Determine if two triangles overlap
Determining if two triangles in the same plane overlap is an important topic in collision detection.
- Task
Determine which of these pairs of triangles overlap in 2D:
- (0,0),(5,0),(0,5) and (0,0),(5,0),(0,6)
- (0,0),(0,5),(5,0) and (0,0),(0,5),(5,0)
- (0,0),(5,0),(0,5) and (-10,0),(-5,0),(-1,6)
- (0,0),(5,0),(2.5,5) and (0,4),(2.5,-1),(5,4)
- (0,0),(1,1),(0,2) and (2,1),(3,0),(3,2)
- (0,0),(1,1),(0,2) and (2,1),(3,-2),(3,4)
Optionally, see what the result is when only a single corner is in contact (there is no definitively correct answer):
- (0,0),(1,0),(0,1) and (1,0),(2,0),(1,1)
C++
<lang cpp>#include <vector>
- include <iostream>
- include <stdexcept>
using namespace std;
typedef std::pair<double, double> TriPoint;
inline double Det2D(TriPoint &p1, TriPoint &p2, TriPoint &p3) { return +p1.first*(p2.second-p3.second) +p2.first*(p3.second-p1.second) +p3.first*(p1.second-p2.second); }
void CheckTriWinding(TriPoint &p1, TriPoint &p2, TriPoint &p3, bool allowReversed) { double detTri = Det2D(p1, p2, p3); if(detTri < 0.0) { if (allowReversed) { TriPoint a = p3; p3 = p2; p2 = a; } else throw std::runtime_error("triangle has wrong winding direction"); } }
bool BoundaryCollideChk(TriPoint &p1, TriPoint &p2, TriPoint &p3, double eps) { return Det2D(p1, p2, p3) < eps; }
bool BoundaryDoesntCollideChk(TriPoint &p1, TriPoint &p2, TriPoint &p3, double eps) { return Det2D(p1, p2, p3) <= eps; }
bool TriTri2D(TriPoint *t1, TriPoint *t2, double eps = 0.0, bool allowReversed = false, bool onBoundary = true) { //Trangles must be expressed anti-clockwise CheckTriWinding(t1[0], t1[1], t1[2], allowReversed); CheckTriWinding(t2[0], t2[1], t2[2], allowReversed);
bool (*chkEdge)(TriPoint &, TriPoint &, TriPoint &, double) = NULL; if(onBoundary) //Points on the boundary are considered as colliding chkEdge = BoundaryCollideChk; else //Points on the boundary are not considered as colliding chkEdge = BoundaryDoesntCollideChk;
//For edge E of trangle 1, for(int i=0; i<3; i++) { int j=(i+1)%3;
//Check all points of trangle 2 lay on the external side of the edge E. If //they do, the triangles do not collide. if (chkEdge(t1[i], t1[j], t2[0], eps) && chkEdge(t1[i], t1[j], t2[1], eps) && chkEdge(t1[i], t1[j], t2[2], eps)) return false; }
//For edge E of trangle 2, for(int i=0; i<3; i++) { int j=(i+1)%3;
//Check all points of trangle 1 lay on the external side of the edge E. If //they do, the triangles do not collide. if (chkEdge(t2[i], t2[j], t1[0], eps) && chkEdge(t2[i], t2[j], t1[1], eps) && chkEdge(t2[i], t2[j], t1[2], eps)) return false; }
//The triangles collide return true; }
int main() { {TriPoint t1[] = {TriPoint(0,0),TriPoint(5,0),TriPoint(0,5)}; TriPoint t2[] = {TriPoint(0,0),TriPoint(5,0),TriPoint(0,6)}; cout << TriTri2D(t1, t2) << "," << true << endl;}
{TriPoint t1[] = {TriPoint(0,0),TriPoint(0,5),TriPoint(5,0)}; TriPoint t2[] = {TriPoint(0,0),TriPoint(0,5),TriPoint(5,0)}; cout << TriTri2D(t1, t2, 0.0, true) << "," << true << endl;}
{TriPoint t1[] = {TriPoint(0,0),TriPoint(5,0),TriPoint(0,5)}; TriPoint t2[] = {TriPoint(-10,0),TriPoint(-5,0),TriPoint(-1,6)}; cout << TriTri2D(t1, t2) << "," << false << endl;}
{TriPoint t1[] = {TriPoint(0,0),TriPoint(5,0),TriPoint(2.5,5)}; TriPoint t2[] = {TriPoint(0,4),TriPoint(2.5,-1),TriPoint(5,4)}; cout << TriTri2D(t1, t2) << "," << true << endl;}
{TriPoint t1[] = {TriPoint(0,0),TriPoint(1,1),TriPoint(0,2)}; TriPoint t2[] = {TriPoint(2,1),TriPoint(3,0),TriPoint(3,2)}; cout << TriTri2D(t1, t2) << "," << false << endl;}
{TriPoint t1[] = {TriPoint(0,0),TriPoint(1,1),TriPoint(0,2)}; TriPoint t2[] = {TriPoint(2,1),TriPoint(3,-2),TriPoint(3,4)}; cout << TriTri2D(t1, t2) << "," << false << endl;}
