In this task, the job is to rename the file called "input.txt" into "output.txt" and a directory called "docs" into "mydocs". This should be done twice: once "here", i.e. in the current working directory and once in the filesystem root.

Task
Rename a file
You are encouraged to solve this task according to the task description, using any language you may know.

C

Works with: gcc version 4.1.2 20061115 (prerelease) (SUSE Linux)

<lang c>#include <stdio.h>

int main() {

 rename("input.txt", "output.txt");
 rename("docs", "mydocs");
 rename("/input.txt", "/output.txt");
 rename("/docs", "/mydocs");
 return 0;

}</lang>

ALGOL 68

Note: reidf does not appear to be included in ALGOL 68G. Also note that file names would be Operating System dependent.

main:(
  PROC rename = (STRING source name, dest name)INT:
  BEGIN
    FILE actual file;
    INT errno = open(actual file, source name, stand back channel);
    IF errno NE 0 THEN
      errno
    ELSE
      IF reidf possible(actual file) THEN
        reidf(actual file, dest name); # change the identification of the book #
        errno
      ELSE
        close(actual file);
        -1
      FI
    FI
  END;
  rename("input.txt", "output.txt");
  rename("/input.txt", "/output.txt");
  rename("docs", "mydocs");
  rename("/docs", "/mydocs")
)

DOS Batch File

 ren input.txt output.txt
 ren \input.txt output.txt
 ren docs mydocs
 ren \docs mydocs

Forth

 s" input.txt"  s" output.txt" rename-file throw
s" /input.txt" s" /output.txt" rename-file throw

Groovy

Using File

 ['input.txt':'output.txt', 'docs':'mydocs'].each { src, dst ->
   ['.', ''].each { dir ->
     new File("$dir/$src").renameTo(new File("$dir/$dst"))
   }
 }

Using Ant

 ['input.txt':'output.txt', 'docs':'mydocs'].each { src, dst ->
   ['.', ''].each { dir ->
     new AntBuilder().move(file:"$dir/$src", toFile:"$dir/$dst")
   }
 }

Haskell

import System.IO
import System.Directory

main = do
  renameFile "input.txt" "output.txt"
  renameDirectory "docs" "mydocs"
  renameFile "/input.txt" "/output.txt"
  renameDirectory "/docs" "/mydocs"

Java

import java.util.File;
public class FileRenameTest {
   public static boolean renameFile(String oldname, String newname) {
       // File (or directory) with old name
       File file = new File(oldname);
   
       // File (or directory) with new name
       File file2 = new File(newname);
   
       // Rename file (or directory)
       boolean success = file.renameTo(file2);
       return sucess;
   }
   public static void test(String type, String oldname, String newname) {
       System.out.println("The following " + type + " called " + oldname +
           ( renameFile(oldname, newname) ? " was renamed as " : " could not be renamed into ")
           + newname + "."
       );
   }
   public static void main(String args[]) {
        test("file", "input.txt", "output.txt");
        test("file", File.seperator + "input.txt", File.seperator + "output.txt");
        test("directory", "docs", "mydocs");
        test("directory", File.seperator + "docs" + File.seperator, File.seperator + "mydocs" + File.seperator);
   }
}

MAXScript

MAXScript has no folder rename method

-- Here
renameFile "input.txt" "output.txt"
-- Root
renameFile "/input.txt" "/output.txt"

OCaml

Sys.rename "input.txt" "output.txt";;
Sys.rename "docs" "mydocs";;
Sys.rename "/input.txt" "/output.txt";;
Sys.rename "/docs" "/mydocs";;

Pascal / Delphi

  var  
    f : file ; // Untyped file
 begin
 
  // as current directory
  AssignFile(f,'input.doc');
  Rename(f,'output,doc');
 
  // as root directory
  AssignFile(f,'\input.doc');
  Rename(f,'\output,doc');
 
  // rename a directory 
  AssignFile(f,'docs');
  Rename(f,'mydocs');
 
  //rename a directory off the root
 
  AssignFile(f,'\docs');
  Rename(f,'\mydocs');
 
end;

Perl

use File::Copy qw(move);
use File::Spec::Functions qw(catfile rootdir);
# here
move 'input.txt', 'output.txt';
move 'docs', 'mydocs';
# root dir
move (catfile rootdir, 'input.txt'), (catfile rootdir, 'output.txt');
move (catfile rootdir, 'docs'), (catfile rootdir, 'mydocs');

Pop11

sys_file_move('inputs.txt', 'output.txt');
sys_file_move('docs', 'mydocs');
sys_file_move('/inputs.txt', '/output.txt');
sys_file_move(/'docs', '/mydocs');

Note that notion of the root of filesystem is Unix specific, so above we do not try to suport other systems.

PowerShell

Rename-Item input.txt output.txt
# The Rename-item has the alias ren
ren input.txt output.txt

Python

<lang python>

import os

os.rename("input.txt", "output.txt")
os.rename("docs", "mydocs")

os.rename("/input.txt", "/output.txt")
os.rename("/docs", "/mydocs")

</lang>

Ruby

It uses a hash to store the source and destination, so it's easy to add more dirs/files to move and you can easily switch to using another method to move them.

 #!/usr/bin/env ruby
 require 'FileUtils'
 moves = { "input.txt" => "output.txt", "/input.txt" => "/output.txt", "docs" => "mydocs","/docs" => "/mydocs"}
 moves.each{ |src, dest| FileUtils.move( src, dest, :verbose => true ) }

Standard ML

OS.FileSys.rename {old = "input.txt", new = "output.txt"};
OS.FileSys.rename {old = "docs", new = "mydocs"};
OS.FileSys.rename {old = "/input.txt", new = "/output.txt"};
OS.FileSys.rename {old = "/docs", new = "/mydocs"};

Tcl

Assuming that the Bash example shows what is actually meant with this task (one file and one directory here, one file and one directory in the root) and further assuming that this is supposed to be generic (i.e. OS agnostic):

 file rename inputs.txt output.txt
 file rename docs mydocs

 file rename [file nativename /inputs.txt] [file nativename /output.txt]
 file rename [file nativename /docs] [file nativename /mydocs]

Toka

 needs shell
 " input.txt"  " output.txt"  rename
 " /input.txt"  " /output.txt"  rename
 
 " docs"  " mydocs"  rename
 " /docs"  " /mydocs"  rename

UNIX Shell

 mv input.txt output.txt
 mv /input.txt /output.txt
 mv docs mydocs
 mv /docs /mydocs


Visual Basic .NET

Platform: .NET

Works with: Visual Basic .NET version 9.0+
'Current Directory
IO.Directory.Move("docs", "mydocs")
IO.File.Move("input.txt", "output.txt")

'Root
IO.Directory.Move("\docs", "\mydocs")
IO.File.Move("\input.txt", "\output.txt")

'Root, platform independent
IO.Directory.Move(IO.Path.DirectorySeparatorChar & "docs", _
 IO.Path.DirectorySeparatorChar & "mydocs")
IO.File.Move(IO.Path.DirectorySeparatorChar & "input.txt", _
  IO.Path.DirectorySeparatorChar & "output.txt")