Möbius function: Difference between revisions

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The classical '''Möbius function: μ(n)''' is an important multiplicative function in number theory and combinatorics.
The classical '''Möbius function: μ(n)''' is an important multiplicative function in number theory and combinatorics.

Revision as of 12:41, 7 June 2021

Möbius function is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

The classical Möbius function: μ(n) is an important multiplicative function in number theory and combinatorics.

There are several ways to implement a Möbius function.

A fairly straightforward method is to find the prime factors of a positive integer n, then define μ(n) based on the sum of the primitive factors. It has the values {−1, 0, 1} depending on the factorization of n:

  • μ(1) is defined to be 1.
  • μ(n) = 1 if n is a square-free positive integer with an even number of prime factors.
  • μ(n) = −1 if n is a square-free positive integer with an odd number of prime factors.
  • μ(n) = 0 if n has a squared prime factor.


Task
  • Write a routine (function, procedure, whatever) μ(n) to find the Möbius number for a positive integer n.
  • Use that routine to find and display here, on this page, at least the first 99 terms in a grid layout. (Not just one long line or column of numbers.)


See also


Related Tasks



ALGOL 68

Translation of: C

<lang algol68>BEGIN

   # show the first 199 values of the moebius function                 #
   INT sq root = 1 000;
   INT mu max  = sq root * sq root;
   [ 1 : mu max ]INT mu;
   FOR i FROM LWB mu TO UPB mu DO mu[ i ] := 1 OD;
   FOR i FROM 2 TO sq root DO
       IF mu[ i ] = 1 THEN
           # for each factor found, swap + and -                       #
           FOR j FROM i     BY i     TO UPB mu DO mu[ j ] *:= -i OD;
           FOR j FROM i * i BY i * i TO UPB mu DO mu[ j ]  :=  0 OD
       FI
   OD;
   FOR i FROM 2 TO UPB mu DO
       IF   mu[ i ] =  i THEN mu[ i ] :=  1
       ELIF mu[ i ] = -i THEN mu[ i ] := -1
       ELIF mu[ i ] <  0 THEN mu[ i ] :=  1
       ELIF mu[ i ] >  0 THEN mu[ i ] := -1
     # ELSE mu[ i ] =  0 so no change #
       FI
   OD;
   print( ( "First 199 terms of the möbius function are as follows:", newline, "    " ) );
   FOR i TO 199 DO
       print( ( whole( mu[ i ], -4 ) ) );
       IF ( i + 1 ) MOD 20 = 0 THEN print( ( newline ) ) FI
   OD

END</lang>

Output:
First 199 terms of the möbius function are as follows:
       1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1
   0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1
   0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1
   0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1
   0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0
   0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1
   0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1
   0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1
   0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1
   0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1

Arturo

<lang rebol>mobius: function [n][

   if n=0 -> return ""
   if n=1 -> return 1
   f: factors.prime n
   if f <> unique f -> return 0
   if? odd? size f -> return neg 1
   else -> return 1

]

loop split.every:20 map 0..199 => mobius 'a ->

   print map a => [pad to :string & 3]</lang>
Output:
      1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1 
  0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1 
  0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1 
  0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1 
  0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0 
  0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1 
  0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1 
  0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1 
  0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1 
  0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1

AWK

<lang AWK>

  1. syntax: GAWK -f MOBIUS_FUNCTION.AWK
  2. converted from Java

BEGIN {

   printf("first 199 terms of the mobius sequence:\n   ")
   for (n=1; n<200; n++) {
     printf("%3d",mobius(n))
     if ((n+1) % 20 == 0) {
       printf("\n")
     }
   }
   exit(0)

} function mobius(n, i,j,mu_max) {

   if (n in MU) {
     return(MU[n])
   }
   mu_max = 1000000
   for (i=0; i<mu_max; i++) { # populate array
     MU[i] = 1
   }
   for (i=2; i<=int(sqrt(mu_max)); i++ ) {
     if (MU[i] == 1) {
       for (j=i; j<=mu_max; j+=i) { # for each factor found, swap + and -
         MU[j] *= -i
       }
       for (j=i*i; j<=mu_max; j+=i*i) { # square factor = 0
         MU[j] = 0
       }
     }
   }
   for (i=2; i<=mu_max; i++) {
     if (MU[i] == i) {
       MU[i] = 1
     }
     else if (MU[i] == -i) {
       MU[i] = -1
     }
     else if (MU[i] < 0) {
       MU[i] = 1
     }
     else if (MU[i] > 0) {
       MU[i] = -1
     }
   }
   return(MU[n])

} </lang>

Output:
first 199 terms of the mobius sequence:
     1 -1 -1  0 -1  1 -1  0  0  1 -1  0 -1  1  1  0 -1  0 -1
  0  1  1 -1  0  0  1  0  0 -1 -1 -1  0  1  1  1  0 -1  1  1
  0 -1 -1 -1  0  0  1 -1  0  0  0  1  0 -1  0  1  0  1  1 -1
  0 -1  1  0  0  1 -1 -1  0  1 -1 -1  0 -1  1  0  0  1 -1 -1
  0  0  1 -1  0  1  1  1  0 -1  0  1  0  1  1  1  0 -1  0  0
  0 -1 -1 -1  0 -1  1 -1  0 -1 -1  1  0 -1 -1  1  0  0  1  1
  0  0  1  1  0  0  0 -1  0  1 -1 -1  0  1  1  0  0 -1 -1 -1
  0  1  1  1  0  1  1  0  0 -1  0 -1  0  0 -1  1  0 -1  1  1
  0  1  0 -1  0 -1  1 -1  0  0 -1  0  0 -1 -1  0  0  1  1 -1
  0 -1 -1  1  0  1 -1  1  0  0 -1 -1  0 -1  1 -1  0 -1  0 -1

