + 23 = 53 11 + 19 + 29 = 59 13 + 17 + 23 = 53 13 + 17 + 29 = 59 13 + 19 + 29 = 61 17 + 19 + 23 = 59 19 + 23 + 29 = 71 Count of strange unique prime triplets < 30 is 42. Count of strange unique prime triplets < 1000 is 241580.
Delphi
<lang Delphi> program Strange_primes;
{$APPTYPE CONSOLE}
uses
System.SysUtils;
function IsPrime(n: Integer): Boolean; begin
if n < 2 then exit(false);
if n mod 2 = 0 then exit(n = 2);
if n mod 3 = 0 then exit(n = 3);
var d := 5;
while d * d <= n do
begin
if n mod d = 0 then
exit(false);
inc(d, 2);
if n mod d = 0 then
exit(false);
inc(d, 4); end; Result := true;
end;
function Commatize(value: Integer): string; begin
Result := FloatToStrF(value, ffNumber, 10, 0);
end;
function StrangePrimes(n: Integer; countOnly: Boolean): Integer; begin
var c := 0; var f := '%2d: %2d + %2d + %2d = %2d'#10; var s: Integer := 0;
var i := 3;
while i <= n - 4 do
begin
if IsPrime(i) then
begin
var j := i + 2;
while j <= n - 2 do
begin
if IsPrime(j) then
begin
var k := j + 2;
while k <= n do
begin
if IsPrime(k) then
begin
s := i + j + k;
if IsPrime(s) then
begin
inc(c);
if not countOnly then
write(format(f, [c, i, j, k, s]));
end;
end;
inc(k, 2);
end;
end;
inc(j, 2);
end;
end;
inc(i, 2);
end;
Result := c;
end;
begin
Writeln('Unique prime triples under 30 which sum to a prime:');
strangePrimes(29, false);
var cs := commatize(strangePrimes(999, true));
writeln('There are ', cs, ' unique prime triples under 1,000 which sum to a prime.');
readln;
end.</lang>
F#
This task uses Extensible Prime Generator (F#).
<lang fsharp>
// Strange unique prime triplets. Nigel Galloway: March 12th., 2021
let sP n=let N=primes32()|>Seq.takeWhile((>)n)|>Array.ofSeq
seq{for n in 0..N.Length-1 do for i in n+1..N.Length-1 do for g in i+1..N.Length-1->(N.[n],N.[i],N.[g])}|>Seq.filter(fun(n,i,g)->isPrime(n+i+g))
sP 30|>Seq.iteri(fun n(i,g,l)->printfn "%2d: %2d+%2d+%2d=%2d") printfn "%d" (Seq.length(sP 1000)) printfn "%d" (Seq.length(sP 10000)) </lang>
- Output:
241580 74588542
Factor
<lang factor>USING: formatting io kernel math math.combinatorics math.primes sequences tools.memory.private ;
- .triplet ( seq -- ) "%2d+%2d+%2d = %d\n" vprintf ;
- strange ( n -- )
primes-upto 3 [ dup sum dup prime? [ suffix .triplet ] [ 2drop ] if ] each-combination ;
- count-strange ( n -- count )
0 swap primes-upto 3 [ sum prime? [ 1 + ] when ] each-combination ;
30 strange 1,000 count-strange commas nl "Found %s strange prime triplets with n, m, p < 1,000.\n" printf</lang>
- Output:
3+ 5+11 = 19 3+ 5+23 = 31 3+ 5+29 = 37 3+ 7+13 = 23 3+ 7+19 = 29 3+11+17 = 31 3+11+23 = 37 3+11+29 = 43 3+17+23 = 43 5+ 7+11 = 23 5+ 7+17 = 29 5+ 7+19 = 31 5+ 7+29 = 41 5+11+13 = 29 5+13+19 = 37 5+13+23 = 41 5+13+29 = 47 5+17+19 = 41 5+19+23 = 47 5+19+29 = 53 7+11+13 = 31 7+11+19 = 37 7+11+23 = 41 7+11+29 = 47 7+13+17 = 37 7+13+23 = 43 7+17+19 = 43 7+17+23 = 47 7+17+29 = 53 7+23+29 = 59 11+13+17 = 41 11+13+19 = 43 11+13+23 = 47 11+13+29 = 53 11+17+19 = 47 11+19+23 = 53 11+19+29 = 59 13+17+23 = 53 13+17+29 = 59 13+19+29 = 61 17+19+23 = 59 19+23+29 = 71 Found 241,580 strange prime triplets with n, m, p < 1,000.
Fermat
<lang fermat>Function IsSUPT(n,m,p) =
if Isprime(n) and Isprime(m) and Isprime(p) and Isprime(n+m+p) then 1 else 0 fi.
for n=3 to 19 do
for m=n+2 to 23 do
for p=m+2 to 29 do
if IsSUPT(n,m,p) then !!(n,m,p) fi;
od;
od;
od</lang> I'll leave the stretch goal for someone else.
FreeBASIC
Use the function at Primality by trial division#FreeBASIC as an include; I can't be bothered reproducing it here. <lang freebasic>#include"isprime.bas"
dim as uinteger c = 0
for p as uinteger = 3 to 997
if not isprime(p) then continue for
for m as uinteger = p + 1 to 998
if not isprime(m) then continue for
for n as uinteger = m + 1 to 999
if not isprime(n) then continue for
if isprime(p + n + m) then
c = c + 1
if n < 30 then print p;" + ";m;" + ";n;" = "; p + m + n
end if
next n
next m
next p
print "There are ";c;" triples below 1000."</lang>
- Output:
3 + 5 + 11 = 193 + 5 + 23 = 31 3 + 5 + 29 = 37 3 + 7 + 13 = 23 3 + 7 + 19 = 29 3 + 11 + 17 = 31 3 + 11 + 23 = 37 3 + 11 + 29 = 43 3 + 17 + 23 = 43 5 + 7 + 11 = 23 5 + 7 + 17 = 29 5 + 7 + 19 = 31 5 + 7 + 29 = 41 5 + 11 + 13 = 29 5 + 13 + 19 = 37 5 + 13 + 23 = 41 5 + 13 + 29 = 47 5 + 17 + 19 = 41 5 + 19 + 23 = 47 5 + 19 + 29 = 53 7 + 11 + 13 = 31 7 + 11 + 19 = 37 7 + 11 + 23 = 41 7 + 11 + 29 = 47 7 + 13 + 17 = 37 7 + 13 + 23 = 43 7 + 17 + 19 = 43 7 + 17 + 23 = 47 7 + 17 + 29 = 53 7 + 23 + 29 = 59 11 + 13 + 17 = 41 11 + 13 + 19 = 43 11 + 13 + 23 = 47 11 + 13 + 29 = 53 11 + 17 + 19 = 47 11 + 19 + 23 = 53 11 + 19 + 29 = 59 13 + 17 + 23 = 53 13 + 17 + 29 = 59 13 + 19 + 29 = 61 17 + 19 + 23 = 59 19 + 23 + 29 = 71
There are 241580 triples below 1000.
