Zeckendorf arithmetic

From Rosetta Code
Task
Zeckendorf arithmetic
You are encouraged to solve this task according to the task description, using any language you may know.

This task is a total immersion zeckendorf task; using decimal numbers will attract serious disapprobation.

The task is to implement addition, subtraction, multiplication, and division using Zeckendorf number representation. Optionally provide decrement, increment and comparitive operation functions.

Addition

Like binary 1 + 1 = 10, note carry 1 left. There the similarity ends. 10 + 10 = 101, note carry 1 left and 1 right. 100 + 100 = 1001, note carry 1 left and 2 right, this is the general case.

Occurrences of 11 must be changed to 100. Occurrences of 111 may be changed from the right by replacing 11 with 100, or from the left converting 111 to 100 + 100;

Subtraction

10 - 1 = 1. The general rule is borrow 1 right carry 1 left. eg:

  abcde
  10100 -
   1000
  _____
    100  borrow 1 from a leaves 100
  + 100  add the carry
  _____
   1001

A larger example:

  abcdef
  100100 -
    1000
  ______
  1*0100 borrow 1 from b
   + 100 add the carry
  ______
  1*1001

Sadly we borrowed 1 from b which didn't have it to lend. So now b borrows from a:

    1001
  + 1000 add the carry
    ____
   10100
Multiplication

Here you teach your computer its zeckendorf tables. eg. 101 * 1001:

  a = 1 * 101 = 101
  b = 10 * 101 = a + a = 10000
  c = 100 * 101 = b + a = 10101
  d = 1000 * 101 = c + b = 101010

  1001 = d + a therefore 101 * 1001 =
 
  101010
   + 101
  ______
 1000100
Division

Lets try 1000101 divided by 101, so we can use the same table used for multiplication.

  1000101 -
   101010 subtract d (1000 * 101)
  _______
     1000 -
      101 b and c are too large to subtract, so subtract a
     ____
        1 so 1000101 divided by 101 is d + a (1001) remainder 1

Efficient algorithms for Zeckendorf arithmetic is interesting. The sections on addition and subtraction are particularly relevant for this task.

C++[edit]

Works with: C++11
// For a class N which implements Zeckendorf numbers:
// I define an increment operation ++()
// I define a comparison operation <=(other N)
// I define an addition operation +=(other N)
// I define a subtraction operation -=(other N)
// Nigel Galloway October 28th., 2012
#include <iostream>
enum class zd {N00,N01,N10,N11};
class N {
private:
int dVal = 0, dLen;
void _a(int i) {
for (;; i++) {
if (dLen < i) dLen = i;
switch ((zd)((dVal >> (i*2)) & 3)) {
case zd::N00: case zd::N01: return;
case zd::N10: if (((dVal >> ((i+1)*2)) & 1) != 1) return;
dVal += (1 << (i*2+1)); return;
case zd::N11: dVal &= ~(3 << (i*2)); _b((i+1)*2);
}}}
void _b(int pos) {
if (pos == 0) {++*this; return;}
if (((dVal >> pos) & 1) == 0) {
dVal += 1 << pos;
_a(pos/2);
if (pos > 1) _a((pos/2)-1);
} else {
dVal &= ~(1 << pos);
_b(pos + 1);
_b(pos - ((pos > 1)? 2:1));
}}
void _c(int pos) {
if (((dVal >> pos) & 1) == 1) {dVal &= ~(1 << pos); return;}
_c(pos + 1);
if (pos > 0) _b(pos - 1); else ++*this;
return;
}
public:
N(char const* x = "0") {
int i = 0, q = 1;
for (; x[i] > 0; i++);
for (dLen = --i/2; i >= 0; i--) {dVal+=(x[i]-48)*q; q*=2;
}}
const N& operator++() {dVal += 1; _a(0); return *this;}
const N& operator+=(const N& other) {
for (int GN = 0; GN < (other.dLen + 1) * 2; GN++) if ((other.dVal >> GN) & 1 == 1) _b(GN);
return *this;
}
const N& operator-=(const N& other) {
for (int GN = 0; GN < (other.dLen + 1) * 2; GN++) if ((other.dVal >> GN) & 1 == 1) _c(GN);
for (;((dVal >> dLen*2) & 3) == 0 or dLen == 0; dLen--);
return *this;
}
const N& operator*=(const N& other) {
N Na = other, Nb = other, Nt, Nr;
for (int i = 0; i <= (dLen + 1) * 2; i++) {
if (((dVal >> i) & 1) > 0) Nr += Nb;
Nt = Nb; Nb += Na; Na = Nt;
}
return *this = Nr;
}
const bool operator<=(const N& other) const {return dVal <= other.dVal;}
friend std::ostream& operator<<(std::ostream&, const N&);
};
N operator "" N(char const* x) {return N(x);}
std::ostream &operator<<(std::ostream &os, const N &G) {
const static std::string dig[] {"00","01","10"}, dig1[] {"","1","10"};
if (G.dVal == 0) return os << "0";
os << dig1[(G.dVal >> (G.dLen*2)) & 3];
for (int i = G.dLen-1; i >= 0; i--) os << dig[(G.dVal >> (i*2)) & 3];
return os;
}
 

Testing[edit]

The following tests addtition:

int main(void) {
N G;
G = 10N;
G += 10N;
std::cout << G << std::endl;
G += 10N;
std::cout << G << std::endl;
G += 1001N;
std::cout << G << std::endl;
G += 1000N;
std::cout << G << std::endl;
G += 10101N;
std::cout << G << std::endl;
return 0;
}
Output:
101
1001
10101
100101
1010000

The following tests subtraction:

int main(void) {
N G;
G = 1000N;
G -= 101N;
std::cout << G << std::endl;
G = 10101010N;
G -= 1010101N;
std::cout << G << std::endl;
return 0;
}
Output:
1
1000000

The following tests multiplication:

 
int main(void) {
N G = 1001N;
G *= 101N;
std::cout << G << std::endl;
 
G = 101010N;
G += 101N;
std::cout << G << std::endl;
return 0;
}
Output:
1000100
1000100

C#[edit]

Translation of: Java
using System;
using System.Text;
 
namespace ZeckendorfArithmetic {
class Zeckendorf : IComparable<Zeckendorf> {
private static readonly string[] dig = { "00", "01", "10" };
private static readonly string[] dig1 = { "", "1", "10" };
 
private int dVal = 0;
private int dLen = 0;
 
public Zeckendorf() : this("0") {
// empty
}
 
public Zeckendorf(string x) {
int q = 1;
int i = x.Length - 1;
dLen = i / 2;
while (i >= 0) {
dVal += (x[i] - '0') * q;
q *= 2;
i--;
}
}
 
private void A(int n) {
int i = n;
while (true) {
if (dLen < i) dLen = i;
int j = (dVal >> (i * 2)) & 3;
switch (j) {
case 0:
case 1:
return;
case 2:
if (((dVal >> ((i + 1) * 2)) & 1) != 1) return;
dVal += 1 << (i * 2 + 1);
return;
case 3:
int temp = 3 << (i * 2);
temp ^= -1;
dVal = dVal & temp;
B((i + 1) * 2);
break;
}
i++;
}
}
 
private void B(int pos) {
if (pos == 0) {
Inc();
return;
}
if (((dVal >> pos) & 1) == 0) {
dVal += 1 << pos;
A(pos / 2);
if (pos > 1) A(pos / 2 - 1);
}
else {
int temp = 1 << pos;
temp ^= -1;
dVal = dVal & temp;
B(pos + 1);
B(pos - (pos > 1 ? 2 : 1));
}
}
 
private void C(int pos) {
if (((dVal >> pos) & 1) == 1) {
int temp = 1 << pos;
temp ^= -1;
dVal = dVal & temp;
return;
}
C(pos + 1);
if (pos > 0) {
B(pos - 1);
}
else {
Inc();
}
}
 
public Zeckendorf Inc() {
dVal++;
A(0);
return this;
}
 
public Zeckendorf Copy() {
Zeckendorf z = new Zeckendorf {
dVal = dVal,
dLen = dLen
};
return z;
}
 
public void PlusAssign(Zeckendorf other) {
for (int gn = 0; gn < (other.dLen + 1) * 2; gn++) {
if (((other.dVal >> gn) & 1) == 1) {
B(gn);
}
}
}
 
public void MinusAssign(Zeckendorf other) {
for (int gn = 0; gn < (other.dLen + 1) * 2; gn++) {
if (((other.dVal >> gn) & 1) == 1) {
C(gn);
}
}
while ((((dVal >> dLen * 2) & 3) == 0) || (dLen == 0)) {
dLen--;
}
}
 
public void TimesAssign(Zeckendorf other) {
Zeckendorf na = other.Copy();
Zeckendorf nb = other.Copy();
Zeckendorf nt;
Zeckendorf nr = new Zeckendorf();
for (int i = 0; i < (dLen + 1) * 2; i++) {
if (((dVal >> i) & 1) > 0) {
nr.PlusAssign(nb);
}
nt = nb.Copy();
nb.PlusAssign(na);
na = nt.Copy();
}
dVal = nr.dVal;
dLen = nr.dLen;
}
 
public int CompareTo(Zeckendorf other) {
return dVal.CompareTo(other.dVal);
}
 
public override string ToString() {
if (dVal == 0) {
return "0";
}
 
int idx = (dVal >> (dLen * 2)) & 3;
StringBuilder sb = new StringBuilder(dig1[idx]);
for (int i = dLen - 1; i >= 0; i--) {
idx = (dVal >> (i * 2)) & 3;
sb.Append(dig[idx]);
}
return sb.ToString();
}
}
 
class Program {
static void Main(string[] args) {
Console.WriteLine("Addition:");
Zeckendorf g = new Zeckendorf("10");
g.PlusAssign(new Zeckendorf("10"));
Console.WriteLine(g);
g.PlusAssign(new Zeckendorf("10"));
Console.WriteLine(g);
g.PlusAssign(new Zeckendorf("1001"));
Console.WriteLine(g);
g.PlusAssign(new Zeckendorf("1000"));
Console.WriteLine(g);
g.PlusAssign(new Zeckendorf("10101"));
Console.WriteLine(g);
Console.WriteLine();
 
Console.WriteLine("Subtraction:");
g = new Zeckendorf("1000");
g.MinusAssign(new Zeckendorf("101"));
Console.WriteLine(g);
g = new Zeckendorf("10101010");
g.MinusAssign(new Zeckendorf("1010101"));
Console.WriteLine(g);
Console.WriteLine();
 
