Hickerson series of almost integers

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Task
Hickerson series of almost integers
You are encouraged to solve this task according to the task description, using any language you may know.

The following function, due to D Hickerson is said to generate "Almost integers" by the "Almost Integer" page of Wolfram Mathworld. (December 31 2013).

The function is:

The function is said to produce "almost integers" for n in the given range.

Assume that an "almost integer" has either a nine or a zero as its first digit after the decimal point of its decimal string representation

The task is to calculate all values of the function checking and stating which are "almost integers".

Note: Use extended/arbitrary precision numbers in your calculation if necessary to ensure you have adequate precision of results as for example:

   h(18) = 3385534663256845326.39...

C++

Library: Boost version 1.53 or later

<lang cpp>#include <iostream>

  1. include <iomanip>
  2. include <boost/multiprecision/cpp_dec_float.hpp>
  3. include <boost/math/constants/constants.hpp>

typedef boost::multiprecision::cpp_dec_float_50 decfloat;

int main() {

   const decfloat ln_two = boost::math::constants::ln_two<decfloat>();
   decfloat numerator = 1, denominator = ln_two;
   
   for(int n = 1; n <= 17; n++) {
       decfloat h = (numerator *= n) / (denominator *= ln_two) / 2;
       decfloat tenths_dig = floor((h - floor(h)) * 10);
       std::cout << "h(" << std::setw(2) << n << ") = " << std::setw(25) << std::fixed << h << 
           (tenths_dig == 0 || tenths_dig == 9 ? " is " : " is NOT ") << "an almost-integer.\n";
   }

} </lang>

Output:
h( 1) =                  1.040684 is an almost-integer.
h( 2) =                  3.002781 is an almost-integer.
h( 3) =                 12.996291 is an almost-integer.
h( 4) =                 74.998735 is an almost-integer.
h( 5) =                541.001519 is an almost-integer.
h( 6) =               4683.001247 is an almost-integer.
h( 7) =              47292.998731 is an almost-integer.
h( 8) =             545834.997907 is an almost-integer.
h( 9) =            7087261.001623 is an almost-integer.
h(10) =          102247563.005271 is an almost-integer.
h(11) =         1622632572.997550 is an almost-integer.
h(12) =        28091567594.981572 is an almost-integer.
h(13) =       526858348381.001248 is an almost-integer.
h(14) =     10641342970443.084532 is an almost-integer.
h(15) =    230283190977853.037436 is an almost-integer.
h(16) =   5315654681981354.513077 is NOT an almost-integer.
h(17) = 130370767029135900.457985 is NOT an almost-integer.

Clojure

This example is incomplete. Please ensure that it meets all task requirements and remove this message.

This first implementation uses regular precision, which is not enough for this purpose.

<lang clojure>(defn hickerson

 "Hickerson number, calculated with default floating-point settings."
 [n]
 (let [n! (apply * (range 1 (inc n)))]
   (/ n! (* 2 (Math/pow (Math/log 2) (inc n))))))

(defn almost-integer?

 "Tests whether the first digit in the decimal expansion of a number is 0 or 9."
 [x]
 (let [first-digit (int (Math/floor (* 10 (- x (Math/floor x)))))]
   (or (= 0 first-digit) (= 9 first-digit))))
Execute for side effects

(doseq [n (range 1 18)

        :let [h (hickerson n)]]
 (println (format "%2d %24.5f" n h)
          (if (almost-integer? h)
            "almost integer"
            "NOT almost integer")))</lang>
Output:
 1                  1,04068 almost integer
 2                  3,00278 almost integer
 3                 12,99629 almost integer
 4                 74,99874 almost integer
 5                541,00152 almost integer
 6               4683,00125 almost integer
 7              47292,99873 almost integer
 8             545834,99791 almost integer
 9            7087261,00162 almost integer
10          102247563,00527 almost integer
11         1622632572,99755 almost integer
12        28091567594,98158 almost integer
13       526858348381,00150 almost integer
14     10641342970443,09000 almost integer
15    230283190977853,16000 NOT almost integer
16   5315654681981358,00000 almost integer
17 130370767029135968,00000 almost integer
nil

COBOL

Works with: GNU Cobol version 2.0

<lang cobol> >>SOURCE FREE IDENTIFICATION DIVISION. PROGRAM-ID. hickerson-series.