C

Translation of: Java

<lang c>#include <math.h>

  1. include <stdio.h>
  2. include <stdlib.h>
  3. include <string.h>

int main() {

   const int MU_MAX = 1000000;
   int i, j;
   int *mu;
   int sqroot;
   sqroot = (int)sqrt(MU_MAX);
   mu = malloc((MU_MAX + 1) * sizeof(int));
   for (i = 0; i < MU_MAX;i++) {
       mu[i] = 1;
   }
   for (i = 2; i <= sqroot; i++) {
       if (mu[i] == 1) {
           // for each factor found, swap + and -
           for (j = i; j <= MU_MAX; j += i) {
               mu[j] *= -i;
           }
           // square factor = 0
           for (j = i * i; j <= MU_MAX; j += i * i) {
               mu[j] = 0;
           }
       }
   }
   for (i = 2; i <= MU_MAX; i++) {
       if (mu[i] == i) {
           mu[i] = 1;
       } else if (mu[i] == -i) {
           mu[i] = -1;
       } else if (mu[i] < 0) {
           mu[i] = 1;
       } else if (mu[i] > 0) {
           mu[i] = -1;
       }
   }
   printf("First 199 terms of the möbius function are as follows:\n    ");
   for (i = 1; i < 200; i++) {
       printf("%2d  ", mu[i]);
       if ((i + 1) % 20 == 0) {
           printf("\n");
       }
   }
   free(mu);
   return 0;

}</lang>

Output:
First 199 terms of the m÷bius function are as follows:
     1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1
 0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1
 0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1
 0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1
 0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0
 0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1
 0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1
 0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1
 0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1
 0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1

C++

Translation of: Java

<lang cpp>#include <iomanip>

  1. include <iostream>
  2. include <vector>

constexpr int MU_MAX = 1'000'000; std::vector<int> MU;

int mobiusFunction(int n) {

   if (!MU.empty()) {
       return MU[n];
   }
   // Populate array
   MU.resize(MU_MAX + 1, 1);
   int root = sqrt(MU_MAX);
   for (int i = 2; i <= root; i++) {
       if (MU[i] == 1) {
           // for each factor found, swap + and -
           for (int j = i; j <= MU_MAX; j += i) {
               MU[j] *= -i;
           }
           // square factor = 0
           for (int j = i * i; j <= MU_MAX; j += i * i) {
               MU[j] = 0;
           }
       }
   }
   for (int i = 2; i <= MU_MAX; i++) {
       if (MU[i] == i) {
           MU[i] = 1;
       } else if (MU[i] == -i) {
           MU[i] = -1;
       } else if (MU[i] < 0) {
           MU[i] = 1;
       } else if (MU[i] > 0) {
           MU[i] = -1;
       }
   }
   return MU[n];

}

int main() {

   std::cout << "First 199 terms of the möbius function are as follows:\n    ";
   for (int n = 1; n < 200; n++) {
       std::cout << std::setw(2) << mobiusFunction(n) << "  ";
       if ((n + 1) % 20 == 0) {
           std::cout << '\n';
       }
   }
   return 0;

}</lang>

Output:
First 199 terms of the m÷bius function are as follows:
     1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1
 0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1
 0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1
 0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1
 0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0
 0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1
 0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1
 0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1
 0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1
 0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1

D

Translation of: C++

<lang d>import std.math; import std.stdio;

immutable MU_MAX = 1_000_000;

int mobiusFunction(int n) {

   static initialized = false;
   static int[MU_MAX + 1] MU;
   if (initialized) {
       return MU[n];
   }
   // populate array
   MU[] = 1;
   int root = cast(int) sqrt(cast(real) MU_MAX);
   for (int i = 2; i <= root; i++) {
       if (MU[i] == 1) {
           // for each factor found, swap + and -
           for (int j = i; j <= MU_MAX; j += i) {
               MU[j] *= -i;
           }
           // square factor = 0
           for (int j = i * i; j <= MU_MAX; j += i * i) {
               MU[j] = 0;
           }
       }
   }
   for (int i = 2; i <= MU_MAX; i++) {
       if (MU[i] == i) {
           MU[i] = 1;
       } else if (MU[i] == -i) {
           MU[i] = -1;
       } else if (MU[i] < 0) {
           MU[i] = 1;
       } else if (MU[i] > 0) {
           MU[i] = -1;
       }
   }
   initialized = true;
   return MU[n];

}

void main() {

   writeln("First 199 terms of the möbius function are as follows:");
   write("    ");
   for (int n = 1; n < 200; n++) {
       writef("%2d  ", mobiusFunction(n));
       if ((n + 1) % 20 == 0) {
           writeln;
       }
   }

}</lang>

Output:
First 199 terms of the m├╢bius function are as follows:
     1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1
 0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1
 0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1
 0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1
 0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0
 0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1
 0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1
 0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1
 0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1
 0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1

F#

This task uses Extensible Prime Generator (F#) <lang fsharp> // Möbius function. Nigel Galloway: January 31st., 2021 let fN g=let n=primes32()

        let rec fN i g e l=match (l/g,l%g,e) with (1,0,false)->i
                                                 |(n,0,false)->fN (0-i) g true n
                                                 |(_,0,true) ->0
                                                 |_          ->fN i (Seq.head n) false l
        fN -1 (Seq.head n) false g

let mobius=seq{yield 1; yield! Seq.initInfinite((+)2>>fN)} mobius|>Seq.take 500|>Seq.chunkBySize 25|>Seq.iter(fun n->Array.iter(printf "%3d") n;printfn "") </lang>