Forth
<lang forth>: prime? ( n -- ? ) here + c@ 0= ;
- notprime! ( n -- ) here + 1 swap c! ;
- prime_sieve ( n -- )
here over erase
0 notprime!
1 notprime!
dup 4 > if
dup 4 do i notprime! 2 +loop
then
3
begin
2dup dup * >
while
dup prime? if
2dup dup * do
i notprime!
dup 2* +loop
then
2 +
repeat
2drop ;
- print_strange_unique_prime_triplets ( n -- )
dup 8 < if drop exit then
dup 3 * prime_sieve
dup 4 - 3 do
i prime? if
dup 2 - i 2 + do
i prime? if
dup i 2 + do
i prime? if
i j k + + dup prime? if
k 2 .r ." + " j 2 .r ." + " i 2 .r ." = " 2 .r cr
else
drop
then
then
2 +loop
then
2 +loop
then
2 +loop drop ;
- count_strange_unique_prime_triplets ( n -- n )
dup 8 < if drop 0 exit then
dup 3 * prime_sieve
0 swap
dup 4 - 3 do
i prime? if
dup 2 - i 2 + do
i prime? if
dup i 2 + do
i prime? if
i j k + + prime? if
swap 1+ swap
then
then
2 +loop
then
2 +loop
then
2 +loop drop ;
." Strange unique prime triplets < 30:" cr 30 print_strange_unique_prime_triplets
." Count of strange unique prime triplets < 1000: " 1000 count_strange_unique_prime_triplets . cr bye</lang>
- Output:
Strange unique prime triplets < 30: 3 + 5 + 11 = 19 3 + 5 + 23 = 31 3 + 5 + 29 = 37 3 + 7 + 13 = 23 3 + 7 + 19 = 29 3 + 11 + 17 = 31 3 + 11 + 23 = 37 3 + 11 + 29 = 43 3 + 17 + 23 = 43 5 + 7 + 11 = 23 5 + 7 + 17 = 29 5 + 7 + 19 = 31 5 + 7 + 29 = 41 5 + 11 + 13 = 29 5 + 13 + 19 = 37 5 + 13 + 23 = 41 5 + 13 + 29 = 47 5 + 17 + 19 = 41 5 + 19 + 23 = 47 5 + 19 + 29 = 53 7 + 11 + 13 = 31 7 + 11 + 19 = 37 7 + 11 + 23 = 41 7 + 11 + 29 = 47 7 + 13 + 17 = 37 7 + 13 + 23 = 43 7 + 17 + 19 = 43 7 + 17 + 23 = 47 7 + 17 + 29 = 53 7 + 23 + 29 = 59 11 + 13 + 17 = 41 11 + 13 + 19 = 43 11 + 13 + 23 = 47 11 + 13 + 29 = 53 11 + 17 + 19 = 47 11 + 19 + 23 = 53 11 + 19 + 29 = 59 13 + 17 + 23 = 53 13 + 17 + 29 = 59 13 + 19 + 29 = 61 17 + 19 + 23 = 59 19 + 23 + 29 = 71 Count of strange unique prime triplets < 1000: 241580
Go
Basic
<lang go>package main
import "fmt"
func isPrime(n int) bool {
switch {
case n < 2:
return false
case n%2 == 0:
return n == 2
case n%3 == 0:
return n == 3
default:
d := 5
for d*d <= n {
if n%d == 0 {
return false
}
d += 2
if n%d == 0 {
return false
}
d += 4
}
return true
}
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return s
}
return "-" + s
}
func strangePrimes(n int, countOnly bool) int {
c := 0 f := "%2d: %2d + %2d + %2d = %2d\n" var s int
for i := 3; i <= n-4; i += 2 {
if isPrime(i) {
for j := i + 2; j <= n-2; j += 2 {
if isPrime(j) {
for k := j + 2; k <= n; k += 2 {
if isPrime(k) {
s = i + j + k
if isPrime(s) {
c++
if !countOnly {
fmt.Printf(f, c, i, j, k, s)
}
}
}
}
}
}
}
}
return c
}
func main() {
fmt.Println("Unique prime triples under 30 which sum to a prime:")
strangePrimes(29, false)
cs := commatize(strangePrimes(999, true))
fmt.Printf("\nThere are %s unique prime triples under 1,000 which sum to a prime.\n", cs)
}</lang>
- Output:
Unique prime triples under 30 which sum to a prime: 1: 3 + 5 + 11 = 19 2: 3 + 5 + 23 = 31 3: 3 + 5 + 29 = 37 4: 3 + 7 + 13 = 23 5: 3 + 7 + 19 = 29 6: 3 + 11 + 17 = 31 7: 3 + 11 + 23 = 37 8: 3 + 11 + 29 = 43 9: 3 + 17 + 23 = 43 10: 5 + 7 + 11 = 23 11: 5 + 7 + 17 = 29 12: 5 + 7 + 19 = 31 13: 5 + 7 + 29 = 41 14: 5 + 11 + 13 = 29 15: 5 + 13 + 19 = 37 16: 5 + 13 + 23 = 41 17: 5 + 13 + 29 = 47 18: 5 + 17 + 19 = 41 19: 5 + 19 + 23 = 47 20: 5 + 19 + 29 = 53 21: 7 + 11 + 13 = 31 22: 7 + 11 + 19 = 37 23: 7 + 11 + 23 = 41 24: 7 + 11 + 29 = 47 25: 7 + 13 + 17 = 37 26: 7 + 13 + 23 = 43 27: 7 + 17 + 19 = 43 28: 7 + 17 + 23 = 47 29: 7 + 17 + 29 = 53 30: 7 + 23 + 29 = 59 31: 11 + 13 + 17 = 41 32: 11 + 13 + 19 = 43 33: 11 + 13 + 23 = 47 34: 11 + 13 + 29 = 53 35: 11 + 17 + 19 = 47 36: 11 + 19 + 23 = 53 37: 11 + 19 + 29 = 59 38: 13 + 17 + 23 = 53 39: 13 + 17 + 29 = 59 40: 13 + 19 + 29 = 61 41: 17 + 19 + 23 = 59 42: 19 + 23 + 29 = 71 There are 241,580 unique prime triples under 1,000 which sum to a prime.