Console.WriteLine("Multiplication:");
g = new Zeckendorf("1001");
g.TimesAssign(new Zeckendorf("101"));
Console.WriteLine(g);
g = new Zeckendorf("101010");
g.PlusAssign(new Zeckendorf("101"));
Console.WriteLine(g);
}
}
}
Output:
Addition:
101
1001
10101
100101
1010000

Subtraction:
1
1000000

Multiplication:
1000100
1000100

D[edit]

Translation of: Kotlin
import std.stdio;
 
int inv(int a) {
return a ^ -1;
}
 
class Zeckendorf {
private int dVal;
private int dLen;
 
private void a(int n) {
auto i = n;
while (true) {
if (dLen < i) dLen = i;
auto j = (dVal >> (i * 2)) & 3;
switch(j) {
case 0:
case 1:
return;
case 2:
if (((dVal >> ((i + 1) * 2)) & 1) != 1) return;
dVal += 1 << (i * 2 + 1);
return;
case 3:
dVal = dVal & (3 << (i * 2)).inv();
b((i + 1) * 2);
break;
default:
assert(false);
}
i++;
}
}
 
private void b(int pos) {
if (pos == 0) {
this++;
return;
}
if (((dVal >> pos) & 1) == 0) {
dVal += 1 << pos;
a(pos / 2);
if (pos > 1) a(pos / 2 - 1);
} else {
dVal = dVal & (1 << pos).inv();
b(pos + 1);
b(pos - (pos > 1 ? 2 : 1));
}
}
 
private void c(int pos) {
if (((dVal >> pos) & 1) == 1) {
dVal = dVal & (1 << pos).inv();
return;
}
c(pos + 1);
if (pos > 0) {
b(pos - 1);
} else {
++this;
}
}
 
this(string x = "0") {
int q = 1;
int i = x.length - 1;
dLen = i / 2;
while (i >= 0) {
dVal += (x[i] - '0') * q;
q *= 2;
i--;
}
}
 
auto opUnary(string op : "++")() {
dVal += 1;
a(0);
return this;
}
 
void opOpAssign(string op : "+")(Zeckendorf rhs) {
foreach (gn; 0..(rhs.dLen + 1) * 2) {
if (((rhs.dVal >> gn) & 1) == 1) {
b(gn);
}
}
}
 
void opOpAssign(string op : "-")(Zeckendorf rhs) {
foreach (gn; 0..(rhs.dLen + 1) * 2) {
if (((rhs.dVal >> gn) & 1) == 1) {
c(gn);
}
}
while ((((dVal >> dLen * 2) & 3) == 0) || (dLen == 0)) {
dLen--;
}
}
 
void opOpAssign(string op : "*")(Zeckendorf rhs) {
auto na = rhs.dup;
auto nb = rhs.dup;
Zeckendorf nt;
auto nr = "0".Z;
foreach (i; 0..(dLen + 1) * 2) {
if (((dVal >> i) & 1) > 0) nr += nb;
nt = nb.dup;
nb += na;
na = nt.dup;
}
dVal = nr.dVal;
dLen = nr.dLen;
}
 
void toString(scope void delegate(const(char)[]) sink) const {
if (dVal == 0) {
sink("0");
return;
}
sink(dig1[(dVal >> (dLen * 2)) & 3]);
foreach_reverse (i; 0..dLen) {
sink(dig[(dVal >> (i * 2)) & 3]);
}
}
 
Zeckendorf dup() {
auto z = "0".Z;
z.dVal = dVal;
z.dLen = dLen;
return z;
}
 
enum dig = ["00", "01", "10"];
enum dig1 = ["", "1", "10"];
}
 
auto Z(string val) {
return new Zeckendorf(val);
}
 
void main() {
writeln("Addition:");
auto g = "10".Z;
g += "10".Z;
writeln(g);
g += "10".Z;
writeln(g);
g += "1001".Z;
writeln(g);
g += "1000".Z;
writeln(g);
g += "10101".Z;
writeln(g);
writeln();
 
writeln("Subtraction:");
g = "1000".Z;
g -= "101".Z;
writeln(g);
g = "10101010".Z;
g -= "1010101".Z;
writeln(g);
writeln();
 
writeln("Multiplication:");
g = "1001".Z;
g *= "101".Z;
writeln(g);
g = "101010".Z;
g += "101".Z;
writeln(g);
}
Output:
Addition:
101
1001
10101
100101
1010000

Subtraction:
1
1000000

Multiplication:
1000100
1000100

Elena[edit]

Translation of: C++

ELENA 3.4 :

import extensions.
 
const dig = ("00","01","10").
const dig1 = ("","1","10").
 
sealed struct ZeckendorfNumber :: BaseNumber
{
int dVal.
int dLen.
 
clone
= ZeckendorfNumber newInternal(dVal,dLen).
 
cast n(literal s)
[
int i := s length - 1.
int q := 1.
 
dLen := i / 2.
dVal := 0.
 
while (i >= 0)
[
dVal += ((intConvertor convert(s[i]) - 48) * q).
q *= 2.
 
i -= 1.
].
]
 
internal readContent(ref<int> val, ref<int> len)
[
val value := dVal.
len value := dLen.
]
 
sealed private a(int n)
[
int i := n.
 
while (true)
[
if (dLen < i)
[
dLen := i.
].
 
((dVal >> (i * 2)) && 3) =>
0 [ ^ self ];
1 [ ^ self ];
2 [
ifnot ((dVal >> ((i + 1) * 2)) allMask:1)
[
^ self.
].
 
dVal += (1 << (i*2 + 1)).
^ self.
];
3 [
dVal := dVal && ((3 << i*2) inverted).
 
self b((i+1)*2).
].
 
i += 1.
].
]
 
inc
[
dVal += 1.
self a(0).
]
 
private b(int pos)
[
if (pos == 0) [ ^ self inc ].
 
ifnot((dVal >> pos) allMask:1)
[
dVal += (1 << pos).
self a(pos / 2).
if (pos > 1) [ self a((pos / 2) - 1) ]
];
[
dVal := dVal && (1 << pos) inverted.
self b(pos + 1).
self b(pos - (pos > 1) iif(2,1)).
].
]
 
private c(IntNumber pos)
[
if ((dVal >> pos) allMask:1)
[
dVal := dVal && (1 << pos) inverted.
 
^ self
].
 
self c(pos + 1).
 
if (pos > 0)
[
self b(pos - 1).
];
[
self inc.
]
]
 
internal constructor sum(ZeckendorfNumber n, ZeckendorfNumber m)
[
int mVal := 0.
int mLen := 0.
 
n readContent(&dVal, &dLen).
m readContent(&mVal, &mLen).
 
0 till((mLen + 1) * 2) do(:GN)
[
if (mVal shiftRight:GN; allMask:1)
[
self b(GN).
].
].
]
 
internal constructor difference(ZeckendorfNumber n, ZeckendorfNumber m)
[
int mVal := 0.
int mLen := 0.
 
n readContent(&dVal, &dLen).
m readContent(&mVal, &mLen).
 
0 till((mLen + 1) * 2) do(:GN)
[
if (mVal shiftRight:GN; allMask:1)
[
self c(GN).
].
].
 
while ((((dVal >> (dLen*2)) && 3) == 0) || (dLen == 0))
[
dLen -= 1.
].
]
 
internal constructor product(ZeckendorfNumber n, ZeckendorfNumber m)
[
n readContent(&dVal, &dLen).
 
var Na := m.
var Nb := m.
var Nr := 0n.
var Nt := 0n.
 
0 to((dLen + 1) * 2) do(:i)
[
if (((dVal shiftRight:i) && 1) > 0)
[
Nr += Nb
].
Nt := Nb.
Nb += Na.
Na := Nt.
].
 
Nr readContent(&dVal, &dLen).
]
 
internal constructor newInternal(int v, int l)
[
dVal := v.
dLen := l.
]
 
T<literal> literal
[
if (dVal == 0)
[ ^ "0". ].
 
literal s := dig1[(dVal >> (dLen * 2)) && 3].
int i := dLen - 1.
while (i >= 0)
[
s := s + dig[(dVal >> (i * 2)) && 3].
 
i-=1
].
 
^ s.
]
 
add(ZeckendorfNumber n)
= ZeckendorfNumber sum(self, n).
 
subtract(ZeckendorfNumber n)
= ZeckendorfNumber difference(self, n).
 
multiply(ZeckendorfNumber n)
= ZeckendorfNumber product(self, n).
}
 
public program
[
console printLine("Addition:").
var n := 10n.
 
n += 10n.
console printLine(n).
n += 10n.
console printLine(n).
n += 1001n.
console printLine(n).
n += 1000n.
console printLine(n).
n += 10101n.
console printLine(n).
 
console printLine("Subtraction:").
n := 1000n.
n -= 101n.
console printLine(n).
n := 10101010n.
n -= 1010101n.
console printLine(n).
 
console printLine("Multiplication:").
n := 1001n.
n *= 101n.
console printLine(n).
n := 101010n.
n += 101n.
console printLine(n).
]
Output:
Addition:
101
1001
10101
100101
1010000
Subtraction:
1
1000000
Multiplication:
1000100
1000100

Go[edit]

