Sort an integer array
Sort an array (or list) of integers in ascending numerical order. Use a sorting facility provided by the language/library if possible.
You are encouraged to solve this task according to the task description, using any language you may know.
4D
English
<lang 4d>ARRAY INTEGER($nums;0) APPEND TO ARRAY($nums;2) APPEND TO ARRAY($nums;4) APPEND TO ARRAY($nums;3) APPEND TO ARRAY($nums;1) APPEND TO ARRAY($nums;2) SORT ARRAY($nums) ` sort in ascending order SORT ARRAY($nums;<) ` sort in descending order</lang>
Français
<lang 4d>TABLEAU ENTIER($nombres;0) AJOUTER A TABLEAU($nombres;2) AJOUTER A TABLEAU($nombres;4) AJOUTER A TABLEAU($nombres;3) AJOUTER A TABLEAU($nombres;1) AJOUTER A TABLEAU($nombres;2) TRIER TABLEAU($nombres) ` pour effectuer un tri par ordre croissant TRIER TABLEAU($nombres;<) ` pour effectuer un tri par ordre décroissant</lang>
ActionScript
<lang ActionScript>//Comparison function must returns Numbers even though it deals with integers. function compare(x:int, y:int):Number { return Number(x-y); } var nums:Vector.<int> = Vector.<int>([5,12,3,612,31,523,1,234,2]); nums.sort(compare);</lang>
Ada
<lang ada>with Gnat.Heap_Sort_G;
procedure Integer_Sort is
-- Heap sort package requires data to be in index values starting at -- 1 while index value 0 is used as temporary storage type Int_Array is array(Natural range <>) of Integer; Values : Int_Array := (0,1,8,2,7,3,6,4,5); -- define move and less than subprograms for use by the heap sort package procedure Move_Int(From : Natural; To : Natural) is begin Values(To) := Values(From); end Move_Int; function Lt_Int(Left, Right : Natural) return Boolean is begin return Values(Left) < Values (Right); end Lt_Int; -- Instantiate the generic heap sort package package Heap_Sort is new Gnat.Heap_Sort_G(Move_Int, Lt_Int);
begin
Heap_Sort.Sort(8);
end Integer_Sort;
requires an Ada05 compiler, e.g GNAT GPL 2007 with Ada.Containers.Generic_Array_Sort;
procedure Integer_Sort is
-- type Int_Array is array(Natural range <>) of Integer; Values : Int_Array := (0,1,8,2,7,3,6,4,5); -- Instantiate the generic sort package from the standard Ada library procedure Sort is new Ada.Containers.Generic_Array_Sort (Index_Type => Natural; Element_Type => Integer; Array_Type => Int_Array);
begin
Sort(Values);
end Integer_Sort;</lang>
ALGOL 68
<lang algol68>CO PR READ "shell_sort.a68" PR CO MODE TYPE = INT;
PROC in place shell sort = (REF[]TYPE seq)REF[]TYPE:(
INT inc := ( UPB seq + LWB seq + 1 ) OVER 2; WHILE inc NE 0 DO FOR index FROM LWB seq TO UPB seq DO INT i := index; TYPE el = seq[i]; WHILE ( i - LWB seq >= inc | seq[i - inc] > el | FALSE ) DO seq[i] := seq[i - inc]; i -:= inc OD; seq[i] := el OD; inc := IF inc = 2 THEN 1 ELSE ENTIER(inc * 5 / 11) FI OD; seq
);
PROC shell sort = ([]TYPE seq)[]TYPE:
in place shell sort(LOC[LWB seq: UPB seq]TYPE:=seq);
print((shell sort((2, 4, 3, 1, 2)), new line))</lang> Output:
+1 +2 +2 +3 +4
APL
<lang apl> X←63 92 51 92 39 15 43 89 36 69
X[⍋X]
15 36 39 43 51 63 69 89 92 92</lang>
AutoHotkey
<lang AutoHotkey>numbers = 5 4 1 2 3 sort, numbers, N D%A_Space% Msgbox % numbers</lang>
C
<lang c>#include <stdlib.h>
int intcmp(const void *a, const void *b) {
return *(int *)a - *(int *)b;
}
int main() {
int nums[5] = {2,4,3,1,2}; qsort(nums, 5, sizeof(int), intcmp);
}</lang>
C++
Simple Array
<lang cpp>#include <algorithm>
int main() {
int nums[] = {2,4,3,1,2}; std::sort(nums, nums+5);
}</lang>
std::vector
<lang cpp>#include <algorithm>
- include <vector>
int main() {
std::vector<int> nums; nums.push_back(2); nums.push_back(4); nums.push_back(3); nums.push_back(1); nums.push_back(2); std::sort(nums.begin(), nums.end());
}</lang>
std::list
<lang cpp>#include <list>
int main() {
std::list<int> nums; nums.push_back(2); nums.push_back(4); nums.push_back(3); nums.push_back(1); nums.push_back(2); nums.sort();