Output:
  1 -1 -1  0 -1  1 -1  0  0  1 -1  0 -1  1  1  0 -1  0 -1  0  1  1 -1  0  0
  1  0  0 -1 -1 -1  0  1  1  1  0 -1  1  1  0 -1 -1 -1  0  0  1 -1  0  0  0
  1  0 -1  0  1  0  1  1 -1  0 -1  1  0  0  1 -1 -1  0  1 -1 -1  0 -1  1  0
  0  1 -1 -1  0  0  1 -1  0  1  1  1  0 -1  0  1  0  1  1  1  0 -1  0  0  0
 -1 -1 -1  0 -1  1 -1  0 -1 -1  1  0 -1 -1  1  0  0  1  1  0  0  1  1  0  0
  0 -1  0  1 -1 -1  0  1  1  0  0 -1 -1 -1  0  1  1  1  0  1  1  0  0 -1  0
 -1  0  0 -1  1  0 -1  1  1  0  1  0 -1  0 -1  1 -1  0  0 -1  0  0 -1 -1  0
  0  1  1 -1  0 -1 -1  1  0  1 -1  1  0  0 -1 -1  0 -1  1 -1  0 -1  0 -1  0
  1  1  1  0  1  1  0  0  1  1 -1  0  1  1  1  0  1  1  1  0  1 -1 -1  0  0
  1 -1  0 -1 -1 -1  0 -1  0  1  0  1 -1 -1  0 -1  0  0  0  0 -1  1  0  1  0
 -1  0  1  1 -1  0 -1 -1  1  0  0  1 -1  0  1 -1  1  0 -1  0 -1  0 -1  1  0
  0 -1  1  0  0 -1 -1 -1  0 -1 -1  1  0  0 -1  1  0 -1  0  1  0  0  1  1  0
  1  1  1  0  1  0 -1  0  1 -1 -1  0 -1  1  0  0 -1 -1  1  0  1 -1  1  0  0
  1  1  0  1  1 -1  0  0  1  1  0 -1  0  1  0  1  0  0  0 -1  1 -1  0 -1  0
  0  0 -1 -1  1  0 -1  1 -1  0  0  1  0  0  1 -1 -1  0  0 -1  1  0 -1 -1  0
  0  1  0 -1  0  1  1 -1  0 -1  1  0  0 -1  1  1  0  1  1  1  0 -1  1 -1  0
 -1 -1  1  0  0 -1  1  0 -1 -1  1  0  1  0  1  0  1 -1 -1  0 -1  1  0  0  0
 -1  1  0 -1 -1 -1  0 -1 -1 -1  0  1 -1 -1  0  0 -1 -1  0  1  1  1  0 -1  0
  1  0  1  1 -1  0 -1  1  0  0 -1  1 -1  0 -1  1 -1  0  1 -1  1  0  1 -1  0
  0  0  1 -1  0  1  1 -1  0  1  0 -1  0  1  0 -1  0  1 -1  0  0  1 -1 -1  0

Factor

The mobius word exists in the math.extras vocabulary. See the implementation here.

Works with: Factor version 0.99 2020-01-23

<lang factor>USING: formatting grouping io math.extras math.ranges sequences ;

"First 199 terms of the Möbius sequence:" print 199 [1,b] [ mobius ] map " " prefix 20 group [ [ "%3s" printf ] each nl ] each</lang>

Output:
First 199 terms of the Möbius sequence:
     1 -1 -1  0 -1  1 -1  0  0  1 -1  0 -1  1  1  0 -1  0 -1
  0  1  1 -1  0  0  1  0  0 -1 -1 -1  0  1  1  1  0 -1  1  1
  0 -1 -1 -1  0  0  1 -1  0  0  0  1  0 -1  0  1  0  1  1 -1
  0 -1  1  0  0  1 -1 -1  0  1 -1 -1  0 -1  1  0  0  1 -1 -1
  0  0  1 -1  0  1  1  1  0 -1  0  1  0  1  1  1  0 -1  0  0
  0 -1 -1 -1  0 -1  1 -1  0 -1 -1  1  0 -1 -1  1  0  0  1  1
  0  0  1  1  0  0  0 -1  0  1 -1 -1  0  1  1  0  0 -1 -1 -1
  0  1  1  1  0  1  1  0  0 -1  0 -1  0  0 -1  1  0 -1  1  1
  0  1  0 -1  0 -1  1 -1  0  0 -1  0  0 -1 -1  0  0  1  1 -1
  0 -1 -1  1  0  1 -1  1  0  0 -1 -1  0 -1  1 -1  0 -1  0 -1

Fortran

Translation of: C

<lang fortran> program moebius

   use iso_fortran_env, only: output_unit
   integer, parameter          :: mu_max=1000000, line_break=20
   integer, parameter          :: sqroot=int(sqrt(real(mu_max)))
   integer                     :: i, j
   integer, dimension(mu_max)  :: mu
   mu = 1
   do i = 2, sqroot
       if (mu(i) == 1) then
           do j = i, mu_max, i
               mu(j) = mu(j) * (-i)
           end do
           do j = i**2, mu_max, i**2
               mu(j) = 0
           end do
       end if
   end do
   do i = 2, mu_max
       if (mu(i) == i) then
           mu(i) = 1
       else if (mu(i) == -i) then
           mu(i) = -1
       else if (mu(i) < 0) then
           mu(i) = 1
       else if (mu(i) > 0) then
           mu(i) = -1
       end if
   end do
   write(output_unit,*) "The first 199 terms of the Möbius sequence are:"
   write(output_unit,'(3x)', advance="no") ! Alignment of first number
   do i = 1, 199
       write(output_unit,'(I2,x)', advance="no") mu(i)
       if (modulo(i+1, line_break) == 0) write(output_unit,*)
   end do

end program moebius </lang>

Output:
 The first 199 terms of the Möbius sequence are:
    1 -1 -1  0 -1  1 -1  0  0  1 -1  0 -1  1  1  0 -1  0 -1 
 0  1  1 -1  0  0  1  0  0 -1 -1 -1  0  1  1  1  0 -1  1  1 
 0 -1 -1 -1  0  0  1 -1  0  0  0  1  0 -1  0  1  0  1  1 -1 
 0 -1  1  0  0  1 -1 -1  0  1 -1 -1  0 -1  1  0  0  1 -1 -1 
 0  0  1 -1  0  1  1  1  0 -1  0  1  0  1  1  1  0 -1  0  0 
 0 -1 -1 -1  0 -1  1 -1  0 -1 -1  1  0 -1 -1  1  0  0  1  1 
 0  0  1  1  0  0  0 -1  0  1 -1 -1  0  1  1  0  0 -1 -1 -1 
 0  1  1  1  0  1  1  0  0 -1  0 -1  0  0 -1  1  0 -1  1  1 
 0  1  0 -1  0 -1  1 -1  0  0 -1  0  0 -1 -1  0  0  1  1 -1 
 0 -1 -1  1  0  1 -1  1  0  0 -1 -1  0 -1  1 -1  0 -1  0 -1 