Translation of: Kotlin
package main
 
import (
"fmt"
"strings"
)
 
var (
dig = [3]string{"00", "01", "10"}
dig1 = [3]string{"", "1", "10"}
)
 
type Zeckendorf struct{ dVal, dLen int }
 
func NewZeck(x string) *Zeckendorf {
z := new(Zeckendorf)
if x == "" {
x = "0"
}
q := 1
i := len(x) - 1
z.dLen = i / 2
for ; i >= 0; i-- {
z.dVal += int(x[i]-'0') * q
q *= 2
}
return z
}
 
func (z *Zeckendorf) a(i int) {
for ; ; i++ {
if z.dLen < i {
z.dLen = i
}
j := (z.dVal >> uint(i*2)) & 3
switch j {
case 0, 1:
return
case 2:
if ((z.dVal >> (uint(i+1) * 2)) & 1) != 1 {
return
}
z.dVal += 1 << uint(i*2+1)
return
case 3:
z.dVal &= ^(3 << uint(i*2))
z.b((i + 1) * 2)
}
}
}
 
func (z *Zeckendorf) b(pos int) {
if pos == 0 {
z.Inc()
return
}
if ((z.dVal >> uint(pos)) & 1) == 0 {
z.dVal += 1 << uint(pos)
z.a(pos / 2)
if pos > 1 {
z.a(pos/2 - 1)
}
} else {
z.dVal &= ^(1 << uint(pos))
z.b(pos + 1)
temp := 1
if pos > 1 {
temp = 2
}
z.b(pos - temp)
}
}
 
func (z *Zeckendorf) c(pos int) {
if ((z.dVal >> uint(pos)) & 1) == 1 {
z.dVal &= ^(1 << uint(pos))
return
}
z.c(pos + 1)
if pos > 0 {
z.b(pos - 1)
} else {
z.Inc()
}
}
 
func (z *Zeckendorf) Inc() {
z.dVal++
z.a(0)
}
 
func (z1 *Zeckendorf) PlusAssign(z2 *Zeckendorf) {
for gn := 0; gn < (z2.dLen+1)*2; gn++ {
if ((z2.dVal >> uint(gn)) & 1) == 1 {
z1.b(gn)
}
}
}
 
func (z1 *Zeckendorf) MinusAssign(z2 *Zeckendorf) {
for gn := 0; gn < (z2.dLen+1)*2; gn++ {
if ((z2.dVal >> uint(gn)) & 1) == 1 {
z1.c(gn)
}
}
 
for z1.dLen > 0 && ((z1.dVal>>uint(z1.dLen*2))&3) == 0 {
z1.dLen--
}
}
 
func (z1 *Zeckendorf) TimesAssign(z2 *Zeckendorf) {
na := z2.Copy()
nb := z2.Copy()
nr := new(Zeckendorf)
for i := 0; i <= (z1.dLen+1)*2; i++ {
if ((z1.dVal >> uint(i)) & 1) > 0 {
nr.PlusAssign(nb)
}
nt := nb.Copy()
nb.PlusAssign(na)
na = nt.Copy()
}
z1.dVal = nr.dVal
z1.dLen = nr.dLen
}
 
func (z *Zeckendorf) Copy() *Zeckendorf {
return &Zeckendorf{z.dVal, z.dLen}
}
 
func (z1 *Zeckendorf) Compare(z2 *Zeckendorf) int {
switch {
case z1.dVal < z2.dVal:
return -1
case z1.dVal > z2.dVal:
return 1
default:
return 0
}
}
 
func (z *Zeckendorf) String() string {
if z.dVal == 0 {
return "0"
}
var sb strings.Builder
sb.WriteString(dig1[(z.dVal>>uint(z.dLen*2))&3])
for i := z.dLen - 1; i >= 0; i-- {
sb.WriteString(dig[(z.dVal>>uint(i*2))&3])
}
return sb.String()
}
 
func main() {
fmt.Println("Addition:")
g := NewZeck("10")
g.PlusAssign(NewZeck("10"))
fmt.Println(g)
g.PlusAssign(NewZeck("10"))
fmt.Println(g)
g.PlusAssign(NewZeck("1001"))
fmt.Println(g)
g.PlusAssign(NewZeck("1000"))
fmt.Println(g)
g.PlusAssign(NewZeck("10101"))
fmt.Println(g)
 
fmt.Println("\nSubtraction:")
g = NewZeck("1000")
g.MinusAssign(NewZeck("101"))
fmt.Println(g)
g = NewZeck("10101010")
g.MinusAssign(NewZeck("1010101"))
fmt.Println(g)
 
fmt.Println("\nMultiplication:")
g = NewZeck("1001")
g.TimesAssign(NewZeck("101"))
fmt.Println(g)
g = NewZeck("101010")
g.PlusAssign(NewZeck("101"))
fmt.Println(g)
}
Output:
Addition:
101
1001
10101
100101
1010000

Subtraction:
1
1000000

Multiplication:
1000100
1000100

Java[edit]

Translation of: Kotlin
Works with: Java version 9
import java.util.List;
 
public class Zeckendorf implements Comparable<Zeckendorf> {
private static List<String> dig = List.of("00", "01", "10");
private static List<String> dig1 = List.of("", "1", "10");
 
private String x;
private int dVal = 0;
private int dLen = 0;
 
public Zeckendorf() {
this("0");
}
 
public Zeckendorf(String x) {
this.x = x;
 
int q = 1;
int i = x.length() - 1;
dLen = i / 2;
while (i >= 0) {
dVal += (x.charAt(i) - '0') * q;
q *= 2;
i--;
}
}
 
private void a(int n) {
int i = n;
while (true) {
if (dLen < i) dLen = i;
int j = (dVal >> (i * 2)) & 3;
switch (j) {
case 0:
case 1:
return;
case 2:
if (((dVal >> ((i + 1) * 2)) & 1) != 1) return;
dVal += 1 << (i * 2 + 1);
return;
case 3:
int temp = 3 << (i * 2);
temp ^= -1;
dVal = dVal & temp;
b((i + 1) * 2);
break;
}
i++;
}
}
 
private void b(int pos) {
if (pos == 0) {
Zeckendorf thiz = this;
thiz.inc();
return;
}
if (((dVal >> pos) & 1) == 0) {
dVal += 1 << pos;
a(pos / 2);
if (pos > 1) a(pos / 2 - 1);
} else {
int temp = 1 << pos;
temp ^= -1;
dVal = dVal & temp;
b(pos + 1);
b(pos - (pos > 1 ? 2 : 1));
}
}
 
private void c(int pos) {
if (((dVal >> pos) & 1) == 1) {
int temp = 1 << pos;
temp ^= -1;
dVal = dVal & temp;
return;
}
c(pos + 1);
if (pos > 0) {
b(pos - 1);
} else {
Zeckendorf thiz = this;
thiz.inc();
}
}
 
public Zeckendorf inc() {
dVal++;
a(0);
return this;
}
 
public void plusAssign(Zeckendorf other) {
for (int gn = 0; gn < (other.dLen + 1) * 2; gn++) {
if (((other.dVal >> gn) & 1) == 1) {
b(gn);
}
}
}
 
public void minusAssign(Zeckendorf other) {
for (int gn = 0; gn < (other.dLen + 1) * 2; gn++) {
if (((other.dVal >> gn) & 1) == 1) {
c(gn);
}
}
while ((((dVal >> dLen * 2) & 3) == 0) || (dLen == 0)) {
dLen--;
}
}
 
public void timesAssign(Zeckendorf other) {
Zeckendorf na = other.copy();
Zeckendorf nb = other.copy();
Zeckendorf nt;
Zeckendorf nr = new Zeckendorf();
for (int i = 0; i < (dLen + 1) * 2; i++) {
if (((dVal >> i) & 1) > 0) {
nr.plusAssign(nb);
}
nt = nb.copy();
nb.plusAssign(na);
na = nt.copy();
}
dVal = nr.dVal;
dLen = nr.dLen;
}
 
private Zeckendorf copy() {
Zeckendorf z = new Zeckendorf();
z.dVal = dVal;
z.dLen = dLen;
return z;
}
 
@Override
public int compareTo(Zeckendorf other) {
return ((Integer) dVal).compareTo(other.dVal);
}
 
@Override
public String toString() {
if (dVal == 0) {
return "0";
}
 
int idx = (dVal >> (dLen * 2)) & 3;
StringBuilder stringBuilder = new StringBuilder(dig1.get(idx));
for (int i = dLen - 1; i >= 0; i--) {
idx = (dVal >> (i * 2)) & 3;
stringBuilder.append(dig.get(idx));
}
return stringBuilder.toString();
}
 
public static void main(String[] args) {
System.out.println("Addition:");
Zeckendorf g = new Zeckendorf("10");
g.plusAssign(new Zeckendorf("10"));
System.out.println(g);
g.plusAssign(new Zeckendorf("10"));
System.out.println(g);
g.plusAssign(new Zeckendorf("1001"));
System.out.println(g);
g.plusAssign(new Zeckendorf("1000"));
System.out.println(g);
g.plusAssign(new Zeckendorf("10101"));
System.out.println(g);
 
System.out.println("\nSubtraction:");
g = new Zeckendorf("1000");
g.minusAssign(new Zeckendorf("101"));
System.out.println(g);
g = new Zeckendorf("10101010");
g.minusAssign(new Zeckendorf("1010101"));
System.out.println(g);
 
System.out.println("\nMultiplication:");
g = new Zeckendorf("1001");
g.timesAssign(new Zeckendorf("101"));
System.out.println(g);
g = new Zeckendorf("101010");
g.plusAssign(new Zeckendorf("101"));
System.out.println(g);
}
}
Output:
Addition:
101
1001
10101
100101
1010000

Subtraction:
1
1000000

Multiplication:
1000100
1000100

Kotlin[edit]

Translation of: C++
// version 1.1.51
 
class Zeckendorf(x: String = "0") : Comparable<Zeckendorf> {
 
var dVal = 0
var dLen = 0
 
private fun a(n: Int) {
var i = n
while (true) {
if (dLen < i) dLen = i
val j = (dVal shr (i * 2)) and 3
when (j) {
0, 1 -> return
 
2 -> {
if (((dVal shr ((i + 1) * 2)) and 1) != 1) return
dVal += 1 shl (i * 2 + 1)
return
}
 
3 -> {
dVal = dVal and (3 shl (i * 2)).inv()
b((i + 1) * 2)
}
}
i++
}
}
 
private fun b(pos: Int) {
if (pos == 0) {
var thiz = this
++thiz
return
}
if (((dVal shr pos) and 1) == 0) {
dVal += 1 shl pos
a(pos / 2)
if (pos > 1) a(pos / 2 - 1)
}
else {
dVal = dVal and (1 shl pos).inv()
b(pos + 1)
b(pos - (if (pos > 1) 2 else 1))
}
}
 
private fun c(pos: Int) {
if (((dVal shr pos) and 1) == 1) {
dVal = dVal and (1 shl pos).inv()
return
}
c(pos + 1)
if (pos > 0) b(pos - 1) else { var thiz = this; ++thiz }
}
 
init {
var q = 1
var i = x.length - 1
dLen = i / 2
while (i >= 0) {
dVal += (x[i] - '0').toInt() * q
q *= 2
i--
}
}
 
operator fun inc(): Zeckendorf {
dVal += 1
a(0)
return this
}
 
operator fun plusAssign(other: Zeckendorf) {
for (gn in 0 until (other.dLen + 1) * 2) {
if (((other.dVal shr gn) and 1) == 1) b(gn)
}
}
 
operator fun minusAssign(other: Zeckendorf) {
for (gn in 0 until (other.dLen + 1) * 2) {
if (((other.dVal shr gn) and 1) == 1) c(gn)
}
while ((((dVal shr dLen * 2) and 3) == 0) || (dLen == 0)) dLen--
}
 