Faster
<lang go>package main
import "fmt"
var sieved []bool var p = []int{2}
func sieve(limit int) []bool {
limit++
// True denotes composite, false denotes prime.
c := make([]bool, limit) // all false by default
c[0] = true
c[1] = true
// no need to bother with even numbers over 2 for this task
p := 3 // Start from 3.
for {
p2 := p * p
if p2 >= limit {
break
}
for i := p2; i < limit; i += 2 * p {
c[i] = true
}
for {
p += 2
if !c[p] {
break
}
}
}
return c
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return s
}
return "-" + s
}
func strangePrimes(n int, countOnly bool) int {
c := 0
f := "%2d: %2d + %2d + %2d = %2d\n"
var r, s int
m := 0
for ; m < len(p) && p[m] <= n; m++ {
}
for i := 1; i < m-2; i++ {
for j := i + 1; j < m-1; j++ {
r = p[i] + p[j]
for k := j + 1; k < m; k++ {
s = r + p[k]
if !sieved[s] {
c++
if !countOnly {
fmt.Printf(f, c, p[i], p[j], p[k], s)
}
}
}
}
}
return c
}
func main() {
const max = 1000
sieved = sieve(3*max)
for i := 3; i <= max; i += 2 {
if !sieved[i] {
p = append(p, i)
}
}
fmt.Println("Unique prime triples under 30 which sum to a prime:")
strangePrimes(29, false)
cs := commatize(strangePrimes(999, true))
fmt.Printf("\nThere are %s unique prime triples under 1,000 which sum to a prime.\n", cs)
}</lang>
- Output:
Same as 'basic' version.
Java
<lang java>import java.util.*;
public class StrangeUniquePrimeTriplets {
public static void main(String[] args) {
strangeUniquePrimeTriplets(30, true);
strangeUniquePrimeTriplets(1000, false);
}
private static void strangeUniquePrimeTriplets(int limit, boolean verbose) {
boolean[] sieve = primeSieve(limit * 3);
List<Integer> primeList = new ArrayList<>();
for (int p = 3; p < limit; p += 2) {
if (sieve[p])
primeList.add(p);
}
int n = primeList.size();
// Convert object list to primitive array for performance
int[] primes = new int[n];
for (int i = 0; i < n; ++i)
primes[i] = primeList.get(i);
int count = 0;
if (verbose)
System.out.printf("Strange unique prime triplets < %d:\n", limit);
for (int i = 0; i + 2 < n; ++i) {
for (int j = i + 1; j + 1 < n; ++j) {
int s = primes[i] + primes[j];
for (int k = j + 1; k < n; ++k) {
int sum = s + primes[k];
if (sieve[sum]) {
++count;
if (verbose)
System.out.printf("%2d + %2d + %2d = %2d\n", primes[i], primes[j], primes[k], sum);
}
}
}
}
System.out.printf("\nCount of strange unique prime triplets < %d is %d.\n", limit, count);
}
private static boolean[] primeSieve(int limit) {
boolean[] sieve = new boolean[limit];
Arrays.fill(sieve, true);
if (limit > 0)
sieve[0] = false;
if (limit > 1)
sieve[1] = false;
for (int i = 4; i < limit; i += 2)
sieve[i] = false;
for (int p = 3; ; p += 2) {
int q = p * p;
if (q >= limit)
break;
if (sieve[p]) {
int inc = 2 * p;
for (; q < limit; q += inc)
sieve[q] = false;
}
}
return sieve;
}
}</lang>
- Output:
Strange unique prime triplets < 30: 3 + 5 + 11 = 19 3 + 5 + 23 = 31 3 + 5 + 29 = 37 3 + 7 + 13 = 23 3 + 7 + 19 = 29 3 + 11 + 17 = 31 3 + 11 + 23 = 37 3 + 11 + 29 = 43 3 + 17 + 23 = 43 5 + 7 + 11 = 23 5 + 7 + 17 = 29 5 + 7 + 19 = 31 5 + 7 + 29 = 41 5 + 11 + 13 = 29 5 + 13 + 19 = 37 5 + 13 + 23 = 41 5 + 13 + 29 = 47 5 + 17 + 19 = 41 5 + 19 + 23 = 47 5 + 19 + 29 = 53 7 + 11 + 13 = 31 7 + 11 + 19 = 37 7 + 11 + 23 = 41 7 + 11 + 29 = 47 7 + 13 + 17 = 37 7 + 13 + 23 = 43 7 + 17 + 19 = 43 7 + 17 + 23 = 47 7 + 17 + 29 = 53 7 + 23 + 29 = 59 11 + 13 + 17 = 41 11 + 13 + 19 = 43 11 + 13 + 23 = 47 11 + 13 + 29 = 53 11 + 17 + 19 = 47 11 + 19 + 23 = 53 11 + 19 + 29 = 59 13 + 17 + 23 = 53 13 + 17 + 29 = 59 13 + 19 + 29 = 61 17 + 19 + 23 = 59 19 + 23 + 29 = 71 Count of strange unique prime triplets < 30 is 42. Count of strange unique prime triplets < 1000 is 241580.
