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Factors of an integer: Difference between revisions
Faster implementation in scala
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(Faster implementation in scala) |
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=={{header|Scala}}==
<lang Scala>
Brute force approach:
def factors(num: Int) = {
(1 to num).filter { divisor =>
num % divisor == 0
}
}</lang>▼
Since factors can't be higher than sqrt(num), the code above can be edited as follows
def factors(num: Int) = {
(1 to sqrt(num)).filter { divisor =>
num % divisor == 0
}
=={{header|Scheme}}==
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