operator fun timesAssign(other: Zeckendorf) {
var na = other.copy()
var nb = other.copy()
var nt: Zeckendorf
var nr = "0".Z
for (i in 0..(dLen + 1) * 2) {
if (((dVal shr i) and 1) > 0) nr += nb
nt = nb.copy()
nb += na
na = nt.copy()
}
dVal = nr.dVal
dLen = nr.dLen
}
 
override operator fun compareTo(other: Zeckendorf) = dVal.compareTo(other.dVal)
 
override fun toString(): String {
if (dVal == 0) return "0"
val sb = StringBuilder(dig1[(dVal shr (dLen * 2)) and 3])
for (i in dLen - 1 downTo 0) {
sb.append(dig[(dVal shr (i * 2)) and 3])
}
return sb.toString()
}
 
fun copy(): Zeckendorf {
val z = "0".Z
z.dVal = dVal
z.dLen = dLen
return z
}
 
companion object {
val dig = listOf("00", "01", "10")
val dig1 = listOf("", "1", "10")
}
}
 
val String.Z get() = Zeckendorf(this)
 
fun main(args: Array<String>) {
println("Addition:")
var g = "10".Z
g += "10".Z
println(g)
g += "10".Z
println(g)
g += "1001".Z
println(g)
g += "1000".Z
println(g)
g += "10101".Z
println(g)
println("\nSubtraction:")
g = "1000".Z
g -= "101".Z
println(g)
g = "10101010".Z
g -= "1010101".Z
println(g)
println("\nMultiplication:")
g = "1001".Z
g *= "101".Z
println(g)
g = "101010".Z
g += "101".Z
println(g)
}
Output:
Addition:
101
1001
10101
100101
1010000

Subtraction:
1
1000000

Multiplication:
1000100
1000100

Perl 6[edit]

This is a somewhat limited implementation of Zeckendorf arithmetic operators. They only handle positive integer values. There are no actual calculations, everything is done with string manipulations, so it doesn't matter what glyphs you use for 1 and 0.

Works with: rakudo version 2015.09

Implemented arithmetic operators:

 addition: +z
 subtraction: -z
 multiplication: *z
 division: /z (more of a divmod really)
 post increment: ++z
 post decrement: --z

Comparison operators:

 equal eqz
 not equal nez
 greater than gtz
 less than ltz
 
my $z1 = '1'; # glyph to use for a '1'
my $z0 = '0'; # glyph to use for a '0'
 
sub zorder($a) { ($z0 lt $z1) ?? $a !! $a.trans([$z0, $z1] => [$z1, $z0]) };
 
######## Zeckendorf comparison operators #########
 
# less than
sub infix:<ltz>($a, $b) { $a.&zorder lt $b.&zorder };
 
# greater than
sub infix:<gtz>($a, $b) { $a.&zorder gt $b.&zorder };
 
# equal
sub infix:<eqz>($a, $b) { $a eq $b };
 
# not equal
sub infix:<nez>($a, $b) { $a ne $b };
 
 
######## Operators for Zeckendorf arithmetic ########
 
# post increment
sub postfix:<++z>($a is rw) {
$a = ("$z0$z0"~$a).subst(/("$z0$z0")($z1+ %% $z0)?$/,
-> $/ { "$z0$z1" ~ ($1 ?? $z0 x $1.chars !! '') });
$a ~~ s/^$z0+//;
$a
}
 
# post decrement
sub postfix:<--z>($a is rw) {
$a.=subst(/$z1($z0*)$/,
-> $/ {$z0 ~ "$z1$z0" x $0.chars div 2 ~ $z1 x $0.chars mod 2});
$a ~~ s/^$z0+(.+)$/$0/;
$a
}
 
# addition
sub infix:<+z>($a is copy, $b is copy) { $a++z while $b--z nez $z0; $a };
 
# subtraction
sub infix:<-z>($a is copy, $b is copy) { $a--z while $b--z nez $z0; $a };
 
# multiplication
sub infix:<*z>($a, $b) {
return $z0 if $a eqz $z0 or $b eqz $z0;
return $a if $b eqz $z1;
return $b if $a eqz $z1;
my $c = $a;
my $d = $z1;
repeat {
my $e = $z0;
repeat { $c++z; $e++z } until $e eqz $a;
$d++z;
} until $d eqz $b;
$c
};
 
# division (really more of a div mod)
sub infix:</z>($a is copy, $b is copy) {
fail "Divide by zero" if $b eqz $z0;
return $a if $a eqz $z0 or $b eqz $z1;
my $c = $z0;
repeat {
my $d = $b +z ($z1 ~ $z0);
$c++z;
$a--z while $d--z nez $z0
} until $a ltz $b;
$c ~= " remainder $a" if $a nez $z0;
$c
};
 
 
###################### Testing ######################
 
# helper sub to translate constants into the particular glyphs you used
sub z($a) { $a.trans([<1 0>] => [$z1, $z0]) };
 
say "Using the glyph '$z1' for 1 and '$z0' for 0\n";
 
my $fmt = "%-22s = %15s  %s\n";
 
my $zeck = $z1;
 
printf( $fmt, "$zeck++z", $zeck++z, '# increment' ) for 1 .. 10;
 
printf $fmt, "$zeck +z {z('1010')}", $zeck +z= z('1010'), '# addition';
 
printf $fmt, "$zeck -z {z('100')}", $zeck -z= z('100'), '# subtraction';
 
printf $fmt, "$zeck *z {z('100101')}", $zeck *z= z('100101'), '# multiplication';
 
printf $fmt, "$zeck /z {z('100')}", $zeck /z= z('100'), '# division';
 
printf( $fmt, "$zeck--z", $zeck--z, '# decrement' ) for 1 .. 5;
 
printf $fmt, "$zeck *z {z('101001')}", $zeck *z= z('101001'), '# multiplication';
 
printf $fmt, "$zeck /z {z('100')}", $zeck /z= z('100'), '# division';

Testing Output

This example is incorrect. Please fix the code and remove this message.
Details: 10100+1010 <> 100101, see talk page
Using the glyph '1' for 1 and '0' for 0

1++z                   =              10  # increment
10++z                  =             100  # increment
100++z                 =             101  # increment
101++z                 =            1000  # increment
1000++z                =            1001  # increment
1001++z                =            1010  # increment
1010++z                =           10000  # increment
10000++z               =           10001  # increment
10001++z               =           10010  # increment
10010++z               =           10100  # increment
10100 +z 1010          =          100101  # addition
100101 -z 100          =          100010  # subtraction
100010 *z 100101       =    100001000001  # multiplication
100001000001 /z 100    =       101010001  # division
101010001--z           =       101010000  # decrement
101010000--z           =       101001010  # decrement
101001010--z           =       101001001  # decrement
101001001--z           =       101001000  # decrement
101001000--z           =       101000101  # decrement
101000101 *z 101001    = 101010000010101  # multiplication
101010000010101 /z 100 = 1001010001001 remainder 10  # division

Output using 'X' for 1 and 'O' for 0:

Using the glyph 'X' for 1 and 'O' for 0

X++z                   =              XO  # increment
XO++z                  =             XOO  # increment
XOO++z                 =             XOX  # increment
XOX++z                 =            XOOO  # increment
XOOO++z                =            XOOX  # increment
XOOX++z                =            XOXO  # increment
XOXO++z                =           XOOOO  # increment
XOOOO++z               =           XOOOX  # increment
XOOOX++z               =           XOOXO  # increment
XOOXO++z               =           XOXOO  # increment
XOXOO +z XOXO          =          XOOXOX  # addition
XOOXOX -z XOO          =          XOOOXO  # subtraction
XOOOXO *z XOOXOX       =    XOOOOXOOOOOX  # multiplication
XOOOOXOOOOOX /z XOO    =       XOXOXOOOX  # division
XOXOXOOOX--z           =       XOXOXOOOO  # decrement
XOXOXOOOO--z           =       XOXOOXOXO  # decrement
XOXOOXOXO--z           =       XOXOOXOOX  # decrement
XOXOOXOOX--z           =       XOXOOXOOO  # decrement
XOXOOXOOO--z           =       XOXOOOXOX  # decrement
XOXOOOXOX *z XOXOOX    = XOXOXOOOOOXOXOX  # multiplication
XOXOXOOOOOXOXOX /z XOO = XOOXOXOOOXOOX remainder XO  # division

Phix[edit]

Uses a binary representation of Zeckendorf numbers, eg decimal 11 is stored as 0b10100, ie meaning 8+3, but actually 20 in decimal.
As such, they can be directly compared using the standard comparison operators, and printed quite trivially just by using the %b format.
They are however (and not all that surprisingly) pulled apart into individual bits for addition/subtraction, etc.
Does not handle negative numbers or anything >139583862445 (-ve probably doable but messy, >1.4e12 requires a total rewrite, probably using string representation).

sequence fib = {1,1}
 
function zeckendorf(atom n)
-- Same as [[Zeckendorf_number_representation#Phix]]
atom r = 0
while fib[$]<n do
fib &= fib[$] + fib[$-1]
end while
integer k = length(fib)
while k>2 and n<fib[k] do
k -= 1
end while
for i=k to 2 by -1 do
integer c = n>=fib[i]
r += r+c
n -= c*fib[i]
end for
return r
end function
 
function decimal(object z)
-- Convert Zeckendorf number(s) to decimal
atom dec = 0, bit = 2
if sequence(z) then
for i=1 to length(z) do
z[i] = decimal(z[i])
end for
return z
end if
while z do
if and_bits(z,1) then
dec += fib[bit]
end if
bit += 1
if bit>length(fib) then
fib &= fib[$] + fib[$-1]
end if
z = floor(z/2)
end while
return dec
end function
 
function to_bits(integer x)
-- Simplified copy of int_to_bits(), but in reverse order,
-- and +ve only but (also only) as many bits as needed, and
-- ensures there are *two* trailing 0 (most significant)
sequence bits = {}
if x<0 then ?9/0 end if -- sanity/avoid infinite loop
while 1 do
bits &= remainder(x,2)
if x=0 then exit end if
x = floor(x/2)
end while
bits &= 0 -- (since eg 101+101 -> 10000)
return bits
end function
 
function to_bits2(integer a,b)
-- Apply to_bits() to a and b, and pad to the same length
sequence sa = to_bits(a), sb = to_bits(b)
integer diff = length(sa)-length(sb)
if diff!=0 then
if diff<0 then sa &= repeat(0,-diff)
else sb &= repeat(0,+diff)
end if
end if
return {sa,sb}
end function
 
