Common sorted list
Given an integer array nums, the goal is create common sorted list with unique elements.
- Example
nums = [5,1,3,8,9,4,8,7], [3,5,9,8,4], [1,3,7,9]
output = [1,3,4,5,7,8,9]
Factor
Note: in older versions of Factor, union-all
is called refine
.
<lang factor>USING: formatting kernel sets sorting ;
{ { 5 1 3 8 9 4 8 7 } { 3 5 9 8 4 } { 1 3 7 9 } } dup union-all natural-sort "Sorted union of %u is:\n%u\n" printf</lang>
- Output:
Sorted union of { { 5 1 3 8 9 4 8 7 } { 3 5 9 8 4 } { 1 3 7 9 } } is: { 1 3 4 5 7 8 9 }
REXX
<lang rexx>/*REXX pgm creates and displays a common sorted list of a specified collection of sets*/ parse arg a /*obtain optional arguments from the CL*/ if a= | a="," then a= '[5,1,3,8,9,4,8,7] [3,5,9,8,4] [1,3,7,9]' /*default sets.*/ x= translate(a, ,'],[') /*extract elements from collection sets*/ se= words(x)
- = 0; $= /*#: number of unique elements; $: list*/
$= /*the list of common elements (so far).*/
do j=1 for se; _= word(x, j) /*traipse through all elements in sets.*/ if wordpos(_, $)>0 then iterate /*Is element in the new list? Yes, skip*/ $= $ _; #= # + 1; @.#= _ /*add to list; bump counter; assign──►@*/ end /*j*/
$= call eSort # /*use any short (small) exchange sort.*/
do k=1 for #; $= $ @.k /*rebuild the $ list, it's been sorted.*/ end /*k*/
say 'the list of sorted common elements in all sets: ' "["translate(space($), ',', " ")']' exit 0 /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ eSort: procedure expose @.; arg h 1 z; do while h>1; h= h%2; do i=1 for z-h; j= i; k= h+i
do while @.k<@.j; t=@.j; @.j=@.k; @.k=t; if h>=j then leave; j=j-h; k=k-h; end;end end; return /*this sort was used 'cause of brevity.*/</lang>
- output when using the default inputs:
the list of sorted common elements in all sets: [1,3,4,5,7,8,9]
Ring
<lang ring> nums = [[5,1,3,8,9,4,8,7],[3,5,9,8,4],[1,3,7,9]] sumNums = []
for n = 1 to len(nums)
for m = 1 to len(nums[n]) add(sumNums,nums[n][m]) next
next
sumNums = sort(sumNums) for n = len(sumNums) to 2 step -1
if sumNums[n] = sumNums[n-1] del(sumNums,n) ok
next
sumNums = sort(sumNums)
see "common sorted list elements are: " showArray(sumNums)
func showArray(array)
txt = "" see "[" for n = 1 to len(array) txt = txt + array[n] + "," next txt = left(txt,len(txt)-1) txt = txt + "]" see txt
</lang>
- Output:
common sorted list elements are: [1,3,4,5,7,8,9]
Wren
<lang ecmascript>import "/seq" for Lst import "/sort" for Sort
var distinctSortedUnion = Fn.new { |ll|
var res = ll.reduce([]) { |acc, l| acc + l } res = Lst.distinct(res) Sort.insertion(res) return res
}
var ll = [[5, 1, 3, 8, 9, 4, 8, 7], [3, 5, 9, 8, 4], [1, 3, 7, 9]] System.print("Distinct sorted union of %(ll) is:") System.print(distinctSortedUnion.call(ll))</lang>
- Output:
Distinct sorted union of [[5, 1, 3, 8, 9, 4, 8, 7], [3, 5, 9, 8, 4], [1, 3, 7, 9]] is: [1, 3, 4, 5, 7, 8, 9]