Julia
<lang julia>using Primes
function prime_sum_prime_triplets_to(N, verbose=false)
a = primes(3, N)
prime_sieve_set = primesmask(1, N * 3)
len, triplets, n = length(a), Dict{Tuple{Int64,Int64,Int64}, Int}(), 0
for i in eachindex(a), j in i+1:len, k in j+1:len
if prime_sieve_set[a[i] + a[j] + a[k]]
verbose && (triplets[(a[i], a[j], a[k])] = 1)
n += 1
end
end
if verbose
len = (length(string(N)) + 2) * 3
println("\n", rpad("Triplet", len), "Sum\n", "-"^(len+3))
for k in sort(collect(keys(triplets)), lt = (x, y) -> collect(x) < collect(y))
println(rpad(k, len), sum(k))
end
end
println("\n\n$n unique triplets of 3 primes between 2 and $N sum to a prime.")
return triplets
end
prime_sum_prime_triplets_to(30, true) prime_sum_prime_triplets_to(1000) @time prime_sum_prime_triplets_to(10000) @time prime_sum_prime_triplets_to(100000)
</lang>
- Output:
Triplet Sum --------------- (3, 5, 11) 19 (3, 5, 23) 31 (3, 5, 29) 37 (3, 7, 13) 23 (3, 7, 19) 29 (3, 11, 17) 31 (3, 11, 23) 37 (3, 11, 29) 43 (3, 17, 23) 43 (5, 7, 11) 23 (5, 7, 17) 29 (5, 7, 19) 31 (5, 7, 29) 41 (5, 11, 13) 29 (5, 13, 19) 37 (5, 13, 23) 41 (5, 13, 29) 47 (5, 17, 19) 41 (5, 19, 23) 47 (5, 19, 29) 53 (7, 11, 13) 31 (7, 11, 19) 37 (7, 11, 23) 41 (7, 11, 29) 47 (7, 13, 17) 37 (7, 13, 23) 43 (7, 17, 19) 43 (7, 17, 23) 47 (7, 17, 29) 53 (7, 23, 29) 59 (11, 13, 17)41 (11, 13, 19)43 (11, 13, 23)47 (11, 13, 29)53 (11, 17, 19)47 (11, 19, 23)53 (11, 19, 29)59 (13, 17, 23)53 (13, 17, 29)59 (13, 19, 29)61 (17, 19, 23)59 (19, 23, 29)71 42 unique triplets of 3 primes between 2 and 30 sum to a prime. 241580 unique triplets of 3 primes between 2 and 1000 sum to a prime. 74588542 unique triplets of 3 primes between 2 and 10000 sum to a prime. 0.509732 seconds (31 allocations: 25.938 KiB) 28694800655 unique triplets of 3 primes between 2 and 100000 sum to a prime. 224.940756 seconds (35 allocations: 218.156 KiB)
Pascal
<lang pascal>program PrimeTriplets; //Free Pascal Compiler version 3.2.1 [2020/11/03] for x86_64fpc 3.2.1 {$IFDEF FPC}
{$MODE DELPHI}
{$Optimization ON,ALL}
{$ELSE}
{$APPTYPE CONSOLE}
{$ENDIF} const
MAXZAHL = 100000;// > 3 MAXSUM = 3*MAXZAHL;
CountOfPrimes = trunc(MAXZAHL/(ln(MAXZAHL)-1.08))+100;
type
tChkprimes = array[0..MAXSUM] of byte;//prime == 1 , nonprime == 0
var
Chkprimes:tChkprimes; primes : array[0..CountOfPrimes]of Uint32;//here starting with 3 count,primeCount:NativeInt;
procedure InitPrimes; //sieve of eratothenes var
i,j : NativeInt;
begin
fillchar(Chkprimes,SizeOf(tChkprimes),#1);
i := 2;
j := 2*2;
if j> MAXSUM then
EXIT;
repeat
Chkprimes[j]:= 0;
inc(j,i);
until j> Maxsum;
For i := 3 to MAXSUM do
Begin
if Chkprimes[i] <>0 then
Begin
j := i*i;
if j> MAXSUM then
Break;
repeat
Chkprimes[j]:= 0;
inc(j,2*i);
until j> Maxsum;
end;
end;
j := 0;
For i := 3 to MAXZAHL do
IF Chkprimes[i]<>0 then
Begin
primes[j] := i;
inc(j);
end;
primeCount := j-1;
j :=CountOfPrimes -primeCount;
IF j <0 then
begin
writeln(' Need more space for primes ', -j);
HALT(-243);
end;
end;
function GetMaxPrimeIdx(lmt:NativeInt):NativeInt; begin
if lmt >= Maxzahl then Begin result := primecount; EXIT; end; result := 0; while (result < primecount) AND (primes[result]<lmt) do inc(result); dec(result);
end;
procedure Out_Check(lmt:nativeInt); //simplest version var
i,j,k,s,pc: NativeInt;
Begin
pc:= GetMaxPrimeIdx(lmt);
count := 0;
For i := 0 to pc do
For j := i+1 to pc do
For k := j+1 to pc do
Begin
s := primes[i]+primes[j]+Primes[k];
//if takes the longest time
if ChkPrimes[s]<> 0 then
begin
inc(count);
writeln(count:3,': ',primes[i],'+',primes[j],'+',primes[k],' = ',s);
end;
end;
writeln;
end;
procedure Count_Check(pc:nativeInt); // the power of many registers ( 64-Bit ) var
cnt : Uint64; pPrimes : pUint32; pChkPrimes : ^tChkprimes; pi,pij,i,j,k: NativeInt;
Begin
cnt := 0;