}</lang>
C#
<lang csharp>using System; using System.Collections.Generic;
public class Program {
static void Main() { int[] unsorted = { 6, 2, 7, 8, 3, 1, 10, 5, 4, 9 }; Array.Sort(unsorted); }
}</lang>
Clean
We use list and array comprehensions to convert an array to and from a list in order to use the built-in sort on lists. <lang clean>import StdEnv
sortArray :: (a e) -> a e | Array a e & Ord e sortArray array = {y \\ y <- sort [x \\ x <-: array]}
Start :: {#Int} Start = sortArray {2, 4, 3, 1, 2}</lang>
Clojure
<lang clojure>(sort [5 4 3 2 1]) ; sort can also take a comparator function (1 2 3 4 5)</lang>
Common Lisp
In Common Lisp, the sort function takes a predicate that is used as the comparator. This parameter can be any two-argument function. To sort a sequence (list or array) of integers, call sort with the < operator as the predicate: <lang lisp>CL-USER> (sort #(9 -2 1 2 8 0 1 2) #'<)
- (-2 0 1 1 2 2 8 9)</lang>
D
<lang d>auto nums = [2,4,3,1,2]; auto snums = nums.dup.sort; // Sort nums.sort; // Sort in-place</lang>
E
<lang e>[2,4,3,1,2].sort()</lang>
Erlang
<lang erlang>List = [2, 4, 3, 1, 2]. SortedList = lists:sort(List).</lang>
Factor
<lang factor>{ 1 4 9 2 3 0 5 } natural-sort .</lang>
Forth
<lang forth>create test-data 2 , 4 , 3 , 1 , 2 , test-data 5 cell-sort</lang>
Fortran
<lang fortran>CALL ISORT@(b, a, n) ! n = number of elements ! a = array to be sorted ! b = array of indices of a. b(1) 'points' to the minimum value etc.</lang>
Go
<lang go>package main import "fmt" import "sort"
func main() {
nums := []int {2, 4, 3, 1, 2} sort.SortInts(nums) fmt.Println(nums)
}</lang>
Groovy
<lang groovy>println ([2,4,0,3,1,2,-12].sort())</lang>
Output:
[-12, 0, 1, 2, 2, 3, 4]
Haskell
<lang haskell>nums = [2,4,3,1,2] :: [Int] sorted = List.sort nums</lang>
HicEst
<lang hicest>DIMENSION array(100)
array = INT( RAN(100) ) SORT(Vector=array, Sorted=array) </lang>
IDL
<lang idl>result = array[sort(array)]</lang>
Icon and Unicon
Icon and Unicon lists allow mixed type and the built-in function 'sort' will deal with mixed type arrays by sorting by type first then value. Integers sort before, reals, strings, lists, tables, etc. As a result a list of mixed numeric valuess (i.e. integers and reals) will not sort by numeric value, rather the reals will appear after the integers. Sort returns a sorted copy of it's argument. It will also perform some type conversion, such converting an unordered set into an ordered list.
Icon
In the example below, L will remain an unsorted list and S will be sorted. <lang Icon>S := sort(L:= [63, 92, 51, 92, 39, 15, 43, 89, 36, 69]) # will sort a list</lang>
Unicon
The Icon solution works in Unicon.
J
<lang j>/:~</lang> The verb /:~ sorts anything. For example:
<lang j> ] a=: 10 ?@$ 100 NB. random vector 63 92 51 92 39 15 43 89 36 69
/:~ a
15 36 39 43 51 63 69 89 92 92</lang>
Arrays of any rank are treated as lists of component arrays. Thus /:~ sorts not only atoms within a list, but whole lists within a table, tables within a three-axis array, and so on. The level of structure at which sorting occurs may also be specified, so that /:~"1 sorts the atoms within the finest-grained list within the array, regardless of the overall rank of the array.
This code also applies to any data type.
Java
Array
<lang java>import java.util.Arrays;
public class example {
public static void main(String[] args) { int[] nums = {2,4,3,1,2}; Arrays.sort(nums); }
}</lang>
List
<lang java5>import java.util.Arrays; import java.util.Collections; import java.util.List;
public class example {
public static void main(String[] args) { List<Integer> nums = Arrays.asList(2,4,3,1,2); Collections.sort(nums); }
}</lang>
JavaScript
JavaScript sorts lexically by default, so "10000" comes before "2". To sort numerically, a custom comparator is used.
