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Odd and square numbers: Difference between revisions

Added 11l
(Fix Python solution)
(Added 11l)
Line 4:
<br>
Find odd and square numbers (>99) under '''1.000'''
 
=={{header|11l}}==
{{trans|Python}}
 
<lang 11l>V limit = 1000
 
L(i) (1 .< Int(ceil(sqrt(limit)))).step(2)
V num = i * i
I num < limit & num > 99
print(num, end' ‘ ’)</lang>
 
{{out}}
<pre>
121 169 225 289 361 441 529 625 729 841 961
</pre>
 
=={{header|ALGOL 68}}==
1,481

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