Repeat a string: Difference between revisions
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=={{header|C++}}== |
=={{header|C++}}== |
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<lang |
<lang cpp>#include <string> |
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#include <iostream> |
#include <iostream> |
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std::string repeat( std::string word, int times ) { |
std::string repeat( std::string word, int times ) { |
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std::string |
std::string result ; |
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for ( int a = 0 ; a < times |
for ( int a = 0 ; a < times ; a++ ) |
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result += word ; |
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return |
return result ; |
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} |
} |
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std::cout << repeat( "Ha" , 5 ) << std::endl ; |
std::cout << repeat( "Ha" , 5 ) << std::endl ; |
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return 0 ; |
return 0 ; |
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} |
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⚫ | |||
=={{header|Clojure}}== |
=={{header|Clojure}}== |
Revision as of 23:04, 13 November 2009
You are encouraged to solve this task according to the task description, using any language you may know.
Take a string and repeat it some number of times. Example: repeat("ha", 5) => "hahahahaha"
Ada
In Ada multiplication of an universal integer to string gives the desired result. Here is an example of use: <lang Ada> with Ada.Strings.Fixed; use Ada.Strings.Fixed; with Ada.Text_IO; use Ada.Text_IO;
procedure String_Multiplication is begin
Put_Line (5 * "ha");
end String_Multiplication; </lang> Sample output:
hahahahaha
C
<lang c>
- include <stdio.h>
- include <stdlib.h>
- include <string.h>
char * string_repeat( int n, const char * s ) {
size_t slen = strlen(s); char * dest = (char *)calloc(n*slen, sizeof(char));
int i; char * p; for ( i=0, p = dest; i < n; ++i, p += slen ) { memcpy(p, s, slen); } return dest;
}
int main() {
printf("%s\n", string_repeat(5, "ha"));
}
</lang>
C++
<lang cpp>#include <string>
- include <iostream>
std::string repeat( std::string word, int times ) {
std::string result ; for ( int a = 0 ; a < times ; a++ ) result += word ; return result ;
}
int main( ) {
std::cout << repeat( "Ha" , 5 ) << std::endl ; return 0 ;
}</lang>
Clojure
<lang clojure>(apply str (apply concat (repeat 5 "ha")))</lang>
E
<lang e>"ha" * 5</lang>
Forth
<lang forth>
- place-n { src len dest n -- }
0 dest c! n 0 ?do src len dest +place loop ;
create test 256 allot s" ha" test 5 place-n test count type \ hahahahaha </lang>
Fortran
<lang fortran>program test_repeat
write (*, '(a)') repeat ('ha', 5)
end program test_repeat</lang> Output:
hahahahaha
Haskell
<lang haskell>concat $ replicate 5 "ha"</lang>
J
<lang j>
5 ((* #) $ ]) 'ha'
hahahahaha </lang>
Java
There's no function or operator to do this in Java, so you have to do it yourself. <lang java5>public static String repeat(String str, int times){
StringBuilder ret = new StringBuilder(); for(int i = 0;i < times;i++) ret.append(str); return ret.toString();
}
public static void main(String[] args){
System.out.println(repeat("ha", 5));
}</lang>
JavaScript
This solution creates an array of n+1 null elements, then joins them using the target string as the delimiter <lang javascript>String.prototype.repeat = function(n) {
return new Array(1 + parseInt(n, 10)).join(this);
}
alert("ha".repeat(5)); // hahahahaha</lang>
Logo
<lang logo> to copies :n :thing [:acc "||]
if :n = 0 [output :acc] output (copies :n-1 :thing combine :acc :thing)
end </lang> or using cascade: <lang logo> show cascade 5 [combine "ha ?] "|| ; hahahahaha </lang>
OCaml
<lang ocaml>let string_repeat s n =
let len = String.length s in let res = String.create(n * len) in for i = 0 to pred n do String.blit s 0 res (i * len) len; done; (res)
- </lang>
testing in the toplevel: <lang ocaml># string_repeat "Hiuoa" 3 ;; - : string = "HiuoaHiuoaHiuoa"</lang>
Alternately: <lang ocaml>let string_repeat s n =
String.concat "" (Array.to_list (Array.make n s))
- </lang>
Or: <lang ocaml>let string_repeat s n =
Array.fold_left (^) "" (Array.make n s)
- </lang>
Perl
<lang perl>"ha" x 5</lang>
Perl 6
<lang perl6>"ha" x 5</lang>
(Note that the x
operator isn't quite the same as in Perl 5: it now only creates strings. To create lists, use xx
.)
PHP
<lang php>str_repeat("ha", 5)</lang>
PowerBASIC
<lang powerbasic>MSGBOX REPEAT$(5, "ha")</lang>
Pure
str_repeat is defined by pattern-matching: repeating any string 0 times results in the empty string; while repeating it more than 0 times results in the concatenation of the string and (n-1) further repeats.
<lang pure> > str_repeat 0 s = ""; > str_repeat n s = s + (str_repeat (n-1) s) if n>0; > str_repeat 5 "ha"; "hahahahaha" > </lang>
Python
<lang python>"ha" * 5 # ==> "hahahahaha"</lang>
Ruby
<lang ruby>"ha" * 5 # ==> "hahahahaha"</lang>
Tcl
<lang tcl>string repeat "ha" 5 ;# => hahahahaha</lang>