Amb
From Rosetta Code
Amb is a programming task. Visitors like you are encouraged to solve it according to the task description, using any language they may happen to know.
Define and give an example of the Amb operator.
The Amb operator takes some number of expressions (or values if that's simpler in the language) and nondeterministically yields the one or fails if given no parameter, amb returns the value that doesn't lead to failure.
The example is using amb to choose four words from the following strings:
set 1: "the" "that" "a"
set 2: "frog" "elephant" "thing"
set 3: "walked" "treaded" "grows"
set 4: "slowly" "quickly"
It is a failure if the last character of word 1 is not equal to the first character of word 2, and similarly with word 2 and word 3, as well as word 3 and word 4. (the only successful sentence is "that thing grows slowly").
Contents |
[edit] Ada
with Ada.Strings.Unbounded; use Ada.Strings.Unbounded;
with Ada.Text_IO; use Ada.Text_IO;
procedure Test_Amb is
type Alternatives is array (Positive range <>) of Unbounded_String;
type Amb (Count : Positive) is record
This : Positive := 1;
Left : access Amb;
List : Alternatives (1..Count);
end record;
function Image (L : Amb) return String is
begin
return To_String (L.List (L.This));
end Image;
function "/" (L, R : String) return Amb is
Result : Amb (2);
begin
Append (Result.List (1), L);
Append (Result.List (2), R);
return Result;
end "/";
function "/" (L : Amb; R : String) return Amb is
Result : Amb (L.Count + 1);
begin
Result.List (1..L.Count) := L.List ;
Append (Result.List (Result.Count), R);
return Result;
end "/";
function "=" (L, R : Amb) return Boolean is
Left : Unbounded_String renames L.List (L.This);
begin
return Element (Left, Length (Left)) = Element (R.List (R.This), 1);
end "=";
procedure Failure (L : in out Amb) is
begin
loop
if L.This < L.Count then
L.This := L.This + 1;
else
L.This := 1;
Failure (L.Left.all);
end if;
exit when L.Left = null or else L.Left.all = L;
end loop;
end Failure;
procedure Join (L : access Amb; R : in out Amb) is
begin
R.Left := L;
while L.all /= R loop
Failure (R);
end loop;
end Join;
W_1 : aliased Amb := "the" / "that" / "a";
W_2 : aliased Amb := "frog" / "elephant" / "thing";
W_3 : aliased Amb := "walked" / "treaded" / "grows";
W_4 : aliased Amb := "slowly" / "quickly";
begin
Join (W_1'Access, W_2);
Join (W_2'Access, W_3);
Join (W_3'Access, W_4);
Put_Line (Image (W_1) & ' ' & Image (W_2) & ' ' & Image (W_3) & ' ' & Image (W_4));
end Test_Amb;
The type Amb is implemented with the operations "/" to construct it from strings. Each instance keeps its state. The operation Failure performs back tracing. Join connects two elements into a chain. The implementation propagates Constraint_Error when matching fails. Sample output:
that thing grows slowly
[edit] ALGOL 68
Works with: ELLA ALGOL 68 version Any (with appropriate job cards) - tested with release 1.8.8d.fc9.i386
Note: This program violates ALGOL 68's scoping rules when a locally scoped procedure is returned to a more global scope. ELLA ALGOL 68RS misses this violation, but ALGOL 68 Genie spots it at run time and then produces an assert. However ELLA ALGOL 68RS does produce the desired result, but may potentially suffer from "mysterious" stack problems.