FreeBASIC

<lang freebasic>function mobius( n as uinteger ) as integer

   if n = 1 then return 1
   for d as uinteger = 2 to int(sqr(n))
       if n mod d = 0 then 
           if n mod (d*d) = 0 then return 0
           return -mobius(n/d)
       end if
   next d
   return -1

end function

dim as string outstr = " . " for i as uinteger = 1 to 200

   if mobius(i)>=0 then outstr += " "
   outstr += str(mobius(i))+"     "
   if i mod 10 = 9 then 
       print outstr
       outstr = ""
   end if

next i</lang>

Output:
 .      1     -1     -1      0     -1      1     -1      0      0     
 1     -1      0     -1      1      1      0     -1      0     -1     
 0      1      1     -1      0      0      1      0      0     -1     
-1     -1      0      1      1      1      0     -1      1      1     
 0     -1     -1     -1      0      0      1     -1      0      0     
 0      1      0     -1      0      1      0      1      1     -1     
 0     -1      1      0      0      1     -1     -1      0      1     
-1     -1      0     -1      1      0      0      1     -1     -1     
 0      0      1     -1      0      1      1      1      0     -1     
 0      1      0      1      1      1      0     -1      0      0     
 0     -1     -1     -1      0     -1      1     -1      0     -1     
-1      1      0     -1     -1      1      0      0      1      1     
 0      0      1      1      0      0      0     -1      0      1     
-1     -1      0      1      1      0      0     -1     -1     -1     
 0      1      1      1      0      1      1      0      0     -1     
 0     -1      0      0     -1      1      0     -1      1      1     
 0      1      0     -1      0     -1      1     -1      0      0     
-1      0      0     -1     -1      0      0      1      1     -1     
 0     -1     -1      1      0      1     -1      1      0      0     
-1     -1      0     -1      1     -1      0     -1      0     -1

Go

<lang go>package main

import "fmt"

func möbius(to int) []int {

   if to < 1 {
       to = 1
   }
   mobs := make([]int, to+1) // all zero by default
   primes := []int{2}
   for i := 1; i <= to; i++ {
       j := i
       cp := 0      // counts prime factors
       spf := false // true if there is a square prime factor
       for _, p := range primes {
           if p > j {
               break
           }
           if j%p == 0 {
               j /= p
               cp++
           }
           if j%p == 0 {
               spf = true
               break
           }
       }
       if cp == 0 && i > 2 {
           cp = 1
           primes = append(primes, i)
       }
       if !spf {
           if cp%2 == 0 {
               mobs[i] = 1
           } else {
               mobs[i] = -1
           }
       }
   }
   return mobs

}

func main() {

   mobs := möbius(199)
   fmt.Println("Möbius sequence - First 199 terms:")
   for i := 0; i < 200; i++ {
       if i == 0 {
           fmt.Print("    ")
           continue
       }
       if i%20 == 0 {
           fmt.Println()
       }
       fmt.Printf("  % d", mobs[i])
   }

}</lang>

Output:
Möbius sequence - First 199 terms:
       1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1
   0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1
   0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1
   0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1
   0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0
   0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1
   0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1
   0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1
   0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1
   0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1

GW-BASIC

<lang gwbasic>10 FOR T = 0 TO 9 20 FOR U = 1 TO 10 30 N = 10*T + U 40 GOSUB 100 50 PRINT USING "## ";M; 60 NEXT U 70 PRINT 80 NEXT T 90 END 100 IF N = 1 THEN M = 1 : RETURN 110 M = 1 : F = 2 120 IF N MOD (F*F) = 0 THEN M = 0 : RETURN 130 IF N MOD F = 0 THEN GOSUB 170 140 F = F + 1 150 IF F <= N THEN GOTO 120 160 RETURN 170 M = -M 180 N = N/F 190 RETURN</lang>

Java

<lang java> public class MöbiusFunction {

   public static void main(String[] args) {
       System.out.printf("First 199 terms of the möbius function are as follows:%n    ");
       for ( int n = 1 ; n < 200 ; n++ ) {
           System.out.printf("%2d  ", möbiusFunction(n));
           if ( (n+1) % 20 == 0 ) {
               System.out.printf("%n");
           }
       }
   }
   
   private static int MU_MAX = 1_000_000;
   private static int[] MU = null;
   
   //  Compute mobius function via sieve
   private static int möbiusFunction(int n) {
       if ( MU != null ) {
           return MU[n];
       }
       
       //  Populate array
       MU = new int[MU_MAX+1];
       int sqrt = (int) Math.sqrt(MU_MAX);
       for ( int i = 0 ; i < MU_MAX ; i++ ) {
           MU[i] = 1;
       }
       
       for ( int i = 2 ; i <= sqrt ; i++ ) {
           if ( MU[i] == 1 ) {
               //  for each factor found, swap + and -
               for ( int j = i ; j <= MU_MAX ; j += i ) {
                   MU[j] *= -i;
               }
               //  square factor = 0
               for ( int j = i*i ; j <= MU_MAX ; j += i*i ) {
                   MU[j] = 0;
               }
           }
       }
       
       for ( int i = 2 ; i <= MU_MAX ; i++ ) {
           if ( MU[i] == i ) {
               MU[i] = 1;
           }
           else if ( MU[i] == -i ) {
               MU[i] = -1;
           }
           else if ( MU[i] < 0 ) {
               MU[i] = 1;               
           }
           else if ( MU[i] > 0 ) {
               MU[i] = -1;
           }
       }
       return MU[n];
   }

