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Perfect numbers: Difference between revisions

(Added Oz.)
Line 286:
for(BigInteger i= BigInteger.ONE;
i.compareTo(n) < 0;i=i.add(BigInteger.ONE)){
if(n.mod(i).compareToequals(BigInteger.ZERO) == 0){
sum= sum.add(i);
}
}
return sum.compareToequals(n) == 0;
}</lang>
 
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