function to_int(sequence bits)
-- Copy of bits_to_int(), but in reverse order (lsb last)
atom val = 0, p = 1
for i=length(bits) to 1 by -1 do
if bits[i] then
val += p
end if
p += p
end for
return val
end function
 
function zstr(object z)
if sequence(z) then
for i=1 to length(z) do
z[i] = zstr(z[i])
end for
return z
end if
return sprintf("%b",z)
end function
 
function rep(sequence res, integer ds, sequence was, wth)
-- helper for cleanup, validates replacements
integer de = ds+length(was)-1
if res[ds..de]!=was then ?9/0 end if
if length(was)!=length(wth) then ?9/0 end if
res[ds..de] = wth
return res
end function
 
function zcleanup(sequence res)
-- (shared by zadd and zsub)
integer l = length(res)
-- first stage, left to right, {020x -> 100x', 030x -> 110x', 021x->110x, 012x->101x}
for i=1 to l-3 do
switch res[i..i+2]
case {0,2,0}: res[i..i+2] = {1,0,0} res[i+3] += 1
case {0,3,0}: res[i..i+2] = {1,1,0} res[i+3] += 1
case {0,2,1}: res[i..i+2] = {1,1,0}
case {0,1,2}: res[i..i+2] = {1,0,1}
end switch
end for
-- first stage cleanup
if l>1 then
if res[l-1]=3 then res = rep(res,l-2,{0,3,0},{1,1,1}) -- 030 -> 111
elsif res[l-1]=2 then
if res[l-2]=0 then res = rep(res,l-2,{0,2,0},{1,0,1}) -- 020 -> 101
else res = rep(res,l-3,{0,1,2,0},{1,0,1,0}) -- 0120 -> 1010
end if
end if
end if
if res[l]=3 then res = rep(res,l-1,{0,3},{1,1}) -- 03 -> 11
elsif res[l]=2 then
if res[l-1]=0 then res = rep(res,l-1,{0,2},{1,0}) -- 02 -> 10
else res = rep(res,l-2,{0,1,2},{1,0,1}) -- 012 -> 101
end if
end if
-- second stage, pass 1, right to left, 011 -> 100
for i=length(res)-2 to 1 by -1 do
if res[i..i+2]={0,1,1} then res[i..i+2] = {1,0,0} end if
end for
-- second stage, pass 2, left to right, 011 -> 100
for i=1 to length(res)-2 do
if res[i..i+2]={0,1,1} then res[i..i+2] = {1,0,0} end if
end for
return to_int(res)
end function
 
function zadd(integer a, b)
sequence {sa,sb} = to_bits2(a,b)
return zcleanup(reverse(sq_add(sa,sb)))
end function
 
function zinc(integer a)
return zadd(a,0b1)
end function
 
function zsub(integer a, b)
sequence {sa,sb} = to_bits2(a,b)
sequence res = reverse(sq_sub(sa,sb))
-- (/not/ combined with the first pass of the add routine!)
for i=1 to length(res)-2 do
switch res[i..i+2] do
case {1, 0, 0}: res[i..i+2] = {0,1,1}
case {1,-1, 0}: res[i..i+2] = {0,0,1}
case {1,-1, 1}: res[i..i+2] = {0,0,2}
case {1, 0,-1}: res[i..i+2] = {0,1,0}
case {2, 0, 0}: res[i..i+2] = {1,1,1}
case {2,-1, 0}: res[i..i+2] = {1,0,1}
case {2,-1, 1}: res[i..i+2] = {1,0,2}
case {2, 0,-1}: res[i..i+2] = {1,1,0}
end switch
end for
-- copied from PicoLisp: {1,-1} -> {0,1} and {2,-1} -> {1,1}
for i=1 to length(res)-1 do
switch res[i..i+1] do
case {1,-1}: res[i..i+1] = {0,1}
case {2,-1}: res[i..i+1] = {1,1}
end switch
end for
if find(-1,res) then ?9/0 end if -- sanity check
return zcleanup(res)
end function
 
function zdec(integer a)
return zsub(a,0b1)
end function
 
function zmul(integer a, b)
integer res = 0
sequence mult = {a,zadd(a,a)} -- (as per task desc)
integer bits = 2
while bits<b do
mult = append(mult,zadd(mult[$],mult[$-1]))
bits *= 2
end while
integer bit = 1
while b do
if and_bits(b,1) then
res = zadd(res,mult[bit])
end if
b = floor(b/2)
bit += 1
end while
return res
end function
 
function zdiv(integer a, b)
integer res = 0
sequence mult = {b,zadd(b,b)}
integer bits = 2
while mult[$]<a do
mult = append(mult,zadd(mult[$],mult[$-1]))
bits *= 2
end while
for i=length(mult) to 1 by -1 do
integer mi = mult[i]
if mi<=a then
res = zadd(res,bits)
a = zsub(a,mi)
if a=0 then exit end if
end if
bits = floor(bits/2)
end for
return {res,a} -- (a is the remainder)
end function
 
for i=0 to 20 do
integer zi = zeckendorf(i)
atom d = decimal(zi)
printf(1,"%2d: %7b (%d)\n",{i,zi,d})
end for
 
procedure test(atom a, string op, atom b, object res, string expected)
string zres = iff(atom(res)?zstr(res):join(zstr(res)," rem ")),
dres = sprintf(iff(atom(res)?"%d":"%d rem %d"),decimal(res)),
aka = sprintf("aka %d %s %d = %s",{decimal(a),op,decimal(b),dres}),
ok = iff(zres=expected?"":" *** ERROR ***!!")
printf(1,"%s %s %s = %s, %s %s\n",{zstr(a),op,zstr(b),zres,aka,ok})
end procedure
 
test(0b0,"+",0b0,zadd(0b0,0b0),"0")
test(0b101,"+",0b101,zadd(0b101,0b101),"10000")
test(0b10100,"-",0b1000,zsub(0b10100,0b1000),"1001")
test(0b100100,"-",0b1000,zsub(0b100100,0b1000),"10100")
test(0b1001,"*",0b101,zmul(0b1001,0b101),"1000100")
test(0b1000101,"/",0b101,zdiv(0b1000101,0b101),"1001 rem 1")
 
test(0b10,"+",0b10,zadd(0b10,0b10),"101")
test(0b101,"+",0b10,zadd(0b101,0b10),"1001")
test(0b1001,"+",0b1001,zadd(0b1001,0b1001),"10101")
test(0b10101,"+",0b1000,zadd(0b10101,0b1000),"100101")
test(0b100101,"+",0b10101,zadd(0b100101,0b10101),"1010000")
test(0b1000,"-",0b101,zsub(0b1000,0b101),"1")
test(0b10101010,"-",0b1010101,zsub(0b10101010,0b1010101),"1000000")
test(0b1001,"*",0b101,zmul(0b1001,0b101),"1000100")
test(0b101010,"+",0b101,zadd(0b101010,0b101),"1000100")
 
test(0b10100,"+",0b1010,zadd(0b10100,0b1010),"101000")
test(0b101000,"-",0b1010,zsub(0b101000,0b1010),"10100")
 
test(0b100010,"*",0b100101,zmul(0b100010,0b100101),"100001000001")
test(0b100001000001,"/",0b100,zdiv(0b100001000001,0b100),"101010001 rem 0")
test(0b101000101,"*",0b101001,zmul(0b101000101,0b101001),"101010000010101")
test(0b101010000010101,"/",0b100,zdiv(0b101010000010101,0b100),"1001010001001 rem 10")
 
test(0b10100010010100,"+",0b1001000001,zadd(0b10100010010100,0b1001000001),"100000000010101")
test(0b10100010010100,"-",0b1001000001,zsub(0b10100010010100,0b1001000001),"10010001000010")
test(0b10000,"*",0b1001000001,zmul(0b10000,0b1001000001),"10100010010100")
test(0b1010001010000001001,"/",0b100000000100000,zdiv(0b1010001010000001001,0b100000000100000),"10001 rem 10100001010101")
 
test(0b10100,"+",0b1010,zadd(0b10100,0b1010),"101000")
test(0b10100,"-",0b1010,zsub(0b10100,0b1010),"101")
test(0b10100,"*",0b1010,zmul(0b10100,0b1010),"101000001")
test(0b10100,"/",0b1010,zdiv(0b10100,0b1010),"1 rem 101")
integer m = zmul(0b10100,0b1010)
test(m,"/",0b1010,zdiv(m,0b1010),"10100 rem 0")
Output:
 0:       0 (0)
 1:       1 (1)
 2:      10 (2)
 3:     100 (3)
 4:     101 (4)
 5:    1000 (5)
 6:    1001 (6)
 7:    1010 (7)
 8:   10000 (8)
 9:   10001 (9)
10:   10010 (10)
11:   10100 (11)
12:   10101 (12)
13:  100000 (13)
14:  100001 (14)
15:  100010 (15)
16:  100100 (16)
17:  100101 (17)
18:  101000 (18)
19:  101001 (19)
20:  101010 (20)
0 + 0 = 0, aka 0 + 0 = 0
101 + 101 = 10000, aka 4 + 4 = 8
10100 - 1000 = 1001, aka 11 - 5 = 6
100100 - 1000 = 10100, aka 16 - 5 = 11
1001 * 101 = 1000100, aka 6 * 4 = 24
1000101 / 101 = 1001 rem 1, aka 25 / 4 = 6 rem 1
10 + 10 = 101, aka 2 + 2 = 4
101 + 10 = 1001, aka 4 + 2 = 6
1001 + 1001 = 10101, aka 6 + 6 = 12
10101 + 1000 = 100101, aka 12 + 5 = 17
100101 + 10101 = 1010000, aka 17 + 12 = 29
1000 - 101 = 1, aka 5 - 4 = 1
10101010 - 1010101 = 1000000, aka 54 - 33 = 21
1001 * 101 = 1000100, aka 6 * 4 = 24
101010 + 101 = 1000100, aka 20 + 4 = 24
10100 + 1010 = 101000, aka 11 + 7 = 18
101000 - 1010 = 10100, aka 18 - 7 = 11
100010 * 100101 = 100001000001, aka 15 * 17 = 255
100001000001 / 100 = 101010001 rem 0, aka 255 / 3 = 85 rem 0
101000101 * 101001 = 101010000010101, aka 80 * 19 = 1520
101010000010101 / 100 = 1001010001001 rem 10, aka 1520 / 3 = 506 rem 2
10100010010100 + 1001000001 = 100000000010101, aka 888 + 111 = 999
10100010010100 - 1001000001 = 10010001000010, aka 888 - 111 = 777
10000 * 1001000001 = 10100010010100, aka 8 * 111 = 888
1010001010000001001 / 100000000100000 = 10001 rem 10100001010101, aka 9876 / 1000 = 9 rem 876
10100 + 1010 = 101000, aka 11 + 7 = 18
10100 - 1010 = 101, aka 11 - 7 = 4
10100 * 1010 = 101000001, aka 11 * 7 = 77
10100 / 1010 = 1 rem 101, aka 11 / 7 = 1 rem 4
101000001 / 1010 = 10100 rem 0, aka 77 / 7 = 11 rem 0