MODE STRINGS = [0][0]CHAR;
MODE YIELDSTRINGS = PROC(STRINGS)VOID;
MODE ITERSTRINGS = PROC(YIELDSTRINGS)VOID;
OP INITITERSTRINGS = (STRINGS self)ITERSTRINGS:
(YIELDSTRINGS yield)VOID: # scope violation #
FOR i TO UPB self DO
yield(self[i])
OD;
OP + = (ITERSTRINGS for strings, STRINGS b)ITERSTRINGS:
(YIELDSTRINGS yield)VOID: # scope violation #
for strings((STRINGS amb)VOID:(
[UPB amb + 1]STRING joined;
joined[:UPB amb] := amb;
STRING last string := amb[UPB amb];
CHAR last char := last string[UPB last string];
FOR i TO UPB b DO
IF last char = b[i][1] THEN
joined[UPB joined] := b[i];
yield(joined)
FI
OD
));
OP + = (STRINGS a, STRINGS b)ITERSTRINGS: INITITERSTRINGS a + b;
ITERSTRINGS for amb :=
STRINGS("the", "that", "a") +
STRINGS("frog", "elephant", "thing") +
STRINGS("walked", "treaded", "grows") +
STRINGS("slowly", "quickly");
STRINGS sep;
#FOR amb IN for amb DO#
for amb((STRINGS amb)VOID:(
print((amb[1]," ",amb[2]," ",amb[3]," ",amb[4], new line))
))
#OD#
Output:
that thing grows slowly
[edit] AutoHotkey
Search autohotkey.com: [1]
Source: AMB - Ambiguous selector by infogulch
set1 := "the that a"
set2 := "frog elephant thing"
set3 := "walked treaded grows"
set4 := "slowly quickly"
MsgBox % amb( "", set1, set2, set3, set4 )
; this takes a total of 17 iterations to complete
amb( char = "", set1 = "", set2 = "", set3 = "", set4 = "" )
{ ; original call to amb must leave char param blank
Loop, Parse, set1, %A_Space%
If (char = (idxchar := SubStr(A_LoopField, 1, 1)) && set2 = ""
|| (char = idxchar || char = "") && ((retval:= amb(SubStr(A_LoopField, 0, 1), set2, set3, set4)) != ""))
Return A_LoopField " " retval
Return ""
}
[edit] C
Note: This uses the continuations code from http://homepage.mac.com/sigfpe/Computing/continuations.html
typedef const char * amb_t;
amb_t amb(size_t argc, ...)
{
amb_t *choices;
va_list ap;
int i;
if(argc) {
choices = malloc(argc*sizeof(amb_t));
va_start(ap, argc);
i = 0;
do { choices[i] = va_arg(ap, amb_t); } while(++i < argc);
va_end(ap);
i = 0;
do { TRY(choices[i]); } while(++i < argc);
free(choices);
}
FAIL;
}
int joins(const char *left, const char *right) { return left[strlen(left)-1] == right[0]; }
int _main() {
const char *w1,*w2,*w3,*w4;
w1 = amb(3, "the", "that", "a");
w2 = amb(3, "frog", "elephant", "thing");
w3 = amb(3, "walked", "treaded", "grows");
w4 = amb(2, "slowly", "quickly");
if(!joins(w1, w2)) amb(0);
if(!joins(w2, w3)) amb(0);
if(!joins(w3, w4)) amb(0);
printf("%s %s %s %s\n", w1, w2, w3, w4);
return EXIT_SUCCESS;
}
[edit] C#
The implementation of the Amb class
using System;
using System.Collections.Generic;
public class Amb : IDisposable
{
List<IValueSet> streams = new List<IValueSet>();
List<IAssertOrAction> assertsOrActions = new List<IAssertOrAction>();
volatile bool stopped = false;
public IAmbValue<T> DefineValues<T>(params T[] values)
{
return DefineValueSet(values);
}
public IAmbValue<T> DefineValueSet<T>(IEnumerable<T> values)
{
ValueSet<T> stream = new ValueSet<T>();
stream.Enumerable = values;
streams.Add(stream);
return stream;
}
public Amb Assert(Func<bool> function)
{
assertsOrActions.Add(new AmbAssert()
{
Level = streams.Count,
IsValidFunction = function
});
return this;
}
public Amb Perform(Action action)
{
assertsOrActions.Add(new AmbAction()
{
Level = streams.Count,
Action = action
});
return this;
}
public void Stop()
{
stopped = true;