pPrimes := @primes[0];
pChkPrimes := @Chkprimes[0];
For i := 0 to pc do
Begin
pi := pPrimes[i];
For j := i+1 to pc do
begin
pij := pi+pPrimes[j];
For k := j+1 to pc do
inc(cnt,pChkPrimes^[pij+pPrimes[k]]);
end;
end;
count := cnt;
end;
procedure Check_Limit(lmt:NativeInt); Begin
If lmt>primes[primecount] then
lmt := MaxZahl;
write('Limit = ',lmt,' count: ');
Count_Check(GetMaxPrimeIdx(lmt));
writeln(count);
end;
BEGIN
InitPrimes; Out_Check(30); Check_Limit(100); Check_Limit(1000); Check_Limit(10000);
//Check_Limit(MAXZAHL); END.</lang>
- Output:
1: 3+5+11 = 19 2: 3+5+23 = 31 3: 3+5+29 = 37 4: 3+7+13 = 23 5: 3+7+19 = 29 6: 3+11+17 = 31 7: 3+11+23 = 37 8: 3+11+29 = 43 9: 3+17+23 = 43 10: 5+7+11 = 23 11: 5+7+17 = 29 12: 5+7+19 = 31 13: 5+7+29 = 41 14: 5+11+13 = 29 15: 5+13+19 = 37 16: 5+13+23 = 41 17: 5+13+29 = 47 18: 5+17+19 = 41 19: 5+19+23 = 47 20: 5+19+29 = 53 21: 7+11+13 = 31 22: 7+11+19 = 37 23: 7+11+23 = 41 24: 7+11+29 = 47 25: 7+13+17 = 37 26: 7+13+23 = 43 27: 7+17+19 = 43 28: 7+17+23 = 47 29: 7+17+29 = 53 30: 7+23+29 = 59 31: 11+13+17 = 41 32: 11+13+19 = 43 33: 11+13+23 = 47 34: 11+13+29 = 53 35: 11+17+19 = 47 36: 11+19+23 = 53 37: 11+19+29 = 59 38: 13+17+23 = 53 39: 13+17+29 = 59 40: 13+19+29 = 61 41: 17+19+23 = 59 42: 19+23+29 = 71 Limit = 100 count: 891 Limit = 1000 count: 241580 Limit = 10000 count: 74588542 //real 0m0,142s Limit = 100000 count: 28694800655 real 1m5,378s
Perl
<lang perl>use strict; use warnings; use List::Util 'sum'; use ntheory <primes is_prime>; use Algorithm::Combinatorics 'combinations';
for my $n (30, 1000) {
printf "Found %d strange unique prime triplets up to $n.\n",
scalar grep { is_prime(sum @$_) } combinations(primes($n), 3);
}</lang>
- Output:
Found 42 strange unique prime triplets up to 30. Found 241580 strange unique prime triplets up to 1000.
Phix
requires("0.8.4") function create_sieve(integer limit) sequence sieve = repeat(true,limit) sieve[1] = false for i=4 to limit by 2 do sieve[i] = false end for for p=3 to floor(sqrt(limit)) by 2 do integer p2 = p*p if sieve[p2] then for k=p2 to limit by p*2 do sieve[k] = false end for end if end for return sieve end function procedure strange_triplets(integer lim, bool bCountOnly=true) atom t0 = time(), t1 = t0+1 sequence primes = get_primes_le(lim), sieve = create_sieve(lim*3), res = {} atom count = 0 -- -- It is not worth involving 2, ie primes[1], -- since (2 + any other two primes) is even, -- also we may as well leave space for {j,k}, -- {k} in the two outer loops. -- Using a sieve on the inner test is over -- ten times faster than is_prime(), whereas -- using a separate table of primes for the -- two outer loops is about twice as fast as -- scanning the sieve skipping falsies. Also -- interestingly, using nm = n+m is twice as -- fast as nmp = n+m+p. -- for i=2 to length(primes)-2 do integer n = primes[i] for j=i+1 to length(primes)-1 do integer m = primes[j], nm = n+m for k=j+1 to length(primes) do integer p = primes[k], nmp = nm+p if sieve[nmp] then count += 1 if not bCountOnly then res = append(res,sprintf("%2d: %2d+%2d+%2d = %d", {count, n, m, p, nmp})) end if end if if time()>t1 then progress("Working... (%,d)\r",{count}) t1 = time()+1 end if end for end for end for progress("") string r = iff(bCountOnly?sprintf(" (%s)",{elapsed(time()-t0)}) :sprintf(":\n%s",{join(shorten(res,"",3),"\n")})) printf(1,"%,d strange triplets < %,d found%s\n\n",{count,lim,r}) end procedure strange_triplets(30,false) strange_triplets(1000) strange_triplets(10000)
- Output:
42 strange triplets < 30 found: 1: 3+ 5+11 = 19 2: 3+ 5+23 = 31 3: 3+ 5+29 = 37 ... 40: 13+19+29 = 61 41: 17+19+23 = 59 42: 19+23+29 = 71 241,580 strange triplets < 1,000 found (0.0s) 74,588,542 strange triplets < 10,000 found (11.4s)
Python
Using sympy.primerange.
