A+B

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A+B - in programming contests, classic problem, which is given so contestants can gain familiarity with online judging system being used.

A+B is one of few problems on contests, which traditionally lacks fabula.

Problem statement

Given 2 integer numbers, A and B. One needs to find their sum.

Input data

In input stream, two integer numbers are written, separated by space.  

Output data

In output, should be one integer be written: sum of A and B.

Example

Input Output
2 2 4
3 2 5

Solution

Pascal

<lang pascal> var

  a, b: integer;

begin

  readln(a, b);
  writeln(a + b);

end. </lang> Same with input from file input.txt and output from file output.txt. <lang pascal> var

  a, b: integer;

begin

  reset(input, 'input.txt');
  rewrite(output, 'output.txt');
  readln(a, b);
  writeln(a + b);
  close(input);
  close(output);

end. </lang>

C

<lang c> // Standard input-output streams

  1. include <stdio.h>

main() {

  int a, b;
  scanf("%d%d", &a, &b);
  printf("%d\n", a + b);

} </lang> <lang c> // Input file: input.txt // Output file: output.txt

  1. include <stdio.h>

int main() {

  freopen("input.txt", "rt", stdin);
  freopen("output.txt", "wt", stdout);
  int a, b;
  scanf("%d%d", &a, &b);
  printf("%d\n", a + b);
  return 0;

} </lang>

C++

<lang cpp> // Standard input-output streams

  1. include <iostream>

using namespace std; int main() {

  int a, b;
  cin >> a >> b;
  cout << a + b << endl;
  return 0;

} </lang> <lang cpp> // Input file: input.txt // Output file: output.txt

  1. include <fstream>

using namespace std; int main() {

  ifstream in("input.txt");
  ofstream out("output.txt");
  int a, b;
  in >> a >> b;
  out << a + b << endl;
  return 0;

} </lang>

Java

<lang java> import java.util.*;

public class Sum2 {

  public static void main(String[] args) {
     Scanner in = new Scanner(System.in); // Standard input
     System.out.println(in.nextInt() + in.nextInt()); // Standard output
  }

} </lang> Object of class Scanner works slow enough, because of that contestants prefer to avoid its use. Often, longer solution works faster and easily scales to problems.

<lang java> import java.io.*; import java.util.*;

public class SumDif {

  StreamTokenizer in;
  PrintWriter out;
  public static void main(String[] args) throws IOException {
     new SumDif().run();
  }
  private int nextInt() throws IOException {
     in.nextToken();
     return (int)in.nval;
  }
  public void run() throws IOException {
     in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in))); // Standard input
     out = new PrintWriter(new OutputStreamWriter(System.out)); // Standard output
     solve();
     out.flush();
  }
  private void solve() throws IOException {
     out.println(nextInt() + nextInt());
  }

} </lang>

<lang java>

import java.io.*;

public class AplusB { public static void main(String[] args) { try { StreamTokenizer in = new StreamTokenizer(new FileReader("input.txt")); in.nextToken(); int a = (int) in.nval; in.nextToken(); int b = (int) in.nval; FileWriter outFile = new FileWriter("output.txt"); outFile.write(Integer.toString(a + b)); outFile.close(); } catch (IOException e) { System.out.println("IO error"); } } } </lang>

C#

<lang csharp> using System.IO;

class plus { public static void Main(string[] args) { int a,b; { StreamReader reader = new StreamReader("plus.in"); a = int.Parse(reader.ReadLine()); b = int.Parse(reader.ReadLine()); StreamWriter writer = new StreamWriter("plus.out"); writer.WriteLine(a+b); writer.Close(); } } } </lang>

Scheme

<lang scheme> (write (+ (read) (read))) </lang>

Python (console)

<lang python> r = raw_input().split() print int(r[0]) + int(r[1]) </lang>

Python (file)

<lang python> fin = open("input.txt", "r") fout = open("output.txt","w") r = fin.readline().split() fout.write(str(int(r[0]) + int(r[1]))) </lang>

Haskell

<lang text> import Control.Monad

main = liftM2 (+) readLn readLn >>= print </lang>

Ruby

<lang ruby> puts gets.split(/\s+/).map{|x| x.to_i}.inject{|sum, x| sum + x} </lang>