}
public void Dispose()
{
RunLevel(0, 0);
if (!stopped)
{
throw new AmbException();
}
}
void RunLevel(int level, int actionIndex)
{
while (actionIndex < assertsOrActions.Count && assertsOrActions[actionIndex].Level <= level)
{
if (!assertsOrActions[actionIndex].Invoke() || stopped)
return;
actionIndex++;
}
if (level < streams.Count)
{
using (IValueSetIterator iterator = streams[level].CreateIterator())
{
while (iterator.MoveNext())
{
RunLevel(level + 1, actionIndex);
}
}
}
}
interface IValueSet
{
IValueSetIterator CreateIterator();
}
interface IValueSetIterator : IDisposable
{
bool MoveNext();
}
interface IAssertOrAction
{
int Level { get; }
bool Invoke();
}
class AmbAssert : IAssertOrAction
{
internal int Level;
internal Func<bool> IsValidFunction;
int IAssertOrAction.Level { get { return Level; } }
bool IAssertOrAction.Invoke()
{
return IsValidFunction();
}
}
class AmbAction : IAssertOrAction
{
internal int Level;
internal Action Action;
int IAssertOrAction.Level { get { return Level; } }
bool IAssertOrAction.Invoke()
{
Action(); return true;
}
}
class ValueSet<T> : IValueSet, IAmbValue<T>, IValueSetIterator
{
internal IEnumerable<T> Enumerable;
private IEnumerator<T> enumerator;
public T Value { get { return enumerator.Current; } }
public IValueSetIterator CreateIterator()
{
enumerator = Enumerable.GetEnumerator();
return this;
}
public bool MoveNext()
{
return enumerator.MoveNext();
}
public void Dispose()
{
enumerator.Dispose();
}
}
}
public interface IAmbValue<T>
{
T Value { get; }
}
public class AmbException : Exception
{
public AmbException() : base("AMB is angry") { }
}
Usage:
// original problem
using (Amb amb = new Amb())
{
var set1 = amb.DefineValues("the", "that", "a");
var set2 = amb.DefineValues("frog", "elephant", "thing");
var set3 = amb.DefineValues("walked", "treaded", "grows");
var set4 = amb.DefineValues("slowly", "quickly");
amb.Assert(() => IsJoinable(set1.Value, set2.Value));
amb.Assert(() => IsJoinable(set2.Value, set3.Value));
amb.Assert(() => IsJoinable(set3.Value, set4.Value));
amb.Perform(() =>
{
System.Console.WriteLine("{0} {1} {2} {3}", set1.Value, set2.Value, set3.Value, set4.Value);
amb.Stop();
});
}
// problem from http://www.randomhacks.net/articles/2005/10/11/amb-operator
using (Amb amb = new Amb())
{
IAmbValue<int> x = amb.DefineValues(1, 2, 3);
IAmbValue<int> y = amb.DefineValues(4, 5, 6);
amb.Assert(() => x.Value * y.Value == 8);
amb.Perform(() =>
{
System.Console.WriteLine("{0} {1}", x.Value, y.Value);
amb.Stop();
});
}
[edit] Common Lisp
Common Lisp lacks the call/cc present in Scheme, and so the straightforward implementation using continuations would require a full-blown code walker (and could still have some issues with dynamically bound variables). A workable compromise uses the condition system and some convenience macros to define amblet a binding construct like let except that if a variable's init-form is of the form (amb {form}*) the amblet's body will be evaluated with the variable bound to successive values produced by each form until some evaluation does not signal an amb-error.
(define-condition amb-failure () ()
(:report "No amb alternative succeeded."))
(defun invoke-ambiguously (function thunks)
"Call function with successive values produced by successive
functions in thunks until some invocation of function does not signal
an amb-failure."
