JSON: Difference between revisions
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=={{header|JavaScript}}== |
=={{header|JavaScript}}== |
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Requires JSON library, now present in some browsers. |
Requires JSON library, now present in some browsers. |
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<lang JavaScript>var data = JSON.parse('{ "foo": 1, "bar": [10, "apples"] }') |
<lang JavaScript>var data = JSON.parse('{ "foo": 1, "bar": [10, "apples"] }'); |
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var sample = { "blue": [1,2], "ocean": "water" }; |
var sample = { "blue": [1,2], "ocean": "water" }; |
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var json_string = JSON.stringify(sample);</lang> |
var json_string = JSON.stringify(sample);</lang> |
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Of course, it IS called ''JavaScript'' Object Notation, so it is a JavaScript object literal, |
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and you can, alternately, parse it by just eval'ing it. This should work in any browser without a library. |
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(Eval may be dangerous, depending on the source of the data.) |
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However, there is an ambiguity with parsing JavaScript object literals by themselves, where it might be mistakenly interpreted as a block, and the key followed by a colon as a label. To avoid this, remember to surround it in parentheses to force it to be interpreted as an expression: |
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<lang javascript>var data = eval('(' + '{ "foo": 1, "bar": [10, "apples"] }' + ')');</lang> |
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=={{header|PHP}}== |
=={{header|PHP}}== |
Revision as of 05:58, 25 August 2010
You are encouraged to solve this task according to the task description, using any language you may know.
Load a JSON string into a data structure. Also create a new data structure and serialize it into JSON. Use objects and arrays, and make sure your JSON is valid (http://www.jsonlint.com/).
JavaScript
Requires JSON library, now present in some browsers. <lang JavaScript>var data = JSON.parse('{ "foo": 1, "bar": [10, "apples"] }');
var sample = { "blue": [1,2], "ocean": "water" }; var json_string = JSON.stringify(sample);</lang>
Of course, it IS called JavaScript Object Notation, so it is a JavaScript object literal, and you can, alternately, parse it by just eval'ing it. This should work in any browser without a library. (Eval may be dangerous, depending on the source of the data.) However, there is an ambiguity with parsing JavaScript object literals by themselves, where it might be mistakenly interpreted as a block, and the key followed by a colon as a label. To avoid this, remember to surround it in parentheses to force it to be interpreted as an expression: <lang javascript>var data = eval('(' + '{ "foo": 1, "bar": [10, "apples"] }' + ')');</lang>
PHP
<lang php><?php $data = json_decode('{ "foo": 1, "bar": [10, "apples"] }'); // dictionaries will be returned as objects $data2 = json_decode('{ "foo": 1, "bar": [10, "apples"] }', true); // dictionaries will be returned as arrays
$sample = array( "blue" => array(1,2), "ocean" => "water" ); $json_string = json_encode($sample); ?></lang>
Python
<lang Python>import json data = json.loads('{ "foo": 1, "bar": [10, "apples"] }')
sample = { "blue": [1,2], "ocean": "water" } json_string = json.dumps(sample)</lang>