} </lang>

Output:
First 199 terms of the möbius function are as follows:
     1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1  
 0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1  
 0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1  
 0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1  
 0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0  
 0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1  
 0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1  
 0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1  
 0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1  
 0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1  

Julia

<lang julia>using Primes

  1. modified from reinermartin's PR at https://github.com/JuliaMath/Primes.jl/pull/70/files

function moebius(n::Integer)

   @assert n > 0
   m(p, e) = p == 0 ? 0 : e == 1 ? -1 : 0
   reduce(*, m(p, e) for (p, e) in factor(n) if p ≥ 0; init=1)

end μ(n) = moebius(n)

print("First 199 terms of the Möbius sequence:\n ") for n in 1:199

   print(lpad(μ(n), 3), n % 20 == 19 ? "\n" : "")

end

</lang>

Output:
First 199 terms of the Möbius sequence:
     1 -1 -1  0 -1  1 -1  0  0  1 -1  0 -1  1  1  0 -1  0 -1
  0  1  1 -1  0  0  1  0  0 -1 -1 -1  0  1  1  1  0 -1  1  1
  0 -1 -1 -1  0  0  1 -1  0  0  0  1  0 -1  0  1  0  1  1 -1
  0 -1  1  0  0  1 -1 -1  0  1 -1 -1  0 -1  1  0  0  1 -1 -1
  0  0  1 -1  0  1  1  1  0 -1  0  1  0  1  1  1  0 -1  0  0
  0 -1 -1 -1  0 -1  1 -1  0 -1 -1  1  0 -1 -1  1  0  0  1  1
  0  0  1  1  0  0  0 -1  0  1 -1 -1  0  1  1  0  0 -1 -1 -1
  0  1  1  1  0  1  1  0  0 -1  0 -1  0  0 -1  1  0 -1  1  1
  0  1  0 -1  0 -1  1 -1  0  0 -1  0  0 -1 -1  0  0  1  1 -1
  0 -1 -1  1  0  1 -1  1  0  0 -1 -1  0 -1  1 -1  0 -1  0 -1

Kotlin

Translation of: Java

<lang scala>import kotlin.math.sqrt

fun main() {

   println("First 199 terms of the möbius function are as follows:")
   print("    ")
   for (n in 1..199) {
       print("%2d  ".format(mobiusFunction(n)))
       if ((n + 1) % 20 == 0) {
           println()
       }
   }

}

private const val MU_MAX = 1000000 private var MU: IntArray? = null

// Compute mobius function via sieve private fun mobiusFunction(n: Int): Int {

   if (MU != null) {
       return MU!![n]
   }
   //  Populate array
   MU = IntArray(MU_MAX + 1)
   val sqrt = sqrt(MU_MAX.toDouble()).toInt()
   for (i in 0 until MU_MAX) {
       MU!![i] = 1
   }
   for (i in 2..sqrt) {
       if (MU!![i] == 1) {
           //  for each factor found, swap + and -
           for (j in i..MU_MAX step i) {
               MU!![j] *= -i
           }
           //  square factor = 0
           for (j in i * i..MU_MAX step i * i) {
               MU!![j] = 0
           }
       }
   }
   for (i in 2..MU_MAX) {
       when {
           MU!![i] == i -> {
               MU!![i] = 1
           }
           MU!![i] == -i -> {
               MU!![i] = -1
           }
           MU!![i] < 0 -> {
               MU!![i] = 1
           }
           MU!![i] > 0 -> {
               MU!![i] = -1
           }
       }
   }
   return MU!![n]

}</lang>

Output:
First 199 terms of the möbius function are as follows:
     1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1  
 0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1  
 0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1  
 0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1  
 0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0  
 0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1  
 0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1  
 0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1  
 0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1  
 0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1  

Lua

Translation of: C

<lang lua>function buildArray(size, value)

   local tbl = {}
   for i=1, size do
       table.insert(tbl, value)
   end
   return tbl

end

MU_MAX = 1000000 sqroot = math.sqrt(MU_MAX) mu = buildArray(MU_MAX, 1)

for i=2, sqroot do

   if mu[i] == 1 then
       -- for each factor found, swap + and -
       for j=i, MU_MAX, i do
           mu[j] = mu[j] * -i
       end
       -- square factor = 0
       for j=i*i, MU_MAX, i*i do
           mu[j] = 0
       end
   end

end

for i=2, MU_MAX do

   if mu[i] == i then
       mu[i] = 1
   elseif mu[i] == -i then
       mu[i] = -1
   elseif mu[i] < 0 then
       mu[i] = 1
   elseif mu[i] > 0 then
       mu[i] = -1
   end

end

print("First 199 terms of the mobius function are as follows:") io.write(" ") for i=1, 199 do

   io.write(string.format("%2d  ", mu[i]))
   if (i + 1) % 20 == 0 then
       print()
   end

end</lang>

Output:
First 199 terms of the mobius function are as follows:
     1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1
 0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1
 0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1
 0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1
 0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0
 0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1
 0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1
 0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1
 0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1
 0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1

Pascal

 See Mertens_function#Pascal

Perl

<lang perl>use utf8; use strict; use warnings; use feature 'say'; use List::Util 'uniq';

sub prime_factors {

   my ($n, $d, @factors) = (shift, 1);
   while ($n > 1 and $d++) {
       $n /= $d, push @factors, $d until $n % $d;
   }
   @factors

}

sub μ {

   my @p = prime_factors(shift);
   @p == uniq(@p) ? 0 == @p%2 ? 1 : -1 : 0;

}

my @möebius; push @möebius, μ($_) for 1 .. (my $upto = 199);

say "Möbius sequence - First $upto terms:\n" .