PicoLisp[edit]

(seed (in "/dev/urandom" (rd 8)))
 
(de unpad (Lst)
(while (=0 (car Lst))
(pop 'Lst) )
Lst )
 
(de numz (N)
(let Fibs (1 1)
(while (>= N (+ (car Fibs) (cadr Fibs)))
(push 'Fibs (+ (car Fibs) (cadr Fibs))) )
(make
(for I (uniq Fibs)
(if (> I N)
(link 0)
(link 1)
(dec 'N I) ) ) ) ) )
 
(de znum (Lst)
(let Fibs (1 1)
(do (dec (length Lst))
(push 'Fibs (+ (car Fibs) (cadr Fibs))) )
(sum
'((X Y) (unless (=0 X) Y))
Lst
(uniq Fibs) ) ) )
 
(de incz (Lst)
(addz Lst (1)) )
 
(de decz (Lst)
(subz Lst (1)) )
 
(de addz (Lst1 Lst2)
(let Max (max (length Lst1) (length Lst2))
(reorg
(mapcar + (need Max Lst1 0) (need Max Lst2 0)) ) ) )
 
(de subz (Lst1 Lst2)
(use (@A @B)
(let
(Max (max (length Lst1) (length Lst2))
Lst (mapcar - (need Max Lst1 0) (need Max Lst2 0)) )
(loop
(while (match '(@A 1 0 0 @B) Lst)
(setq Lst (append @A (0 1 1) @B)) )
(while (match '(@A 1 -1 0 @B) Lst)
(setq Lst (append @A (0 0 1) @B)) )
(while (match '(@A 1 -1 1 @B) Lst)
(setq Lst (append @A (0 0 2) @B)) )
(while (match '(@A 1 0 -1 @B) Lst)
(setq Lst (append @A (0 1 0) @B)) )
(while (match '(@A 2 0 0 @B) Lst)
(setq Lst (append @A (1 1 1) @B)) )
(while (match '(@A 2 -1 0 @B) Lst)
(setq Lst (append @A (1 0 1) @B)) )
(while (match '(@A 2 -1 1 @B) Lst)
(setq Lst (append @A (1 0 2) @B)) )
(while (match '(@A 2 0 -1 @B) Lst)
(setq Lst (append @A (1 1 0) @B)) )
(while (match '(@A 1 -1) Lst)
(setq Lst (append @A (0 1))) )
(while (match '(@A 2 -1) Lst)
(setq Lst (append @A (1 1))) )
(NIL (match '(@A -1 @B) Lst)) )
(reorg (unpad Lst)) ) ) )
 
(de mulz (Lst1 Lst2)
(let (Sums (list Lst1) Mulz (0))
(mapc
'((X)
(when (= 1 (car X))
(setq Mulz (addz (cdr X) Mulz)) )
Mulz )
(mapcar
'((X)
(cons
X
(push 'Sums (addz (car Sums) (cadr Sums))) ) )
(reverse Lst2) ) ) ) )
 
(de divz (Lst1 Lst2)
(let Q 0
(while (lez Lst2 Lst1)
(setq Lst1 (subz Lst1 Lst2))
(setq Q (incz Q)) )
(list Q (or Lst1 (0))) ) )
 
(de reorg (Lst)
(use (@A @B)
(let Lst (reverse Lst)
(loop
(while (match '(@A 1 1 @B) Lst)
(if @B
(inc (nth @B 1))
(setq @B (1)) )
(setq Lst (append @A (0 0) @B) ) )
(while (match '(@A 2 @B) Lst)
(inc
(if (cdr @A)
(tail 2 @A)
@A ) )
(if @B
(inc (nth @B 1))
(setq @B (1)) )
(setq Lst (append @A (0) @B)) )
(NIL
(or
(match '(@A 1 1 @B) Lst)
(match '(@A 2 @B) Lst) ) ) )
(reverse Lst) ) ) )
 
(de lez (Lst1 Lst2)
(let Max (max (length Lst1) (length Lst2))
(<= (need Max Lst1 0) (need Max Lst2 0)) ) )
 
(let (X 0 Y 0)
(do 1024
(setq X (rand 1 1024))
(setq Y (rand 1 1024))
(test (numz (+ X Y)) (addz (numz X) (numz Y)))
(test (numz (* X Y)) (mulz (numz X) (numz Y)))
(test (numz (+ X 1)) (incz (numz X))) )
 
(do 1024
(setq X (rand 129 1024))
(setq Y (rand 1 128))
(test (numz (- X Y)) (subz (numz X) (numz Y)))
(test (numz (/ X Y)) (car (divz (numz X) (numz Y))))
(test (numz (% X Y)) (cadr (divz (numz X) (numz Y))))
(test (numz (- X 1)) (decz (numz X))) ) )
 
(bye)

Racket[edit]

This implementation only handles natural (non-negative numbers). The algorithms for addition and subtraction use the techniques explained in the paper "Efficient algorithms for Zeckendorf arithmetic" (http://arxiv.org/pdf/1207.4497.pdf).

#lang racket (require math)
 
(define sqrt5 (sqrt 5))
(define phi (* 0.5 (+ 1 sqrt5)))
 
;; What is the nth fibonnaci number, shifted by 2 so that
;; F(0) = 1, F(1) = 2, ...?
;;
(define (F n)
(fibonacci (+ n 2)))
 
;; What is the largest n such that F(n) <= m?
;;
(define (F* m)
(let ([n (- (inexact->exact (round (/ (log (* m sqrt5)) (log phi)))) 2)])
(if (<= (F n) m) n (sub1 n))))
 
(define (zeck->natural z)
(for/sum ([i (reverse z)]
[j (in-naturals)])
(* i (F j))))
 
(define (natural->zeck n)
(if (zero? n)
null
(for/list ([i (in-range (F* n) -1 -1)])
(let ([f (F i)])
(cond [(>= n f) (set! n (- n f))
1]
[else 0])))))
 
; Extend list to the right to a length of len with repeated padding elements
;
(define (pad lst len [padding 0])
(append lst (make-list (- len (length lst)) padding)))
 
; Strip padding elements from the left of the list
;
(define (unpad lst [padding 0])
(cond [(null? lst) lst]
[(equal? (first lst) padding) (unpad (rest lst) padding)]
[else lst]))
 
;; Run a filter function across a window in a list from left to right
;;
(define (left->right width fn)
(λ (lst)
(let F ([a lst])
(if (< (length a) width)
a
(let ([f (fn (take a width))])
(cons (first f) (F (append (rest f) (drop a width)))))))))
 
;; Run a function fn across a window in a list from right to left
;;
(define (right->left width fn)
(λ (lst)
(let F ([a lst])
(if (< (length a) width)
a
(let ([f (fn (take-right a width))])
(append (F (append (drop-right a width) (drop-right f 1)))
(list (last f))))))))
 
;; (a0 a1 a2 ... an) -> (a0 a1 a2 ... (fn ... an))
;;
(define (replace-tail width fn)
(λ (lst)
(append (drop-right lst width) (fn (take-right lst width)))))
 
(define (rule-a lst)
(match lst
[(list 0 2 0 x) (list 1 0 0 (add1 x))]
[(list 0 3 0 x) (list 1 1 0 (add1 x))]
[(list 0 2 1 x) (list 1 1 0 x)]
[(list 0 1 2 x) (list 1 0 1 x)]
[else lst]))
 
(define (rule-a-tail lst)
(match lst
[(list x 0 3 0) (list x 1 1 1)]
[(list x 0 2 0) (list x 1 0 1)]
[(list 0 1 2 0) (list 1 0 1 0)]
[(list x y 0 3) (list x y 1 1)]
[(list x y 0 2) (list x y 1 0)]
[(list x 0 1 2) (list x 1 0 0)]
[else lst]))
 
(define (rule-b lst)
(match lst
[(list 0 1 1) (list 1 0 0)]
[else lst]))
 
(define (rule-c lst)
(match lst
[(list 1 0 0) (list 0 1 1)]
[(list 1 -1 0) (list 0 0 1)]
[(list 1 -1 1) (list 0 0 2)]
[(list 1 0 -1) (list 0 1 0)]
[(list 2 0 0) (list 1 1 1)]
[(list 2 -1 0) (list 1 0 1)]
[(list 2 -1 1) (list 1 0 2)]
[(list 2 0 -1) (list 1 1 0)]
[else lst]))
 
(define (zeck-combine op y z [f identity])
(let* ([bits (max (add1 (length y)) (add1 (length z)) 4)]
[f0 (λ (x) (pad (reverse x) bits))]
[f1 (left->right 4 rule-a)]
[f2 (replace-tail 4 rule-a-tail)]
[f3 (right->left 3 rule-b)]
[f4 (left->right 3 rule-b)])
((compose1 unpad f4 f3 f2 f1 f reverse) (map op (f0 y) (f0 z)))))
 
(define (zeck+ y z)
(zeck-combine + y z))
 
(define (zeck- y z)
(when (zeck< y z) (error (format "~a" `(zeck-: cannot subtract since ,y < ,z))))
(zeck-combine - y z (left->right 3 rule-c)))
 
(define (zeck* y z)
(define (M ry Zn Zn_1 [acc null])
(if (null? ry)
acc
(M (rest ry) (zeck+ Zn Zn_1) Zn
(if (zero? (first ry)) acc (zeck+ acc Zn)))))
(cond [(zeck< z y) (zeck* z y)]
[(null? y) null]  ; 0 * z -> 0
[else (M (reverse y) z z)]))
 
(define (zeck-quotient/remainder y z)
(define (M Zn acc)
(if (zeck< y Zn)
(drop-right acc 1)
(M (zeck+ Zn (first acc)) (cons Zn acc))))
(define (D x m [acc null])
(if (null? m)
(values (reverse acc) x)
(let* ([v (first m)]
[smaller (zeck< v x)]
[bit (if smaller 1 0)]
[x_ (if smaller (zeck- x v) x)])
(D x_ (rest m) (cons bit acc)))))
(D y (M z (list z))))
 