//Barely touching {TriPoint t1[] = {TriPoint(0,0),TriPoint(1,0),TriPoint(0,1)}; TriPoint t2[] = {TriPoint(1,0),TriPoint(2,0),TriPoint(1,1)}; cout << TriTri2D(t1, t2, 0.0, false, true) << "," << true << endl;}
//Barely touching {TriPoint t1[] = {TriPoint(0,0),TriPoint(1,0),TriPoint(0,1)}; TriPoint t2[] = {TriPoint(1,0),TriPoint(2,0),TriPoint(1,1)}; cout << TriTri2D(t1, t2, 0.0, false, false) << "," << false << endl;}
}</lang>
- Output:
1,1 1,1 0,0 1,1 0,0 0,0 1,1 0,0
Python
Using numpy:
<lang python>from __future__ import print_function import numpy as np
def CheckTriWinding(tri, allowReversed): trisq = np.ones((3,3)) trisq[:,0:2] = np.array(tri) detTri = np.linalg.det(trisq) if detTri < 0.0: if allowReversed: a = trisq[2,:].copy() trisq[2,:] = trisq[1,:] trisq[1,:] = a else: raise ValueError("triangle has wrong winding direction") return trisq
def TriTri2D(t1, t2, eps = 0.0, allowReversed = False, onBoundary = True): #Trangles must be expressed anti-clockwise t1s = CheckTriWinding(t1, allowReversed) t2s = CheckTriWinding(t2, allowReversed)
if onBoundary: #Points on the boundary are considered as colliding chkEdge = lambda x: np.linalg.det(x) < eps else: #Points on the boundary are not considered as colliding chkEdge = lambda x: np.linalg.det(x) <= eps
#For edge E of trangle 1, for i in range(3): edge = np.roll(t1s, i, axis=0)[:2,:]
#Check all points of trangle 2 lay on the external side of the edge E. If #they do, the triangles do not collide. if (chkEdge(np.vstack((edge, t2s[0]))) and chkEdge(np.vstack((edge, t2s[1]))) and chkEdge(np.vstack((edge, t2s[2])))): return False
#For edge E of trangle 2, for i in range(3): edge = np.roll(t2s, i, axis=0)[:2,:]
#Check all points of trangle 1 lay on the external side of the edge E. If #they do, the triangles do not collide. if (chkEdge(np.vstack((edge, t1s[0]))) and chkEdge(np.vstack((edge, t1s[1]))) and chkEdge(np.vstack((edge, t1s[2])))): return False
#The triangles collide return True
if __name__=="__main__": t1 = [[0,0],[5,0],[0,5]] t2 = [[0,0],[5,0],[0,6]] print (TriTri2D(t1, t2), True)
t1 = [[0,0],[0,5],[5,0]] t2 = [[0,0],[0,6],[5,0]] print (TriTri2D(t1, t2, allowReversed = True), True)
t1 = [[0,0],[5,0],[0,5]] t2 = [[-10,0],[-5,0],[-1,6]] print (TriTri2D(t1, t2), False)
t1 = [[0,0],[5,0],[2.5,5]] t2 = [[0,4],[2.5,-1],[5,4]] print (TriTri2D(t1, t2), True)
t1 = [[0,0],[1,1],[0,2]] t2 = [[2,1],[3,0],[3,2]] print (TriTri2D(t1, t2), False)
t1 = [[0,0],[1,1],[0,2]] t2 = [[2,1],[3,-2],[3,4]] print (TriTri2D(t1, t2), False)
#Barely touching t1 = [[0,0],[1,0],[0,1]] t2 = [[1,0],[2,0],[1,1]] print (TriTri2D(t1, t2, onBoundary = True), True)
#Barely touching t1 = [[0,0],[1,0],[0,1]] t2 = [[1,0],[2,0],[1,1]] print (TriTri2D(t1, t2, onBoundary = False), False)</lang>
- Output:
True True True True False False True True False False False False True True /False False
Using shapely:
<lang python>from __future__ import print_function from shapely.geometry import Polygon
def PolyOverlaps(poly1, poly2): poly1s = Polygon(poly1) poly2s = Polygon(poly2) return poly1s.intersects(poly2s)
if __name__=="__main__": t1 = [[0,0],[5,0],[0,5]] t2 = [[0,0],[5,0],[0,6]] print (PolyOverlaps(t1, t2), True)
t1 = [[0,0],[0,5],[5,0]] t2 = [[0,0],[0,6],[5,0]] print (PolyOverlaps(t1, t2), True)
t1 = [[0,0],[5,0],[0,5]] t2 = [[-10,0],[-5,0],[-1,6]] print (PolyOverlaps(t1, t2), False)
t1 = [[0,0],[5,0],[2.5,5]] t2 = [[0,4],[2.5,-1],[5,4]] print (PolyOverlaps(t1, t2), True)
t1 = [[0,0],[1,1],[0,2]] t2 = [[2,1],[3,0],[3,2]] print (PolyOverlaps(t1, t2), False)
t1 = [[0,0],[1,1],[0,2]] t2 = [[2,1],[3,-2],[3,4]] print (PolyOverlaps(t1, t2), False)
#Barely touching t1 = [[0,0],[1,0],[0,1]] t2 = [[1,0],[2,0],[1,1]] print (PolyOverlaps(t1, t2), "?")</lang>
- Output:
True True True True False False True True False False False False True ?