   (' 'x4 . sprintf "@{['%4d' x $upto]}", @möebius) =~ s/((.){80})/$1\n/gr;</lang>
Output:
Möbius sequence - First 199 terms:
       1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1
   0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1
   0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1
   0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1
   0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0
   0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1
   0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1
   0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1
   0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1
   0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1

Phix

<lang Phix>function Moebius(integer n)

   if n=1 then return 1 end if
   sequence f = prime_factors(n,true)
   for i=2 to length(f) do
       if f[i] = f[i-1] then return 0 end if
   end for
   return iff(and_bits(length(f),1)?-1:+1)

end function

sequence s = {" ."} for i=1 to 199 do s = append(s,sprintf("%3d",Moebius(i))) end for puts(1,join_by(s,1,20," "))</lang>

Output:
  .   1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1
  0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1
  0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1
  0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1
  0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0
  0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1
  0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1
  0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1
  0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1
  0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1

Raku

(formerly Perl 6)

Works with: Rakudo version 2019.11

Möbius number is not defined for n == 0. Raku arrays are indexed from 0 so store a blank value at position zero to keep n and μ(n) aligned.

<lang perl6>use Prime::Factor;

sub μ (Int \n) {

   return 0 if n %% 4 or n %% 9 or n %% 25 or n %% 49 or n %% 121;
   my @p = prime-factors(n);
   +@p == +@p.unique ?? +@p %% 2 ?? 1 !! -1 !! 0

}

my @möbius = lazy flat , 1, (2..*).hyper.map: -> \n { μ(n) };

  1. The Task

put "Möbius sequence - First 199 terms:\n",

   @möbius[^200]».fmt('%3s').batch(20).join: "\n";</lang>
Output:
Möbius sequence - First 199 terms:
      1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1
  0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1
  0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1
  0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1
  0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0
  0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1
  0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1
  0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1
  0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1
  0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1

REXX

Note that the   Möbius   function is also spelled   Mobius   and/or Moebius,   and it is also known as the   mu   function,   where   mu   is the Greek symbol   μ.

Programming note:   This REXX version supports the specifying of the low and high values to be generated,
as well as the group size for the grid   (it can be specified as   1   which will show a vertical list).

A null value will be shown as a bullet (•) when showing the Möbius value of for zero   (this can be changed in the 2nd line of the   mobius   function).

The above "feature" was added to make the grid to be aligned with other solutions.

The function to computer some prime numbers is a bit of an overkill, but the goal was to keep it general  (in case of larger/higher ranges for a Möbius sequence). <lang rexx>/*REXX pgm computes & shows a value grid of the Möbius function for a range of integers.*/ parse arg LO HI grp . /*obtain optional arguments from the CL*/ if LO== | LO=="," then LO= 0 /*Not specified? Then use the default.*/ if HI== | HI=="," then HI= 199 /* " " " " " " */ if grp== | grp=="," then grp= 20 /* " " " " " " */

                                                /*                            ______   */

call genP HI /*generate primes up to the √ HI */ say center(' The Möbius sequence from ' LO " ──► " HI" ", max(50, grp*3), '═') /*title*/ $= /*variable holds output grid of GRP #s.*/

   do j=LO  to  HI;  $= $  right( mobius(j), 2) /*process some numbers from  LO ──► HI.*/
   if words($)==grp  then do;  say substr($, 2);  $=    /*show grid if fully populated,*/
                          end                           /*  and nullify it for more #s.*/
   end   /*j*/                                  /*for small grids, using wordCnt is OK.*/

if $\== then say substr($, 2) /*handle any residual numbers not shown*/ exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ mobius: procedure expose @.; parse arg x /*obtain a integer to be tested for mu.*/

       if x<1  then return '∙'                  /*special? Then return symbol for null.*/
       #= 0                                     /*start with a value of zero.          */
            do k=1;  p= @.k                     /*get the  Kth  (pre─generated)  prime.*/
            if p>x  then leave                  /*prime (P)   > X?    Then we're done. */
            if p*p>x  then do;   #= #+1;  leave /*prime (P**2 > X?    Bump # and leave.*/
                           end
            if x//p==0  then do; #= #+1         /*X divisible by P?   Bump mu number.  */
                                 x= x % p       /*                    Divide by prime. */
                                 if x//p==0  then return 0  /*X÷by P?  Then return zero*/
                             end
            end   /*k*/                         /*#  (below) is almost always small, <9*/
       if #//2==0  then return  1               /*Is # even?   Then return postive  1  */
                        return -1               /* " "  odd?     "     "   negative 1. */

/*──────────────────────────────────────────────────────────────────────────────────────*/ genP: @.1=2; @.2=3; @.3=5; @.4=7; @.5=11; @.6= 13; nP=6 /*assign low primes; # primes.*/

                   do lim=nP  until lim*lim>=HI /*only keep primes up to the  sqrt(HI).*/
                   end   /*lim*/
      do j=@.nP+4  by 2  to HI                  /*only find odd primes from here on.   */
      parse var j  -1 _;if _==5  then iterate /*Is last digit a "5"?   Then not prime*/
      if j// 3==0  then iterate                 /*is J divisible by  3?    "   "    "  */
      if j// 7==0  then iterate                 /* " "     "      "  7?    "   "    "  */
      if j//11==0  then iterate                 /* " "     "      " 11?    "   "    "  */
      if j//13==0  then iterate                 /* " "     "      " 13?    "   "    "  */
                do k=7  while k*k<=j            /*divide by some generated odd primes. */
                if j // @.k==0  then iterate j  /*Is J divisible by  P?  Then not prime*/
                end   /*k*/                     /* [↓]  a prime  (J)  has been found.  */
      nP= nP+1;    if nP<=HI  then @.nP= j      /*bump prime count; assign prime to  @.*/
      end      /*j*/;              return</lang>
output   when using the default inputs:

Output note:   note the use of a bullet (•) to signify that a "null" is being shown (for the 0th entry).