<lang python>from sympy import primerange
def strange_triplets(mx: int = 30) -> None:
primes = list(primerange(0, mx))
primes3 = set(primerange(0, 3 * mx))
for i, n in enumerate(primes):
for j, m in enumerate(primes[i + 1:], i + 1):
for p in primes[j + 1:]:
if n + m + p in primes3:
yield n, m, p
for c, (n, m, p) in enumerate(strange_triplets(), 1):
print(f"{c:2}: {n:2}+{m:2}+{p:2} = {n + m + p}")
mx = 1_000 print(f"\nIf n, m, p < {mx:_} finds {sum(1 for _ in strange_triplets(mx)):_}")</lang>
- Output:
1: 3+ 5+11 = 19 2: 3+ 5+23 = 31 3: 3+ 5+29 = 37 4: 3+ 7+13 = 23 5: 3+ 7+19 = 29 6: 3+11+17 = 31 7: 3+11+23 = 37 8: 3+11+29 = 43 9: 3+17+23 = 43 10: 5+ 7+11 = 23 11: 5+ 7+17 = 29 12: 5+ 7+19 = 31 13: 5+ 7+29 = 41 14: 5+11+13 = 29 15: 5+13+19 = 37 16: 5+13+23 = 41 17: 5+13+29 = 47 18: 5+17+19 = 41 19: 5+19+23 = 47 20: 5+19+29 = 53 21: 7+11+13 = 31 22: 7+11+19 = 37 23: 7+11+23 = 41 24: 7+11+29 = 47 25: 7+13+17 = 37 26: 7+13+23 = 43 27: 7+17+19 = 43 28: 7+17+23 = 47 29: 7+17+29 = 53 30: 7+23+29 = 59 31: 11+13+17 = 41 32: 11+13+19 = 43 33: 11+13+23 = 47 34: 11+13+29 = 53 35: 11+17+19 = 47 36: 11+19+23 = 53 37: 11+19+29 = 59 38: 13+17+23 = 53 39: 13+17+29 = 59 40: 13+19+29 = 61 41: 17+19+23 = 59 42: 19+23+29 = 71 If n, m, p < 1_000 finds 241_580
Raku
(formerly Perl 6) <lang perl6># 20210312 Raku programming solution
for 30, 1000 -> \k {
given (2..k).grep(*.is-prime).combinations(3).grep(*.sum.is-prime) {
say "Found ", +$_, " strange unique prime triplets up to ", k
}
}</lang>
- Output:
Found 42 strange unique prime triplets up to 30 Found 241580 strange unique prime triplets up to 1000
REXX
<lang rexx>/*REXX program finds/lists triplet strange primes (<HI) where the triplets' sum is prime*/ parse arg hi . /*obtain optional argument from the CL.*/ if hi== | hi=="," then hi= 30 /*Not specified? Then use the default.*/ tell= hi>0; hi= abs(hi); hi= hi - 1 /*use absolute value of HI for limit. */ if tell>0 then say 'list of unique triplet strange primes whose sum is a prime.:' call genP /*build array of semaphores for primes.*/ finds= 0 /*# of triplet strange primes (so far).*/ say
do m=2+1 by 2 to hi; if \!.m then iterate /*just use the odd primes. */
do n=m+2 by 2 to hi; if \!.n then iterate /* " " " " " */
mn= m + n /*partial sum (deep loops).*/
do p=n+2 by 2 to hi; if \!.p then iterate /*just use the odd primes. */
sum= mn + p /*compute sum of 3 primes. */
if \!.sum then iterate /*Is the sum prime? No, then skip it.*/
finds= finds + 1 /*bump # of triplet "strange" primes.*/
if tell then say right(m, w+9) right(n, w) right(p, w) ' sum to:' right(sum, w+2)
end /*p*/
end /*n*/
end /*m*/
say say 'Found ' commas(finds) " unique triplet strange primes < " commas(hi+1) ,
" which sum to a prime."
exit 0 /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ commas: parse arg ?; do jc=length(?)-3 to 1 by -3; ?=insert(',', ?, jc); end; return ? /*──────────────────────────────────────────────────────────────────────────────────────*/ genP: !.= 0; w= length(hi) /*semaphores for primes; width of #'s.*/
@.1=2; @.2=3; @.3=5; @.4=7; @.5=11 /*define some low primes. */
!.2=1; !.3=1; !.5=1; !.7=1; !.11=1 /* " " " " semaphores. */
#=5; s.#= @.# **2 /*number of primes so far; prime². */
/* [↓] generate more primes ≤ high.*/
do j=@.#+2 by 2 for hi*3%2 /*find odd primes from here on. */
parse var j -1 _; if _==5 then iterate /*J divisible by 5? (right dig)*/
if j// 3==0 then iterate /*" " " 3? */
if j// 7==0 then iterate /*" " " 7? */
/* [↑] the above five lines saves time*/
do k=5 while s.k<=j /* [↓] divide by the known odd primes.*/
if j // @.k == 0 then iterate j /*Is J ÷ X? Then not prime. ___ */
end /*k*/ /* [↑] only process numbers ≤ √ J */
#= #+1; @.#= j; s.#= j*j; !.j= 1 /*bump # of Ps; assign next P; P²; P# */
end /*j*/; return</lang>
- output when using the default input:
list of unique triplet strange primes that sum to a prime:
prime generation took 0.02 seconds.
3 5 11 sum to: 19
3 5 23 sum to: 31
3 5 29 sum to: 37
3 7 13 sum to: 23
3 7 19 sum to: 29
3 11 17 sum to: 31
3 11 23 sum to: 37
3 11 29 sum to: 43
3 17 23 sum to: 43
5 7 11 sum to: 23
5 7 17 sum to: 29
5 7 19 sum to: 31
5 7 29 sum to: 41
5 11 13 sum to: 29
5 13 19 sum to: 37
5 13 23 sum to: 41
5 13 29 sum to: 47
5 17 19 sum to: 41
5 19 23 sum to: 47
5 19 29 sum to: 53
7 11 13 sum to: 31
7 11 19 sum to: 37
7 11 23 sum to: 41
7 11 29 sum to: 47
7 13 17 sum to: 37
7 13 23 sum to: 43
7 17 19 sum to: 43
7 17 23 sum to: 47
7 17 29 sum to: 53
7 23 29 sum to: 59
11 13 17 sum to: 41
11 13 19 sum to: 43
11 13 23 sum to: 47
11 13 29 sum to: 53
11 17 19 sum to: 47
11 19 23 sum to: 53
11 19 29 sum to: 59
13 17 23 sum to: 53
13 17 29 sum to: 59
13 19 29 sum to: 61
17 19 23 sum to: 59
19 23 29 sum to: 71
Found 42 unique triplet strange primes < 30 which sum to a prime.
- output when using the input of: -1000
Found 241,580 unique triplet strange primes < 1,000 which sum to a prime.