(define (zeck-quotient y z)
(let-values ([(quotient _) (zeck-quotient/remainder y z)])
quotient))
 
(define (zeck-remainder y z)
(let-values ([(_ remainder) (zeck-quotient/remainder y z)])
remainder))
 
(define (zeck-add1 z)
(zeck+ z '(1)))
 
(define (zeck= y z)
(equal? (unpad y) (unpad z)))
 
(define (zeck< y z)
 ; Compare equal-length unpadded zecks
(define (LT a b)
(if (null? a)
#f
(let ([a0 (first a)] [b0 (first b)])
(if (= a0 b0)
(LT (rest a) (rest b))
(= a0 0)))))
 
(let* ([a (unpad y)] [len-a (length a)]
[b (unpad z)] [len-b (length b)])
(cond [(< len-a len-b) #t]
[(> len-a len-b) #f]
[else (LT a b)])))
 
(define (zeck> y z)
(not (or (zeck= y z) (zeck< y z))))
 
 
;; Examples
;;
(define (example op-name op a b)
(let* ([y (natural->zeck a)]
[z (natural->zeck b)]
[x (op y z)]
[c (zeck->natural x)])
(printf "~a ~a ~a = ~a ~a ~a = ~a = ~a\n"
a op-name b y op-name z x c)))
 
(example '+ zeck+ 888 111)
(example '- zeck- 888 111)
(example '* zeck* 8 111)
(example '/ zeck-quotient 9876 1000)
(example '% zeck-remainder 9876 1000)
 
Output:
888 + 111 = (1 0 1 0 0 0 1 0 0 1 0 1 0 0) + (1 0 0 1 0 0 0 0 0 1) = (1 0 0 0 0 0 0 0 0 0 1 0 1 0 1) = 999
888 - 111 = (1 0 1 0 0 0 1 0 0 1 0 1 0 0) - (1 0 0 1 0 0 0 0 0 1) = (1 0 0 1 0 0 0 1 0 0 0 0 1 0) = 777
8 * 111 = (1 0 0 0 0) * (1 0 0 1 0 0 0 0 0 1) = (1 0 1 0 0 0 1 0 0 1 0 1 0 0) = 888
9876 / 1000 = (1 0 1 0 0 0 1 0 1 0 0 0 0 0 0 1 0 0 1) / (1 0 0 0 0 0 0 0 0 1 0 0 0 0 0) = (1 0 0 0 1) = 9
9876 % 1000 = (1 0 1 0 0 0 1 0 1 0 0 0 0 0 0 1 0 0 1) % (1 0 0 0 0 0 0 0 0 1 0 0 0 0 0) = (1 0 1 0 0 0 0 1 0 1 0 1 0 1) = 876

Scala[edit]

Works with: Scala version 2.9.1

The addition is an implementation of an algorithm suggested in http[:]//arxiv.org/pdf/1207.4497.pdf: Efficient Algorithms for Zeckendorf Arithmetic.

object ZA extends App {
import Stream._
import scala.collection.mutable.ListBuffer
 
object Z {
// only for comfort and result checking:
val fibs: Stream[BigInt] = {def series(i:BigInt,j:BigInt):Stream[BigInt] = i #:: series(j,i+j); series(1,0).tail.tail.tail }
val z2i: Z => BigInt = z => (z.z.abs.toString.map(_.asDigit).reverse.zipWithIndex.map{case (v,i)=>v*fibs(i)}:\BigInt(0))(_+_)*z.z.signum
 
var fmts = Map(Z("0")->List[Z](Z("0"))) //map of Fibonacci multiples table of divisors
 
// get multiply table from fmts
def mt(z: Z): List[Z] = {fmts.getOrElse(z,Nil) match {case Nil => {val e = mwv(z); fmts=fmts+(z->e); e}; case l => l}}
 
// multiply weight vector
def mwv(z: Z): List[Z] = {
val wv = new ListBuffer[Z]; wv += z; wv += (z+z)
var zs = "11"; val upper = z.z.abs.toString
while ((zs.size<upper.size)) {wv += (wv.toList.last + wv.toList.reverse.tail.head); zs = "1"+zs}
wv.toList
}
 
// get division table (division weight vector)
def dt(dd: Z, ds: Z): List[Z] = {
val wv = new ListBuffer[Z]; mt(ds).copyToBuffer(wv)
var zs = ds.z.abs.toString; val upper = dd.z.abs.toString
while ((zs.size<upper.size)) {wv += (wv.toList.last + wv.toList.reverse.tail.head); zs = "1"+zs}
wv.toList
}
}
 
case class Z(var zs: String) {
import Z._
require ((zs.toSet--Set('-','0','1')==Set()) && (!zs.contains("11")))
 
var z: BigInt = BigInt(zs)
override def toString = z+"Z(i:"+z2i(this)+")"
def size = z.abs.toString.size
 
//--- fa(summand1.z,summand2.z) --------------------------
val fa: (BigInt,BigInt) => BigInt = (z1, z2) => {
val v =z1.toString.map(_.asDigit).reverse.padTo(5,0).zipAll(z2.toString.map(_.asDigit).reverse, 0, 0)
val arr1 = (v.map(p=>p._1+p._2):+0 reverse).toArray
(0 to arr1.size-4) foreach {i=> //stage1
val a = arr1.slice(i,i+4).toList
val b = (a:\"")(_+_) dropRight 1
val a1 = b match {
case "020" => List(1,0,0, a(3)+1)
case "030" => List(1,1,0, a(3)+1)
case "021" => List(1,1,0, a(3))
case "012" => List(1,0,1, a(3))
case _ => a
}
0 to 3 foreach {j=>arr1(j+i) = a1(j)}
}
val arr2 = (arr1:\"")(_+_)
.replace("0120","1010").replace("030","111").replace("003","100").replace("020","101")
.replace("003","100").replace("012","101").replace("021","110")
.replace("02","10").replace("03","11")
.reverse.toArray
(0 to arr2.size-3) foreach {i=> //stage2, step1
val a = arr2.slice(i,i+3).toList
val b = (a:\"")(_+_)
val a1 = b match {
case "110" => List('0','0','1')
case _ => a
}
0 to 2 foreach {j=>arr2(j+i) = a1(j)}
}
val arr3 = (arr2:\"")(_+_).concat("0").reverse.toArray
(0 to arr3.size-3) foreach {i=> //stage2, step2
val a = arr3.slice(i,i+3).toList
val b = (a:\"")(_+_)
val a1 = b match {
case "011" => List('1','0','0')
case _ => a
}
0 to 2 foreach {j=>arr3(j+i) = a1(j)}
}
BigInt((arr3:\"")(_+_))
}
 
//--- fs(minuend.z,subtrahend.z) -------------------------
val fs: (BigInt,BigInt) => BigInt = (min,sub) => {
val zmvr = min.toString.map(_.asDigit).reverse
val zsvr = sub.toString.map(_.asDigit).reverse.padTo(zmvr.size,0)
val v = zmvr.zipAll(zsvr, 0, 0).reverse
val last = v.size-1
val zma = zmvr.reverse.toArray; val zsa = zsvr.reverse.toArray
for (i <- 0 to last reverse) {
val e = zma(i)-zsa(i)
if (e<0) {
zma(i-1) = zma(i-1)-1
zma(i) = 0
val part = Z((((i to last).map(zma(_))):\"")(_+_))
val carry = Z(("1".padTo(last-i,"0"):\"")(_+_))
val sum = part + carry; val sums = sum.z.toString
(1 to sum.size) foreach {j=>zma(last-sum.size+j)=sums(j-1).asDigit}
if (zma(i-1)<0) {
for (j <- 0 to i-1 reverse) {
if (zma(j)<0) {
zma(j-1) = zma(j-1)-1
zma(j) = 0
val part = Z((((j to last).map(zma(_))):\"")(_+_))
val carry = Z(("1".padTo(last-j,"0"):\"")(_+_))
val sum = part + carry; val sums = sum.z.toString
(1 to sum.size) foreach {k=>zma(last-sum.size+k)=sums(k-1).asDigit}
}
}
}
}
else zma(i) = e
zsa(i) = 0
}
BigInt((zma:\"")(_+_))
}
 
//--- fm(multiplicand.z,multplier.z) ---------------------
val fm: (BigInt,BigInt) => BigInt = (mc, mp) => {
val mct = mt(Z(mc.toString))
val mpxi = mp.toString.reverse.map(_.asDigit).zipWithIndex.filter(_._1 != 0).map(_._2)
(mpxi:\Z("0"))((fi,sum)=>sum+mct(fi)).z
}
 
//--- fd(dividend.z,divisor.z) ---------------------------
val fd: (BigInt,BigInt) => BigInt = (dd, ds) => {
val dst = dt(Z(dd.toString),Z(ds.toString)).reverse
var diff = Z(dd.toString)
val zd = ListBuffer[String]()
(0 to dst.size-1) foreach {i=>
if (dst(i)>diff) zd+="0" else {diff = diff-dst(i); zd+="1"}
}
BigInt(zd.mkString)
}
 
val fasig: (Z, Z) => Int = (z1, z2) => if (z1.z.abs>z2.z.abs) z1.z.signum else z2.z.signum
val fssig: (Z, Z) => Int = (z1, z2) =>
if ((z1.z.abs>z2.z.abs && z1.z.signum>0)||(z1.z.abs<z2.z.abs && z1.z.signum<0)) 1 else -1
 
def +(that: Z): Z =
if (this==Z("0")) that
else if (that==Z("0")) this
else if (this.z.signum == that.z.signum) Z((fa(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*this.z.signum).toString)
else if (this.z.abs == that.z.abs) Z("0")
else Z((fs(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*fasig(this, that)).toString)
 
def ++ : Z = {val za = this + Z("1"); this.zs = za.zs; this.z = za.z; this}
 
def -(that: Z): Z =
if (this==Z("0")) Z((that.z*(-1)).toString)
else if (that==Z("0")) this
else if (this.z.signum != that.z.signum) Z((fa(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*this.z.signum).toString)
else if (this.z.abs == that.z.abs) Z("0")
else Z((fs(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*fssig(this, that)).toString)
 
def -- : Z = {val zs = this - Z("1"); this.zs = zs.zs; this.z = zs.z; this}
 
def * (that: Z): Z =
if (this==Z("0")||that==Z("0")) Z("0")
else if (this==Z("1")) that
else if (that==Z("1")) this
else Z((fm(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*this.z.signum*that.z.signum).toString)
 
def / (that: Z): Option[Z] =
if (that==Z("0")) None
else if (this==Z("0")) Some(Z("0"))
else if (that==Z("1")) Some(Z("1"))
else if (this.z.abs < that.z.abs) Some(Z("0"))
else if (this.z == that.z) Some(Z("1"))
else Some(Z((fd(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*this.z.signum*that.z.signum).toString))
 
def % (that: Z): Option[Z] =
if (that==Z("0")) None
else if (this==Z("0")) Some(Z("0"))
else if (that==Z("1")) Some(Z("0"))
else if (this.z.abs < that.z.abs) Some(this)
else if (this.z == that.z) Some(Z("0") )
else this/that match {case None => None; case Some(z) => Some(this-z*that)}
 
def < (that: Z): Boolean = this.z < that.z
def <= (that: Z): Boolean = this.z <= that.z
def > (that: Z): Boolean = this.z > that.z
def >= (that: Z): Boolean = this.z >= that.z
 