zkl
<lang zkl>// A triangle is three pairs of points: ( (x,y), (x,y), (x,y) )
fcn det2D(triangle){
p1,p2,p3 := triangle; p1[0]*(p2[1] - p3[1]) + p2[0]*(p3[1] - p1[1]) + p3[0]*(p1[1] - p2[1]);
} fcn checkTriWinding(triangle,allowReversed){ //-->triangle, maybe new
detTri:=det2D(triangle); if(detTri<0.0){ if(allowReversed){ p1,p2,p3 := triangle; return(p1,p3,p2); } // reverse else throw(Exception.AssertionError(
"triangle has wrong winding direction"));
} triangle // no change
} fcn boundaryCollideChk(triangle,eps) { det2D(triangle)<eps } fcn boundaryDoesntCollideChk(triangle,eps){ det2D(triangle)<=eps } fcn triTri2D(triangle1,triangle2, eps=0.0, allowReversed=False, onBoundary=True){
// Trangles must be expressed anti-clockwise triangle1=checkTriWinding(triangle1, allowReversed); triangle2=checkTriWinding(triangle2, allowReversed); chkEdge:= if(onBoundary) // Points on the boundary are considered as colliding
boundaryCollideChk;
else // Points on the boundary are not considered as colliding
boundaryDoesntCollideChk;;
t1,t2 := triangle1,triangle2; // change names to protect the typist do(2){ // check triangle1 and then triangle2 foreach i in (3){ //For edge E of trangle 1,
j:=(i+1)%3; // 1,2,0 // Check all points of trangle 2 lay on the external side // of the edge E. If they do, the triangles do not collide. if(chkEdge(T(t1[i],t1[j],t2[0]), eps) and chkEdge(T(t1[i],t1[j],t2[1]), eps) and chkEdge(T(t1[i],t1[j],t2[2]), eps)) return(False); // no collision
} t2,t1 = triangle1,triangle2; // flip and re-test }
True // The triangles collide
}</lang> <lang zkl>fcn toTri(ax,ay,bx,by,cx,cy){ //-->( (ax,ay),(bx,by),(cx,cy) )
vm.arglist.apply("toFloat").pump(List,Void.Read)
} triangles:=T( // pairs of triangles
T(toTri(0,0, 5,0, 0, 5), toTri( 0,0, 5, 0, 0,6)), T(toTri(0,0, 0,5, 5, 0), toTri( 0,0, 0, 5 , 5,0)), T(toTri(0,0, 5,0, 0, 5), toTri(-10,0, -5, 0, -1,6)), T(toTri(0,0, 5,0, 2.5,5), toTri( 0,4, 2.5,-1, 5,4)), T(toTri(0,0, 1,1, 0, 2), toTri( 2,1, 3, 0, 3,2)), T(toTri(0,0, 1,1, 0, 2), toTri( 2,1, 3, -2, 3,4))
);
// Expect: overlap, overlap (reversed), no overlap, overlap, no overlap, no overlap
foreach t1,t2 in (triangles){
reg r, reversed=False; try{ r=triTri2D(t1,t2) } catch(AssertionError){ r=triTri2D(t1,t2,0.0,True); reversed=True; } print(t1,"\n",t2," "); println(r and "overlap" or "no overlap", reversed and " (reversed)" or ""); println();
}
c1,c2 := toTri(0,0, 1,0, 0,1), toTri(1,0, 2,0, 1,1); println("Corner case (barely touching): ",triTri2D(c1,c2,0.0,False,True)); // True println("Corner case (barely touching): ",triTri2D(c1,c2,0.0,False,False)); // False</lang>
- Output:
L(L(0,0),L(5,0),L(0,5)) L(L(0,0),L(5,0),L(0,6)) overlap L(L(0,0),L(0,5),L(5,0)) L(L(0,0),L(0,5),L(5,0)) overlap (reversed) L(L(0,0),L(5,0),L(0,5)) L(L(-10,0),L(-5,0),L(-1,6)) no overlap L(L(0,0),L(5,0),L(2.5,5)) L(L(0,4),L(2.5,-1),L(5,4)) overlap L(L(0,0),L(1,1),L(0,2)) L(L(2,1),L(3,0),L(3,2)) no overlap L(L(0,0),L(1,1),L(0,2)) L(L(2,1),L(3,-2),L(3,4)) no overlap Corner case (barely touching): True Corner case (barely touching): False