Ring
<lang ring> load "stdlib.ring"
num = 0 limit = 30
see "working..." + nl see "the strange primes are:" + nl
for n = 1 to limit
for m = n+1 to limit
for p = m+1 to limit
sum = n+m+p
if isprime(sum) and isprime(n) and isprime(m) and isprime(p)
num = num + 1
see "" + num + ": " + n + "+" + m + "+" + p + " = " + sum + nl
ok
next
next
next
see "done..." + nl </lang>
- Output:
working... the strange primes are: 1: 3+5+11 = 19 2: 3+5+23 = 31 3: 3+5+29 = 37 4: 3+7+13 = 23 5: 3+7+19 = 29 6: 3+11+17 = 31 7: 3+11+23 = 37 8: 3+11+29 = 43 9: 3+17+23 = 43 10: 5+7+11 = 23 11: 5+7+17 = 29 12: 5+7+19 = 31 13: 5+7+29 = 41 14: 5+11+13 = 29 15: 5+13+19 = 37 16: 5+13+23 = 41 17: 5+13+29 = 47 18: 5+17+19 = 41 19: 5+19+23 = 47 20: 5+19+29 = 53 21: 7+11+13 = 31 22: 7+11+19 = 37 23: 7+11+23 = 41 24: 7+11+29 = 47 25: 7+13+17 = 37 26: 7+13+23 = 43 27: 7+17+19 = 43 28: 7+17+23 = 47 29: 7+17+29 = 53 30: 7+23+29 = 59 31: 11+13+17 = 41 32: 11+13+19 = 43 33: 11+13+23 = 47 34: 11+13+29 = 53 35: 11+17+19 = 47 36: 11+19+23 = 53 37: 11+19+29 = 59 38: 13+17+23 = 53 39: 13+17+29 = 59 40: 13+19+29 = 61 41: 17+19+23 = 59 42: 19+23+29 = 71 done...
Rust
<lang rust>fn prime_sieve(limit: usize) -> Vec<bool> {
let mut sieve = vec![true; limit];
if limit > 0 {
sieve[0] = false;
}
if limit > 1 {
sieve[1] = false;
}
for i in (4..limit).step_by(2) {
sieve[i] = false;
}
let mut p = 3;
loop {
let mut q = p * p;
if q >= limit {
break;
}
if sieve[p] {
let inc = 2 * p;
while q < limit {
sieve[q] = false;
q += inc;
}
}
p += 2;
}
sieve
}
fn strange_unique_prime_triplets(limit: usize, verbose: bool) {
if limit < 6 {
return;
}
let mut primes = Vec::new();
let sieve = prime_sieve(limit * 3);
for p in (3..limit).step_by(2) {
if sieve[p] {
primes.push(p);
}
}
if verbose {
println!("Strange unique prime triplets < {}:", limit);
}
let mut count = 0;
let n = primes.len();
for i in 0..n - 2 {
for j in i + 1..n - 1 {
for k in j + 1..n {
let sum = primes[i] + primes[j] + primes[k];
if sieve[sum] {
count += 1;
if verbose {
println!(
"{:2} + {:2} + {:2} = {:2}",
primes[i], primes[j], primes[k], sum
);
}
}
}
}
}
println!(
"Count of strange unique prime triplets < {} is {}.",
limit, count
);
}
fn main() {
strange_unique_prime_triplets(30, true); strange_unique_prime_triplets(1000, false);
}</lang>
- Output:
Strange unique prime triplets < 30: 3 + 5 + 11 = 19 3 + 5 + 23 = 31 3 + 5 + 29 = 37 3 + 7 + 13 = 23 3 + 7 + 19 = 29 3 + 11 + 17 = 31 3 + 11 + 23 = 37 3 + 11 + 29 = 43 3 + 17 + 23 = 43 5 + 7 + 11 = 23 5 + 7 + 17 = 29 5 + 7 + 19 = 31 5 + 7 + 29 = 41 5 + 11 + 13 = 29 5 + 13 + 19 = 37 5 + 13 + 23 = 41 5 + 13 + 29 = 47 5 + 17 + 19 = 41 5 + 19 + 23 = 47 5 + 19 + 29 = 53 7 + 11 + 13 = 31 7 + 11 + 19 = 37 7 + 11 + 23 = 41 7 + 11 + 29 = 47 7 + 13 + 17 = 37 7 + 13 + 23 = 43 7 + 17 + 19 = 43 7 + 17 + 23 = 47 7 + 17 + 29 = 53 7 + 23 + 29 = 59 11 + 13 + 17 = 41 11 + 13 + 19 = 43 11 + 13 + 23 = 47 11 + 13 + 29 = 53 11 + 17 + 19 = 47 11 + 19 + 23 = 53 11 + 19 + 29 = 59 13 + 17 + 23 = 53 13 + 17 + 29 = 59 13 + 19 + 29 = 61 17 + 19 + 23 = 59 19 + 23 + 29 = 71 Count of strange unique prime triplets < 30 is 42. Count of strange unique prime triplets < 1000 is 241580.
Swift
<lang swift>import Foundation
func primeSieve(limit: Int) -> [Bool] {
guard limit > 0 else {
return []
}
var sieve = Array(repeating: true, count: limit)
sieve[0] = false
if limit > 1 {
sieve[1] = false
}
if limit > 4 {
for i in stride(from: 4, to: limit, by: 2) {
sieve[i] = false
}
}
var p = 3
while true {
var q = p * p
if q >= limit {
break
}
if sieve[p] {
let inc = 2 * p
while q < limit {
sieve[q] = false
q += inc
}
}
p += 2
}
return sieve
}
func strangeUniquePrimeTriplets(limit: Int, verbose: Bool) {
guard limit > 5 else {
return;
}
let sieve = primeSieve(limit: 3 * limit)
var primes: [Int] = []
for p in stride(from: 3, to: limit, by: 2) {
if sieve[p] {
primes.append(p)
}
}
let n = primes.count
var count = 0
if verbose {
print("Strange unique prime triplets < \(limit):")
}
for i in (0..<n - 2) {
for j in (i + 1..<n - 1) {
for k in (j + 1..<n) {
let sum = primes[i] + primes[j] + primes[k]
if sieve[sum] {
count += 1
if verbose {
print(String(format: "%2d + %2d + %2d = %2d",
primes[i], primes[j], primes[k], sum))
}
}
}
}
}
print("\nCount of strange unique prime triplets < \(limit) is \(count).")