}
 
val elapsed: (=> Unit) => Long = f => {val s = System.currentTimeMillis; f; (System.currentTimeMillis - s)/1000}
 
val add: (Z,Z) => Z = (z1,z2) => z1+z2
val subtract: (Z,Z) => Z = (z1,z2) => z1-z2
val multiply: (Z,Z) => Z = (z1,z2) => z1*z2
val divide: (Z,Z) => Option[Z] = (z1,z2) => z1/z2
val modulo: (Z,Z) => Option[Z] = (z1,z2) => z1%z2
 
val ops = Map(("+",add),("-",subtract),("*",multiply),("/",divide),("%",modulo))
 
val calcs = List(
(Z("101"),"+",Z("10100"))
, (Z("101"),"-",Z("10100"))
, (Z("101"),"*",Z("10100"))
, (Z("101"),"/",Z("10100"))
, (Z("-1010101"),"+",Z("10100"))
, (Z("-1010101"),"-",Z("10100"))
, (Z("-1010101"),"*",Z("10100"))
, (Z("-1010101"),"/",Z("10100"))
, (Z("1000101010"),"+",Z("10101010"))
, (Z("1000101010"),"-",Z("10101010"))
, (Z("1000101010"),"*",Z("10101010"))
, (Z("1000101010"),"/",Z("10101010"))
, (Z("10100"),"+",Z("1010"))
, (Z("100101"),"-",Z("100"))
, (Z("1010101010101010101"),"+",Z("-1010101010101"))
, (Z("1010101010101010101"),"-",Z("-1010101010101"))
, (Z("1010101010101010101"),"*",Z("-1010101010101"))
, (Z("1010101010101010101"),"/",Z("-1010101010101"))
, (Z("1010101010101010101"),"%",Z("-1010101010101"))
, (Z("1010101010101010101"),"+",Z("101010101010101"))
, (Z("1010101010101010101"),"-",Z("101010101010101"))
, (Z("1010101010101010101"),"*",Z("101010101010101"))
, (Z("1010101010101010101"),"/",Z("101010101010101"))
, (Z("1010101010101010101"),"%",Z("101010101010101"))
, (Z("10101010101010101010"),"+",Z("1010101010101010"))
, (Z("10101010101010101010"),"-",Z("1010101010101010"))
, (Z("10101010101010101010"),"*",Z("1010101010101010"))
, (Z("10101010101010101010"),"/",Z("1010101010101010"))
, (Z("10101010101010101010"),"%",Z("1010101010101010"))
, (Z("1010"),"%",Z("10"))
, (Z("1010"),"%",Z("-10"))
, (Z("-1010"),"%",Z("10"))
, (Z("-1010"),"%",Z("-10"))
, (Z("100"),"/",Z("0"))
, (Z("100"),"%",Z("0"))
)
 
// just for result checking:
import Z._
val iadd: (BigInt,BigInt) => BigInt = (a,b) => a+b
val isub: (BigInt,BigInt) => BigInt = (a,b) => a-b
val imul: (BigInt,BigInt) => BigInt = (a,b) => a*b
val idiv: (BigInt,BigInt) => Option[BigInt] = (a,b) => if (b==0) None else Some(a/b)
val imod: (BigInt,BigInt) => Option[BigInt] = (a,b) => if (b==0) None else Some(a%b)
val iops = Map(("+",iadd),("-",isub),("*",imul),("/",idiv),("%",imod))
 
println("elapsed time: "+elapsed{
calcs foreach {case (op1,op,op2) => println(op1+" "+op+" "+op2+" = "
+{(ops(op))(op1,op2) match {case None => None; case Some(z) => z; case z => z}}
.ensuring{x=>(iops(op))(z2i(op1),z2i(op2)) match {case None => None == x; case Some(i) => i == z2i(x.asInstanceOf[Z]); case i => i == z2i(x.asInstanceOf[Z])}})}
}+" sec"
)
 
}

Output:

101Z(i:4) + 10100Z(i:11) = 100010Z(i:15)
101Z(i:4) - 10100Z(i:11) = -1010Z(i:-7)
101Z(i:4) * 10100Z(i:11) = 10010010Z(i:44)
101Z(i:4) / 10100Z(i:11) = 0Z(i:0)
-1010101Z(i:-33) + 10100Z(i:11) = -1000001Z(i:-22)
-1010101Z(i:-33) - 10100Z(i:11) = -10010010Z(i:-44)
-1010101Z(i:-33) * 10100Z(i:11) = -101010001010Z(i:-363)
-1010101Z(i:-33) / 10100Z(i:11) = -100Z(i:-3)
1000101010Z(i:109) + 10101010Z(i:54) = 10000101001Z(i:163)
1000101010Z(i:109) - 10101010Z(i:54) = 100000000Z(i:55)
1000101010Z(i:109) * 10101010Z(i:54) = 101000001000101001Z(i:5886)
1000101010Z(i:109) / 10101010Z(i:54) = 10Z(i:2)
10100Z(i:11) + 1010Z(i:7) = 101000Z(i:18)
100101Z(i:17) - 100Z(i:3) = 100001Z(i:14)
1010101010101010101Z(i:10945) + -1010101010101Z(i:-609) = 1010100000000000000Z(i:10336)
1010101010101010101Z(i:10945) - -1010101010101Z(i:-609) = 10000001010101010100Z(i:11554)
1010101010101010101Z(i:10945) * -1010101010101Z(i:-609) = -100010001000001001010010100100001Z(i:-6665505)
1010101010101010101Z(i:10945) / -1010101010101Z(i:-609) = -100101Z(i:-17)
1010101010101010101Z(i:10945) % -1010101010101Z(i:-609) = 1010100100100Z(i:592)
1010101010101010101Z(i:10945) + 101010101010101Z(i:1596) = 10000101010101010100Z(i:12541)
1010101010101010101Z(i:10945) - 101010101010101Z(i:1596) = 1010000000000000000Z(i:9349)
1010101010101010101Z(i:10945) * 101010101010101Z(i:1596) = 10001000100001010001001010001001001Z(i:17468220)
1010101010101010101Z(i:10945) / 101010101010101Z(i:1596) = 1001Z(i:6)
1010101010101010101Z(i:10945) % 101010101010101Z(i:1596) = 101000000001000Z(i:1369)
10101010101010101010Z(i:17710) + 1010101010101010Z(i:2583) = 100001010101010101001Z(i:20293)
10101010101010101010Z(i:17710) - 1010101010101010Z(i:2583) = 10100000000000000000Z(i:15127)
10101010101010101010Z(i:17710) * 1010101010101010Z(i:2583) = 1000100010001000000000001000100010001Z(i:45744930)
10101010101010101010Z(i:17710) / 1010101010101010Z(i:2583) = 1001Z(i:6)
10101010101010101010Z(i:17710) % 1010101010101010Z(i:2583) = 1010000000001000Z(i:2212)
1010Z(i:7) % 10Z(i:2) = 1Z(i:1)
1010Z(i:7) % -10Z(i:-2) = 1Z(i:1)
-1010Z(i:-7) % 10Z(i:2) = -1Z(i:-1)
-1010Z(i:-7) % -10Z(i:-2) = -1Z(i:-1)
100Z(i:3) / 0Z(i:0) = None
100Z(i:3) % 0Z(i:0) = None
elapsed time: 1 sec

Tcl[edit]

Translation of: Perl 6
namespace eval zeckendorf {
# Want to use alternate symbols? Change these
variable zero "0"
variable one "1"
 
# Base operations: increment and decrement
proc zincr var {
upvar 1 $var a
namespace upvar [namespace current] zero 0 one 1
if {![regsub "$0$" $a $1$0 a]} {append a $1}
while {[regsub "$0$1$1" $a "$1$0$0" a]
|| [regsub "^$1$1" $a "$1$0$0" a]} {}
regsub ".$" $a "" a
return $a
}
proc zdecr var {
upvar 1 $var a
namespace upvar [namespace current] zero 0 one 1
regsub "^$0+(.+)$" [subst [regsub "${1}($0*)$" $a "$0\[
string repeat {$1$0} \[regsub -all .. {\\1} {} x]]\[
string repeat {$1} \[expr {\$x ne {}}]]"
]
] {\1} a
return $a
}
 
# Exported operations
proc eq {a b} {
expr {$a eq $b}
}
proc add {a b} {
variable zero
while {![eq $b $zero]} {
zincr a
zdecr b
}
return $a
}
proc sub {a b} {
variable zero
while {![eq $b $zero]} {
zdecr a
zdecr b
}
return $a
}
proc mul {a b} {
variable zero
variable one
if {[eq $a $zero] || [eq $b $zero]} {return $zero}
if {[eq $a $one]} {return $b}
if {[eq $b $one]} {return $a}
set c $a
while {![eq [zdecr b] $zero]} {
set c [add $c $a]
}
return $c
}
proc div {a b} {
variable zero
variable one
if {[eq $b $zero]} {error "div zero"}
if {[eq $a $zero] || [eq $b $one]} {return $a}
set r $zero
while {![eq $a $zero]} {
if {![eq $a [add [set a [sub $a $b]] $b]]} break
zincr r
}
return $r
}
# Note that there aren't any ordering operations in this version
 
# Assemble into a coherent API
namespace export \[a-y\]*
namespace ensemble create
}

Demonstrating:

puts [zeckendorf add "10100" "1010"]
puts [zeckendorf sub "10100" "1010"]
puts [zeckendorf mul "10100" "1010"]
puts [zeckendorf div "10100" "1010"]
puts [zeckendorf div [zeckendorf mul "10100" "1010"] "1010"]
Output:
101000
101
101000001
1
10100