(do ((thunks thunks (rest thunks)))
((endp thunks) (error 'amb-failure))
(let ((argument (funcall (first thunks))))
(handler-case (return (funcall function argument))
(amb-failure ())))))
(defmacro amblet1 ((var form) &body body)
"If form is of the form (amb {form}*) then amblet1 is a convenient
syntax for invoke-ambiguously, by which body is evaluated with var
bound the results of each form until some evaluation of body does not
signal an amb-failure. For any other form, amblet binds var the result
of form, and evaluates body."
(if (and (listp form) (eq (first form) 'amb))
`(invoke-ambiguously
#'(lambda (,var) ,@body)
(list ,@(loop for amb-form in (rest form)
collecting `#'(lambda () ,amb-form))))
`(let ((,var ,form))
,@body)))
(defmacro amblet (bindings &body body)
"Like let, except that if an init-form is of the form (amb {form}*),
then the corresponding var is bound with amblet1."
(if (endp bindings)
`(progn ,@body)
`(amblet1 ,(first bindings)
(amblet ,(rest bindings)
,@body))))
Example:
> (flet ((string-adjacent (s1 s2)
(char= (char s1 (1- (length s1)))
(char s2 0))))
(amblet ((w1 (amb "the" "that" "a"))
(w2 (amb "frog" "elephant" "thing"))
(w3 (amb "walked" "treaded" "grows"))
(w4 (amb "slowly" "quickly")))
(if (and (string-adjacent w1 w2)
(string-adjacent w2 w3)
(string-adjacent w3 w4))
(list w1 w2 w3 w4)
(signal 'amb-failure))))
("that" "thing" "grows" "slowly")
[edit] D
This example may not display the original intent of this exercise, since the implementer was not fully aware of what the amb operator is used for.
import std.stdio;
import std.string;
char[][]set1 = ["the","that","a"];
char[][]set2 = ["frog","elephant","thing"];
char[][]set3 = ["walked","treaded","grows"];
char[][]set4 = ["slowly","quickly"];
// this amb function takes a function pointer to a comparison function and the possibilities that need to be checked
char[][]amb(bool function(char[],char[])comp,char[][][]options,char[]prev = "") {
char[][]res;
char[][]set = options[0];
options = options[1..$];
foreach(opt;set) {
// if this is the base call, prev is "" and we need to continue (unfortunately, this is array specific,
// but could be reworked with pointers)
if (!prev.length || comp(prev,opt)) {
// take care of the case where we have no options left
if (!options.length) return [opt];
// traverse into the tree
res = amb(comp,options,opt);
// if it was a failure, try the next one
if (res is null) continue;
// we have a match!
else return opt~res;
}
}
// no matches
return null;
}
bool comparator(char[]left,char[]right) {
return left[$-1] == right[0];
}
int main() {
// pass in the comparator and the available sets
char[][]ret = amb(&comparator,[set1,set2,set3,set4]);
if (ret is null) writefln("No matches found!");
else writefln("%s",ret.join(" "));
return 0;
}
[edit] E
E does not currently have any kind of backtracking control flow (though there is a proposal in the works to backtrack upon exceptions, for the sake of consistency). However, since (Almost) Everything Is Message Passing, we can create an object which represents a set of possible values.
This is complicated, however, by the fact that any given amb must appear to produce only one result; that is, def x := amb(["a", "b"]); x + x produces aa or bb, not aa,bb,ab,ba as amb(["a", "b"]) + amb(["a", "b"]) would. Therefore, each choice is associated with the decisions which produced it: a map from amb objects to which member of them was chosen; any combination of two ambs discards any combination of choices which have inconsistent decisions.