══════════ The Möbius sequence from  0  ──►  199 ═══════════
 ∙  1 -1 -1  0 -1  1 -1  0  0  1 -1  0 -1  1  1  0 -1  0 -1
 0  1  1 -1  0  0  1  0  0 -1 -1 -1  0  1  1  1  0 -1  1  1
 0 -1 -1 -1  0  0  1 -1  0  0  0  1  0 -1  0  1  0  1  1 -1
 0 -1  1  0  0  1 -1 -1  0  1 -1 -1  0 -1  1  0  0  1 -1 -1
 0  0  1 -1  0  1  1  1  0 -1  0  1  0  1  1  1  0 -1  0  0
 0 -1 -1 -1  0 -1  1 -1  0 -1 -1  1  0 -1 -1  1  0  0  1  1
 0  0  1  1  0  0  0 -1  0  1 -1 -1  0  1  1  0  0 -1 -1 -1
 0  1  1  1  0  1  1  0  0 -1  0 -1  0  0 -1  1  0 -1  1  1
 0  1  0 -1  0 -1  1 -1  0  0 -1  0  0 -1 -1  0  0  1  1 -1
 0 -1 -1  1  0  1 -1  1  0  0 -1 -1  0 -1  1 -1  0 -1  0 -1

Ring

Translation of: FreeBASIC

<lang ring> mobStr = " . "

for i = 1 to 200

   if mobius(i) >= 0
      mobStr + = " "
   ok
   temp = string(mobius(i))
   if left(temp,2) = "-0"
      temp = right(temp,len(temp)-1)
   ok
   mobStr += temp + " "
   if i % 10 = 9  
       see mobStr + nl
       mobStr = "     "
   ok

next

func mobius(n)

    if n = 1 
       return 1
    ok
    for d = 2 to ceil(sqrt(n))
        if n % d = 0  
           if n % (d*d) = 0
              return 0
           ok
           return -mobius(n/d)
        ok
    next 
    return -1

</lang> Output:

      .  1 -1 -1  0 -1  1 -1  0  0 
      1 -1  0 -1  1  1  0 -1  0 -1 
      0  1  1 -1  0  0  1  0  0 -1 
     -1 -1  0  1  1  1  0 -1  1  1 
      0 -1 -1 -1  0  0  1 -1  0  0 
      0  1  0 -1  0  1  0  1  1 -1 
      0 -1  1  0  0  1 -1 -1  0  1 
     -1 -1  0 -1  1  0  0  1 -1 -1 
      0  0  1 -1  0  1  1  1  0 -1 
      0  1  0  1  1  1  0 -1  0  0 
      0 -1 -1 -1  0 -1  1 -1  0 -1 
     -1  1  0 -1 -1  1  0  0  1  1 
      0  0  1  1  0  0  0 -1  0  1 
     -1 -1  0  1  1  0  0 -1 -1 -1 
      0  1  1  1  0  1  1  0  0 -1 
      0 -1  0  0 -1  1  0 -1  1  1 
      0  1  0 -1  0 -1  1 -1  0  0 
     -1  0  0 -1 -1  0  0  1  1 -1 
      0 -1 -1  1  0  1 -1  1  0  0 
     -1 -1  0 -1  1 -1  0 -1  0 -1 

Ruby

<lang ruby>require 'prime'

def μ(n)

 pd = n.prime_division
 return 0 unless pd.map(&:last).all?(1)
 pd.size.even? ? 1 : -1

end

([" "] + (1..199).map{|n|"%2s" % μ(n)}).each_slice(20){|line| puts line.join(" ") }

</lang>

Output:
    1 -1 -1  0 -1  1 -1  0  0  1 -1  0 -1  1  1  0 -1  0 -1
 0  1  1 -1  0  0  1  0  0 -1 -1 -1  0  1  1  1  0 -1  1  1
 0 -1 -1 -1  0  0  1 -1  0  0  0  1  0 -1  0  1  0  1  1 -1
 0 -1  1  0  0  1 -1 -1  0  1 -1 -1  0 -1  1  0  0  1 -1 -1
 0  0  1 -1  0  1  1  1  0 -1  0  1  0  1  1  1  0 -1  0  0
 0 -1 -1 -1  0 -1  1 -1  0 -1 -1  1  0 -1 -1  1  0  0  1  1
 0  0  1  1  0  0  0 -1  0  1 -1 -1  0  1  1  0  0 -1 -1 -1
 0  1  1  1  0  1  1  0  0 -1  0 -1  0  0 -1  1  0 -1  1  1
 0  1  0 -1  0 -1  1 -1  0  0 -1  0  0 -1 -1  0  0  1  1 -1
 0 -1 -1  1  0  1 -1  1  0  0 -1 -1  0 -1  1 -1  0 -1  0 -1

Sidef

Built-in:

<lang ruby>say moebius(53) #=> -1 say moebius(54) #=> 0 say moebius(55) #=> 1</lang>

Simple implementation: <lang ruby>func μ(n) {

   var f = n.factor_exp.map { .tail }
   f.any { _ > 1 } ? 0 : ((-1)**f.sum)

}

with (199) { |n|

   say "Values of the Möbius function for numbers in the range 1..#{n}:"
   [' '] + (1..n->map(μ)) -> each_slice(20, {|*line|
       say line.map { '%2s' % _ }.join(' ')
   })

}</lang>

Output:
Values of the Möbius function for numbers in the range 1..199:
    1 -1 -1  0 -1  1 -1  0  0  1 -1  0 -1  1  1  0 -1  0 -1
 0  1  1 -1  0  0  1  0  0 -1 -1 -1  0  1  1  1  0 -1  1  1
 0 -1 -1 -1  0  0  1 -1  0  0  0  1  0 -1  0  1  0  1  1 -1
 0 -1  1  0  0  1 -1 -1  0  1 -1 -1  0 -1  1  0  0  1 -1 -1
 0  0  1 -1  0  1  1  1  0 -1  0  1  0  1  1  1  0 -1  0  0
 0 -1 -1 -1  0 -1  1 -1  0 -1 -1  1  0 -1 -1  1  0  0  1  1
 0  0  1  1  0  0  0 -1  0  1 -1 -1  0  1  1  0  0 -1 -1 -1
 0  1  1  1  0  1  1  0  0 -1  0 -1  0  0 -1  1  0 -1  1  1
 0  1  0 -1  0 -1  1 -1  0  0 -1  0  0 -1 -1  0  0  1  1 -1
 0 -1 -1  1  0  1 -1  1  0  0 -1 -1  0 -1  1 -1  0 -1  0 -1

Tiny BASIC

Tiny BASIC is not suited for printing tables, so this is limited to prompting for a single number and calculating its Mobius number.

