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zeller ← { 7|+/(((1↑⍴⍵),6)⍴1 1 1 1 ¯1 1)× ⌊(((⍴⍵)⍴1 13 1)×⍵+(⍴⍵)⍴0 1 0)[;0 1 2 2 2 2]÷((1↑⍴⍵),6)⍴1 5 1 4 100 400}
result ← ( 1 = Zeller 25,[1]12,[0.5]y) / y
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