ENVIRONMENT DIVISION. CONFIGURATION SECTION. REPOSITORY.

   FUNCTION ALL INTRINSIC
   .

DATA DIVISION. WORKING-STORAGE SECTION. 01 n PIC 99 COMP.

01 h PIC Z(19)9.9(10).

01 First-Decimal-Digit-Pos CONSTANT 22.

PROCEDURE DIVISION.

   PERFORM VARYING n FROM 0 BY 1 UNTIL n > 17
       COMPUTE h = FACTORIAL(n) / (2 * LOG(2) ** (n + 1))
       DISPLAY "h(" n ") = " h " which is " NO ADVANCING
       IF h (First-Decimal-Digit-Pos:1) = "0" OR "9"
           DISPLAY "an almost integer."
       ELSE
           DISPLAY "not an almost integer."
       END-IF
   END-PERFORM
   .

END PROGRAM hickerson-series.</lang>

Output:
h(00) =                    0.7213475204 which is not an almost integer.
h(01) =                    1.0406844905 which is an almost integer.
h(02) =                    3.0027807071 which is an almost integer.
h(03) =                   12.9962905052 which is an almost integer.
h(04) =                   74.9987354476 which is an almost integer.
h(05) =                  541.0015185164 which is an almost integer.
h(06) =                 4683.0012472622 which is an almost integer.
h(07) =                47292.9987313146 which is an almost integer.
h(08) =               545834.9979074851 which is an almost integer.
h(09) =              7087261.0016228991 which is an almost integer.
h(10) =            102247563.0052710420 which is an almost integer.
h(11) =           1622632572.9975500498 which is an almost integer.
h(12) =          28091567594.9815724407 which is an almost integer.
h(13) =         526858348381.0012482861 which is an almost integer.
h(14) =       10641342970443.0845319270 which is an almost integer.
h(15) =      230283190977853.0374360391 which is an almost integer.
h(16) =     5315654681981354.5130767434 which is not an almost integer.
h(17) =   130370767029135900.4579853491 which is not an almost integer.

D

The D real type has enough precision for this task. <lang d>import std.stdio, std.algorithm, std.mathspecial;

void main() {

   foreach (immutable n; 0 .. 18) {
       immutable x = gamma(n + 1) / (2 * LN2 ^^ (n + 1)),
                 tenths = cast(int)floor((x - x.floor) * 10);
       writefln("H(%2d)=%22.2f is %snearly integer.", n, x,
                 [0, 9].canFind(tenths) ? "" : "NOT ");
   }

}</lang>

H( 0)=                  0.72 is NOT nearly integer.
H( 1)=                  1.04 is nearly integer.
H( 2)=                  3.00 is nearly integer.
H( 3)=                 13.00 is nearly integer.
H( 4)=                 75.00 is nearly integer.
H( 5)=                541.00 is nearly integer.
H( 6)=               4683.00 is nearly integer.
H( 7)=              47293.00 is nearly integer.
H( 8)=             545835.00 is nearly integer.
H( 9)=            7087261.00 is nearly integer.
H(10)=          102247563.01 is nearly integer.
H(11)=         1622632573.00 is nearly integer.
H(12)=        28091567594.98 is nearly integer.
H(13)=       526858348381.00 is nearly integer.
H(14)=     10641342970443.08 is nearly integer.
H(15)=    230283190977853.04 is nearly integer.
H(16)=   5315654681981354.51 is NOT nearly integer.
H(17)= 130370767029135900.50 is NOT nearly integer.

Go

<lang go>package main

import (

   "fmt"
   "math/big"

)

func main() {

   ln2, _ := new(big.Rat).SetString("0.6931471805599453094172")
   h := big.NewRat(1, 2)
   h.Quo(h, ln2)
   var f big.Rat
   var w big.Int
   for i := int64(1); i <= 17; i++ {
       h.Quo(h.Mul(h, f.SetInt64(i)), ln2)
       w.Quo(h.Num(), h.Denom())
       f.Sub(h, f.SetInt(&w))
       y, _ := f.Float64()
       d := fmt.Sprintf("%.3f", y)
       fmt.Printf("n: %2d  h: %18d%s  Nearly integer: %t\n",
           i, &w, d[1:], d[2] == '0' || d[2] == '9')
   }

