Word wheel: Difference between revisions
m
Text overflowing line length corrected.
m (Minor improvement to coding.) |
m (Text overflowing line length corrected.) |
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Line 1,635:
String middleLetter = allLetters.substring(4, 5);
Predicate<String> firstFilter = word -> word.contains(middleLetter) &&
Predicate<String> secondFilter = word -> word.chars().allMatch( ch -> allLetters.indexOf(ch) >= 0 );
Predicate<String> correctWords = firstFilter.and(secondFilter);
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