<lang javascript>function numberSorter(a, b) {
return a - b;
} var numbers = [20, 7, 65, 10, 3, 0, 8, -60]; numbers.sort(numberSorter); alert( numbers );</lang>
Io
<lang lua> mums := list(2,4,3,1,2) sorted := nums sort # returns a new sorted array. 'nums' is unchanged nums sortInPlace # sort 'nums' "in-place"</lang>
Lua
<lang lua> t = {4, 5, 2} table.sort(t) print(unpack(t))</lang>
Mathematica
<lang mathematica>numbers = Sort[{2,4,3,1,2}]</lang>
MATLAB
<lang Matlab>a = [4,3,7,-2,9,1]; b = sort(a) % b contains elements of a in ascending order [b,idx] = sort(a) % b contains a(idx)</lang>
MAXScript
<lang maxscript>arr = #(5, 4, 3, 2, 1) arr = sort arr</lang>
Modula-3
Modula-3 provides a generic ArraySort module, as well as an instance of that module for integers called IntArraySort. <lang modula3>MODULE ArraySort EXPORTS Main;
IMPORT IntArraySort;
VAR arr := ARRAY [1..10] OF INTEGER{3, 6, 1, 2, 10, 7, 9, 4, 8, 5};
BEGIN
IntArraySort.Sort(arr);
END ArraySort.</lang>
Nial
<lang nial>sort >= 9 6 8 7 1 10 = 10 9 8 7 6 1</lang>
Niue
Library <lang Niue>2 6 1 0 3 8 sort .s 0 1 2 3 6 8 </lang>
Objective-C
<lang objc>- (void)example {
NSArray *nums, *sorted; nums = [NSArray arrayWithObjects: [NSNumber numberWithInt:2], [NSNumber numberWithInt:4], [NSNumber numberWithInt:3], [NSNumber numberWithInt:1], [NSNumber numberWithInt:2], nil]; sorted = [nums sortedArrayUsingSelector:@selector(compare:)];
}</lang>
Objeck
<lang objeck> bundle Default {
class Sort { function : Main(args : System.String[]), Nil { nums := Structure.IntVector->New([2,4,3,1,2]); nums->Sort(); } }
} </lang>
OCaml
Array
<lang ocaml>let nums = [|2; 4; 3; 1; 2|] Array.sort compare nums</lang>
List
<lang ocaml>let nums = [2; 4; 3; 1; 2] let sorted = List.sort compare nums</lang>
Octave
The variable v can be a vector or a matrix (columns will be sorted).
<lang octave>sortedv = sort(v);</lang>
Oz
<lang oz>declare
Nums = [2 4 3 1 2] Sorted = {List.sort Nums Value.'<'}
in
{Show Sorted}</lang>
Perl
<lang perl>@nums = (2,4,3,1,2); @sorted = sort {$a <=> $b} @nums;</lang>
Perl 6
If @a
contains only numbers:
<lang perl6>my @sorted = sort @a;</lang>
If some elements of @a
are strings or are otherwise non-numeric but you want to treat them as numbers:
<lang perl6>my @sorted = sort +*, @a;</lang>
For an in-place sort:
<lang perl6>@a .= sort;</lang>
PHP
<lang php><?php $nums = array(2,4,3,1,2); sort($nums); ?></lang>
PicoLisp
The sort function in PicoLisp returns already by default an ascending list (of any type, not only integers): <lang PicoLisp>(sort (2 4 3 1 2)) -> (1 2 2 3 4)</lang>
PL/I
<lang pli>DCL (T(10)) FIXED BIN(31); /* scratch space of length N/2 */
MERGE: PROCEDURE (A,LA,B,LB,C);
DECLARE (A(*),B(*),C(*)) FIXED BIN(31); DECLARE (LA,LB) FIXED BIN(31) NONASGN; DECLARE (I,J,K) FIXED BIN(31); I=1; J=1; K=1; DO WHILE ((I <= LA) & (J <= LB)); IF(A(I) <= B(J)) THEN DO; C(K)=A(I); K=K+1; I=I+1; END; ELSE DO; C(K)=B(J); K=K+1; J=J+1; END; END; DO WHILE (I <= LA); C(K)=A(I); I=I+1; K=K+1; END; RETURN;
END MERGE;
MERGESORT: PROCEDURE (A,N) RECURSIVE ;
DECLARE (A(*)) FIXED BINARY(31); DECLARE N FIXED BINARY(31) NONASGN; DECLARE Temp FIXED BINARY; DECLARE (M,I) FIXED BINARY; DECLARE AMP1(N) FIXED BINARY(31) BASED(P); DECLARE P POINTER; IF (N=1) THEN RETURN; M = trunc((N+1)/2); IF (M>1) THEN CALL MERGESORT(A,M); P=ADDR(A(M+1)); IF (N-M > 1) THEN CALL MERGESORT(AMP1,N-M); IF A(M) <= AMP1(1) THEN RETURN; DO I=1 to M; T(I)=A(I); END; CALL MERGE(T,M,AMP1,N-M,A); RETURN;
END MERGESORT;</lang>
Pop11
Pop11 library function sorts lists. So we first convert array to list, then sort and finally convert back:
<lang pop11>lvars ar = {2 4 3 1 2};
- Convert array to list.