}</lang>

Output:
n:  1  h:                  1.041  Nearly integer: true
n:  2  h:                  3.003  Nearly integer: true
n:  3  h:                 12.996  Nearly integer: true
n:  4  h:                 74.999  Nearly integer: true
n:  5  h:                541.002  Nearly integer: true
n:  6  h:               4683.001  Nearly integer: true
n:  7  h:              47292.999  Nearly integer: true
n:  8  h:             545834.998  Nearly integer: true
n:  9  h:            7087261.002  Nearly integer: true
n: 10  h:          102247563.005  Nearly integer: true
n: 11  h:         1622632572.998  Nearly integer: true
n: 12  h:        28091567594.982  Nearly integer: true
n: 13  h:       526858348381.001  Nearly integer: true
n: 14  h:     10641342970443.085  Nearly integer: true
n: 15  h:    230283190977853.037  Nearly integer: true
n: 16  h:   5315654681981354.513  Nearly integer: false
n: 17  h: 130370767029135900.458  Nearly integer: false

Perl 6

We'll use FatRat values, and a series for an approximation of ln(2).

<lang perl6>constant ln2 = [\+] map { 1.FatRat / 2**$_ / $_ }, 1 .. *; constant fact = 1, [\*] 1..*;

sub h(Int $n --> FatRat) { fact[$n] / (2 * ln2[100]**($n+1)) }

use Test; plan 17;

for 1 .. 17 -> $n {

   ok m/'.'<[09]>/, .round(0.001) given h($n);

}</lang>

Output:
1..17
ok 1 - 1.041
ok 2 - 3.003
ok 3 - 12.996
ok 4 - 74.999
ok 5 - 541.002
ok 6 - 4683.001
ok 7 - 47292.999
ok 8 - 545834.998
ok 9 - 7087261.002
ok 10 - 102247563.005
ok 11 - 1622632572.998
ok 12 - 28091567594.982
ok 13 - 526858348381.001
ok 14 - 10641342970443.085
ok 15 - 230283190977853.037
not ok 16 - 5315654681981354.513
not ok 17 - 130370767029135900.458
# Looks like you failed 2 tests of 17

Python

This uses Pythons decimal module of fixed precision decimal floating point calculations.

<lang python>from decimal import Decimal import math

def h(n):

   'Simple, reduced precision calculation'
   return math.factorial(n) / (2 * math.log(2) ** (n + 1))
   

def h2(n):

   'Extended precision Hickerson function'
   return Decimal(math.factorial(n)) / (2 * Decimal(2).ln() ** (n + 1))

for n in range(18):

   x = h2(n)
   norm = str(x.normalize())
   almostinteger = (' Nearly integer' 
                    if 'E' not in norm and ('.0' in norm or '.9' in norm) 
                    else ' NOT nearly integer!')
   print('n:%2i h:%s%s' % (n, norm, almostinteger))</lang>
Output:
n: 0 h:0.7213475204444817036799623405 NOT nearly integer!
n: 1 h:1.040684490502803898934790802 Nearly integer
n: 2 h:3.002780707156905443499767406 Nearly integer
n: 3 h:12.99629050527696646222488454 Nearly integer
n: 4 h:74.99873544766160012763455035 Nearly integer
n: 5 h:541.0015185164235075692027746 Nearly integer
n: 6 h:4683.001247262257437180467151 Nearly integer
n: 7 h:47292.99873131462390482283547 Nearly integer
n: 8 h:545834.9979074851670672910395 Nearly integer
n: 9 h:7087261.001622899120979187513 Nearly integer
n:10 h:102247563.0052710420110883885 Nearly integer
n:11 h:1622632572.997550049852874859 Nearly integer
n:12 h:28091567594.98157244071518915 Nearly integer
n:13 h:526858348381.0012482861804887 Nearly integer
n:14 h:10641342970443.08453192709506 Nearly integer
n:15 h:230283190977853.0374360391257 Nearly integer
n:16 h:5315654681981354.513076743451 NOT nearly integer!
n:17 h:130370767029135900.4579853491 NOT nearly integer!

The range for should be reduced to be for this definition of almost integer.