}
strangeUniquePrimeTriplets(limit: 30, verbose: true) strangeUniquePrimeTriplets(limit: 1000, verbose: false)</lang>
- Output:
Strange unique prime triplets < 30: 3 + 5 + 11 = 19 3 + 5 + 23 = 31 3 + 5 + 29 = 37 3 + 7 + 13 = 23 3 + 7 + 19 = 29 3 + 11 + 17 = 31 3 + 11 + 23 = 37 3 + 11 + 29 = 43 3 + 17 + 23 = 43 5 + 7 + 11 = 23 5 + 7 + 17 = 29 5 + 7 + 19 = 31 5 + 7 + 29 = 41 5 + 11 + 13 = 29 5 + 13 + 19 = 37 5 + 13 + 23 = 41 5 + 13 + 29 = 47 5 + 17 + 19 = 41 5 + 19 + 23 = 47 5 + 19 + 29 = 53 7 + 11 + 13 = 31 7 + 11 + 19 = 37 7 + 11 + 23 = 41 7 + 11 + 29 = 47 7 + 13 + 17 = 37 7 + 13 + 23 = 43 7 + 17 + 19 = 43 7 + 17 + 23 = 47 7 + 17 + 29 = 53 7 + 23 + 29 = 59 11 + 13 + 17 = 41 11 + 13 + 19 = 43 11 + 13 + 23 = 47 11 + 13 + 29 = 53 11 + 17 + 19 = 47 11 + 19 + 23 = 53 11 + 19 + 29 = 59 13 + 17 + 23 = 53 13 + 17 + 29 = 59 13 + 19 + 29 = 61 17 + 19 + 23 = 59 19 + 23 + 29 = 71 Count of strange unique prime triplets < 30 is 42. Count of strange unique prime triplets < 1000 is 241580.
Wren
Basic
<lang ecmascript>import "/math" for Int import "/trait" for Stepped import "/fmt" for Fmt
var strangePrimes = Fn.new { |n, countOnly|
var c = 0
var s
for (i in Stepped.new(3..n-4, 2)) {
if (Int.isPrime(i)) {
for (j in Stepped.new(i+2..n-2, 2)) {
if (Int.isPrime(j)) {
for (k in Stepped.new(j+2..n, 2)) {
if (Int.isPrime(k) && Int.isPrime(s = i + j + k)) {
c = c + 1
if (!countOnly) Fmt.print("$2d: $2d + $2d + $2d = $2d", c, i, j, k, s)
}
}
}
}
}
}
return c
}
System.print("Unique prime triples under 30 which sum to a prime:") strangePrimes.call(29, false) var c = strangePrimes.call(999, true) Fmt.print("\nThere are $,d unique prime triples under 1,000 which sum to a prime.", c)</lang>
- Output:
Unique prime triples under 30 which sum to a prime: 1: 3 + 5 + 11 = 19 2: 3 + 5 + 23 = 31 3: 3 + 5 + 29 = 37 4: 3 + 7 + 13 = 23 5: 3 + 7 + 19 = 29 6: 3 + 11 + 17 = 31 7: 3 + 11 + 23 = 37 8: 3 + 11 + 29 = 43 9: 3 + 17 + 23 = 43 10: 5 + 7 + 11 = 23 11: 5 + 7 + 17 = 29 12: 5 + 7 + 19 = 31 13: 5 + 7 + 29 = 41 14: 5 + 11 + 13 = 29 15: 5 + 13 + 19 = 37 16: 5 + 13 + 23 = 41 17: 5 + 13 + 29 = 47 18: 5 + 17 + 19 = 41 19: 5 + 19 + 23 = 47 20: 5 + 19 + 29 = 53 21: 7 + 11 + 13 = 31 22: 7 + 11 + 19 = 37 23: 7 + 11 + 23 = 41 24: 7 + 11 + 29 = 47 25: 7 + 13 + 17 = 37 26: 7 + 13 + 23 = 43 27: 7 + 17 + 19 = 43 28: 7 + 17 + 23 = 47 29: 7 + 17 + 29 = 53 30: 7 + 23 + 29 = 59 31: 11 + 13 + 17 = 41 32: 11 + 13 + 19 = 43 33: 11 + 13 + 23 = 47 34: 11 + 13 + 29 = 53 35: 11 + 17 + 19 = 47 36: 11 + 19 + 23 = 53 37: 11 + 19 + 29 = 59 38: 13 + 17 + 23 = 53 39: 13 + 17 + 29 = 59 40: 13 + 19 + 29 = 61 41: 17 + 19 + 23 = 59 42: 19 + 23 + 29 = 71 There are 241,580 unique prime triples under 1,000 which sum to a prime.
Faster
The following version uses a prime sieve and is about 17 times faster than the 'basic' version. <lang ecmascript>import "/math" for Int import "/fmt" for Fmt
var max = 1000 var sieved = Int.primeSieve(3*max, false) // includes composites var p = Int.primeSieve(max, true) // primes only
var strangePrimes = Fn.new { |n, countOnly|
var c = 0
var m = 0
while (m < p.count && p[m] <= n) m = m + 1
var r
var s
for (i in 1...m-2) {
for (j in i+1...m-1) {
r = p[i] + p[j]
for (k in j+1...m) {
if (!sieved[s = r + p[k]]) {
c = c + 1
if (!countOnly) Fmt.print("$2d: $2d + $2d + $2d = $2d", c, p[i], p[j], p[k], s)
}
}
}
}
return c
}
System.print("Unique prime triples under 30 which sum to a prime:") strangePrimes.call(29, false) var c = strangePrimes.call(999, true) Fmt.print("\nThere are $,d unique prime triples under 1,000 which sum to a prime.", c)</lang>
- Output:
Same as 'basic' version.