<lang tinybasic> PRINT "Enter an integer"

   INPUT N
   IF N < 0 THEN LET N = -N
   IF N < 2 THEN GOTO 100 + N
   LET C = 1
   LET F = 2
10 IF ((N/F)/F)*F*F = N THEN GOTO 100
   IF (N/F)*F = N THEN GOTO 30
20 LET F = F + 1
   IF F<=N THEN GOTO 10
   GOTO 100 + C
30 LET N = N / F
   LET C = -C
   GOTO 20
99 PRINT "-1"
   END

100 PRINT "0"

   END

101 PRINT "1"

   END</lang>

Wren

Library: Wren-fmt
Library: Wren-math

<lang ecmascript>import "/fmt" for Fmt import "/math" for Int

var isSquareFree = Fn.new { |n|

   var i = 2
   while (i * i <= n) {
       if (n%(i*i) == 0) return false
       i = (i > 2) ? i + 2 : i + 1
   }
   return true

}

var mu = Fn.new { |n|

   if (n < 1) Fiber.abort("Argument must be a positive integer")
   if (n == 1) return 1
   var sqFree = isSquareFree.call(n)
   var factors = Int.primeFactors(n)
   if (sqFree && factors.count % 2 == 0) return 1
   if (sqFree) return -1
   return 0

}

System.print("The first 199 Möbius numbers are:") for (i in 0..9) {

   for (j in 0..19) {
       if (i == 0 && j == 0) {
           System.write("    ")
       } else {
           System.write("%(Fmt.dm(3, mu.call(i*20 + j))) ")
       }
   }
   System.print()

}</lang>

Output:
The first 199 Möbius numbers are:
      1  -1  -1   0  -1   1  -1   0   0   1  -1   0  -1   1   1   0  -1   0  -1 
  0   1   1  -1   0   0   1   0   0  -1  -1  -1   0   1   1   1   0  -1   1   1 
  0  -1  -1  -1   0   0   1  -1   0   0   0   1   0  -1   0   1   0   1   1  -1 
  0  -1   1   0   0   1  -1  -1   0   1  -1  -1   0  -1   1   0   0   1  -1  -1 
  0   0   1  -1   0   1   1   1   0  -1   0   1   0   1   1   1   0  -1   0   0 
  0  -1  -1  -1   0  -1   1  -1   0  -1  -1   1   0  -1  -1   1   0   0   1   1 
  0   0   1   1   0   0   0  -1   0   1  -1  -1   0   1   1   0   0  -1  -1  -1 
  0   1   1   1   0   1   1   0   0  -1   0  -1   0   0  -1   1   0  -1   1   1 
  0   1   0  -1   0  -1   1  -1   0   0  -1   0   0  -1  -1   0   0   1   1  -1 
  0  -1  -1   1   0   1  -1   1   0   0  -1  -1   0  -1   1  -1   0  -1   0  -1 

zkl

<lang zkl>fcn mobius(n){

  pf:=primeFactors(n);
  sq:=pf.filter1('wrap(f){ (n % (f*f))==0 });  // False if square free
  if(sq==False){ if(pf.len().isEven) 1 else -1 }
  else 0

} fcn primeFactors(n){ // Return a list of prime factors of n

  acc:=fcn(n,k,acc,maxD){  // k is 2,3,5,7,9,... not optimum
     if(n==1 or k>maxD) acc.close();
     else{

q,r:=n.divr(k); // divr-->(quotient,remainder) if(r==0) return(self.fcn(q,k,acc.write(k),q.toFloat().sqrt())); return(self.fcn(n,k+1+k.isOdd,acc,maxD)) # both are tail recursion

     }
  }(n,2,Sink(List),n.toFloat().sqrt());
  m:=acc.reduce('*,1);      // mulitply factors
  if(n!=m) acc.append(n/m); // opps, missed last factor
  else acc;

}</lang> <lang zkl>[1..199].apply(mobius) .pump(Console.println, T(Void.Read,19,False), fcn{ vm.arglist.pump(String,"%3d".fmt) });</lang>

Output:
  1 -1 -1  0 -1  1 -1  0  0  1 -1  0 -1  1  1  0 -1  0 -1  0
  1  1 -1  0  0  1  0  0 -1 -1 -1  0  1  1  1  0 -1  1  1  0
 -1 -1 -1  0  0  1 -1  0  0  0  1  0 -1  0  1  0  1  1 -1  0
 -1  1  0  0  1 -1 -1  0  1 -1 -1  0 -1  1  0  0  1 -1 -1  0
  0  1 -1  0  1  1  1  0 -1  0  1  0  1  1  1  0 -1  0  0  0
 -1 -1 -1  0 -1  1 -1  0 -1 -1  1  0 -1 -1  1  0  0  1  1  0
  0  1  1  0  0  0 -1  0  1 -1 -1  0  1  1  0  0 -1 -1 -1  0
  1  1  1  0  1  1  0  0 -1  0 -1  0  0 -1  1  0 -1  1  1  0
  1  0 -1  0 -1  1 -1  0  0 -1  0  0 -1 -1  0  0  1  1 -1  0
 -1 -1  1  0  1 -1  1  0  0 -1 -1  0 -1  1 -1  0 -1  0 -1