REXX

<lang rexx>/* REXX ---------------------------------------------------------------

  • 04.01.2014 Walter Pachl - using a rather aged ln function of mine
  • with probably unreasonably high precision
  • --------------------------------------------------------------------*/

Numeric Digits 100 Do n=1 To 17

 x=format(def(),20,10)
 Parse Var x '.' +1 d +1
 If pos(d,'09')>0 Then
   tag='almost an integer'
 Else
   tag=
 Say right(n,2) x tag
 End

Exit

def:

x=fact(n)/(2*ln(2,200)**(n + 1))
Return x

ln: Procedure /***********************************************************************

  • Return ln(x) -- with specified precision
  • Three different series are used for the ranges 0 to 0.5
  • 0.5 to 1.5
  • 1.5 to infinity
  • 920903 Walter Pachl
                                                                                                                                              • /
 Parse Arg x,prec,b
 If prec= Then prec=9
 Numeric Digits (2*prec)
 Numeric Fuzz   3
 Select
   When x<=0 Then r='*** invalid argument ***'
   When x<0.5 Then Do
     z=(x-1)/(x+1)
     o=z
     r=z
     k=1
     Do i=3 By 2
       ra=r
       k=k+1
       o=o*z*z
       r=r+o/i
       If r=ra Then Leave
       End
     r=2*r
     End
   When x<1.5 Then Do
     z=(x-1)
     o=z
     r=z
     k=1
     Do i=2 By 1
       ra=r
       k=k+1
       o=-o*z
       r=r+o/i
       If r=ra Then Leave
       End
     End
   Otherwise /* 1.5<=x */ Do
     z=(x+1)/(x-1)
     o=1/z
     r=o
     k=1
     Do i=3 By 2
       ra=r
       k=k+1
       o=o/(z*z)
       r=r+o/i
       If r=ra Then Leave
       End
     r=2*r
     End
   End
 If b<> Then
   r=r/ln(b)
 Numeric Digits (prec)
 Return r+0

fact: Procedure

Parse Arg m
fact=1
Do i=2 To m
  fact=fact*i
  End
Return fact</lang>
Output:
 1                    1.0406844905 almost an integer
 2                    3.0027807072 almost an integer
 3                   12.9962905053 almost an integer
 4                   74.9987354477 almost an integer
 5                  541.0015185164 almost an integer
 6                 4683.0012472623 almost an integer
 7                47292.9987313146 almost an integer
 8               545834.9979074852 almost an integer
 9              7087261.0016228991 almost an integer
10            102247563.0052710420 almost an integer
11           1622632572.9975500499 almost an integer
12          28091567594.9815724407 almost an integer
13         526858348381.0012482862 almost an integer
14       10641342970443.0845319271 almost an integer
15      230283190977853.0374360391 almost an integer
16     5315654681981354.5130767435
17   130370767029135900.4579853492

Ruby

Using the BigDecimal standard library: <lang ruby> require "bigdecimal"

LN2 = BigMath::log(2,16) #Use LN2 = Math::log(2) to see the difference with floats FACTORIALS = Hash.new{|h,k,v| h[k]=k * h[k-1]} FACTORIALS[0] = 1

def hickerson(n)

 FACTORIALS[n] / (2 * LN2 ** (n+1))

end

def nearly_int?(n)

 int = n.round
 n.between?(int - 0.1, int + 0.1)

end

1.upto(17) do |n|

 h = hickerson(n)
 str = nearly_int?(h) ? "nearly integer" : "NOT nearly integer"
 puts "n:%3i h: %s\t%s" % [n, h.to_s('F')[0,25], str] #increase the 25 to print more digits, there are 856 of them

end

</lang>

Output:
n:  1 h: 1.04068449050280389893479	nearly integer
n:  2 h: 3.00278070715690544349976	nearly integer
n:  3 h: 12.9962905052769664622248	nearly integer
n:  4 h: 74.9987354476616001276345	nearly integer
n:  5 h: 541.001518516423507569202	nearly integer
n:  6 h: 4683.00124726225743718046	nearly integer
n:  7 h: 47292.9987313146239048228	nearly integer
n:  8 h: 545834.997907485167067291	nearly integer
n:  9 h: 7087261.00162289912097918	nearly integer
n: 10 h: 102247563.005271042011088	nearly integer
n: 11 h: 1622632572.99755004985287	nearly integer
n: 12 h: 28091567594.9815724407151	nearly integer
n: 13 h: 526858348381.001248286180	nearly integer
n: 14 h: 10641342970443.0845319270	nearly integer
n: 15 h: 230283190977853.037436039	nearly integer
n: 16 h: 5315654681981354.51307674	NOT nearly integer
n: 17 h: 130370767029135900.457985	NOT nearly integer