- destvector leaves its results and on the pop11 stack + an integer saying how many there were
destvector(ar);
- conslist uses the items left on the stack plus the integer, to make a list of those items.
lvars ls = conslist();
- Sort it
sort(ls) -> ls;
- Convert list to array
destlist(ls); consvector() -> ar;</lang>
The above can be abbreviated to more economical, but possibly more opaque, syntax, using pop11 as a functional language:
<lang pop11>lvars ar = {2 4 3 1 2}; consvector(destlist(sort(conslist(destvector(ar))))) -> ar;
- print the sorted vector
ar =>
- {1 2 2 3 4}</lang>
(The list created by conslist will be garbage-collected.)
Alternatively, using the datalist function, even more economically:
<lang pop11>lvars ar = {2 4 3 1 2}; consvector(destlist(sort(datalist(ar)))) -> ar;</lang>
or in Forth-like pop11 postfix syntax:
<lang pop11>lvars ar = {2 4 3 1 2}; ar.datalist.sort.destlist.consvector -> ar;</lang>
PowerShell
<lang powershell>34,12,23,56,1,129,4,2,73 | Sort-Object</lang>
PureBasic
<lang PureBasic>Dim numbers(20) For i = 0 To 20
numbers(i) = Random(1000)
Next
SortArray(numbers(), #PB_Sort_Ascending)</lang>
Python
<lang python>nums = [2,4,3,1,2] nums.sort()</lang>
Note: The array nums is sorted in place.
Interpreter: Python 2.4 (and above)
You could also use the built-in sorted() function
<lang python>nums = sorted([2,4,3,1,2])</lang>
R
<lang r>nums <- c(2,4,3,1,2) sorted <- sort(nums)</lang>
Raven
Sort list in place:
<lang raven>[ 2 4 3 1 2 ] sort</lang>
Ruby
<lang ruby>nums = [2,4,3,1,2] sorted = nums.sort # returns a new sorted array. 'nums' is unchanged nums.sort! # sort 'nums' "in-place"</lang>
Seed7
<lang seed7>var array integer: nums is [] (2, 4, 3, 1, 2);
nums := sort(nums);</lang>
Slate
<lang slate> #(7 5 2 9 0 -1) sort</lang>
Smalltalk
<lang smalltalk> #(7 5 2 9 0 -1) asSortedCollection</lang>
Standard ML
Array
<lang sml>val nums = Array.fromList [2, 4, 3, 1, 2]; ArrayQSort.sort Int.compare nums;</lang>
List
<lang sml>val nums = [2, 4, 3, 1, 2]; val sorted = ListMergeSort.sort (op >) nums;</lang>
Tcl
<lang tcl>set result [lsort -integer $unsorted_list]</lang>
TI-83 BASIC
Store input into L1, run prgmSORTBTIN, and L2 will be L1, only sorted.
:L1→L2 :SortA(L2)
SortA is found via: [LIST] → ENTER. SortD is also available for a descending sort.
Toka
This can be done by using the bubble sort library:
<lang toka>needs bsort arrayname number_elements bsort</lang>
See the Toka entry on Bubble Sort for a full example.
UNIX Shell
<lang bash>nums=(2 4 3 1 2) sorted=($(for i in ${nums[*]}; do echo $i; done | sort -n))</lang> Another way: <lang bash>nums=(2 4 3 1 5) sorted=($(echo "${nums[@]}" | tr ' ' '\12' | sort -n))</lang>
Ursala
using the built in sort operator, -<, with the nleq library function for comparing natural numbers <lang Ursala>#import nat
- cast %nL
example = nleq-< <39,47,40,53,14,23,88,52,78,62,41,92,88,66,5,40></lang> output:
<5,14,23,39,40,40,41,47,52,53,62,66,78,88,88,92>