Note that the choices are not evaluated lazily; this is a breadth-first rather than depth-first search through possibilities. Also, every amb remembers all of the ambs which produced it. As such, this is probably not a practical system for large problems.
pragma.enable("accumulator")
def [amb, unamb] := { # block hides internals
def Choice := Tuple[any, Map]
def [ambS, ambU] := <elib:sealing.makeBrand>("amb")
var counter := 0 # Used just for printing ambs
/** Check whether two sets of decisions are consistent */
def consistent(decA, decB) {
def overlap := decA.domain() & decB.domain()
for ambObj in overlap {
if (decA[ambObj] != decB[ambObj]) { return false }
}
return true
}
/** From an amb object, extract the possible choices */
def getChoices(obj, decisions) :List[Choice] {
if (decisions.maps(obj)) {
return [[decisions[obj], decisions]]
} else if (ambU.amplify(obj) =~ [[choices, _]]) {
return accum [] for [chosen, dec] ? (consistent(decisions, dec)) in choices { _ + getChoices(chosen, (decisions | dec).with(obj, chosen)) }
} else {
return [[obj, decisions]]
}
}
/** Construct an amb object with remembered decisions */
def ambDec(choices :List[Choice]) {
def serial := (counter += 1)
def ambObj {
to __printOn(out) {
out.print("<amb(", serial, ")")
for [chosen, decisions] in choices {
out.print(" ", chosen)
for k => v in decisions {
out.print(";", ambU.amplify(k)[0][1], "=", v)
}
}
out.print(">")
}
to __optSealedDispatch(brand) {
if (brand == ambS.getBrand()) {
return ambS.seal([choices, serial])
}
}
match [verb, args] {
var results := []
for [rec, rdec] in getChoices(ambObj, [].asMap()) {
def expandArgs(dec, prefix, choosing) {
switch (choosing) {
match [] { results with= [E.call(rec, verb, prefix), dec] }
match [argAmb] + moreArgs {
for [arg, adec] in getChoices(argAmb, dec) {
expandArgs(adec, prefix.with(arg), moreArgs)
}
}
}
}
expandArgs(rdec, [], args)
}
ambDec(results)
}
}
return ambObj
}
/** Construct an amb object with no remembered decisions. (public interface) */
def amb(choices) {
return ambDec(accum [] for c in choices { _.with([c, [].asMap()]) })
}
/** Get the possible results from an amb object, discarding decision info. (public interface) */
def unamb(ambObj) {
return accum [] for [c,_] in getChoices(ambObj, [].asMap()) { _.with(c) }
}
[amb, unamb]
}
def join(a, b) {
# This must not use the builtin if, since it coerces to boolean rather than passing messages.
# false.pick(x, y) returns y and true.pick(x, y) returns x; we protect the amb([]) from causing
# unconditional failure by putting both options in functions.
# <=> is the comparison operator that happens to be message-based.
return (a.last() <=> b[0]).pick(fn {
a + " " + b
}, fn {
amb([])
})()
}
def w1 := amb(["the", "that", "a" ])
def w2 := amb(["frog", "elephant", "thing" ])
def w3 := amb(["walked", "treaded", "grows" ])
def w4 := amb(["slowly", "quickly" ])
unamb(join(join(join(w1, w2), w3), w4))
[edit] Comparison with Haskell
This can be compared with the Haskell use of lists as a monad to represent choice.
- Haskell uses lazy evaluation; E does not. This implementation does not simulate lazy evaluation with thunks; it is eager (computes every intermediate choice before continuing) and therefore inefficient if you only need one successful result.
- Haskell does not need to track decisions. This is because when using a monad in Haskell, the points of choice are explicitly written, either by monadic operators or combinators. The analogues to the two "ab" operations given above are:
do x <- ["a","b"]; return (x ++ x)anddo x <- ["a","b"]; y <- ["a","b"]; return (x ++ y)— the relevant difference being the number of<-operators. In this implementation, we instead absorb the choice into normal method calls; the Haskell analogue would be something likeinstance Monoid a => Monoid (Amb a) where Amb ... `mconcat` Amb ... = ..., which would have a similar need to track decisions.
[edit] Factor
USING: backtrack continuations kernel prettyprint sequences ;
IN: amb
CONSTANT: words {
{ "the" "that" "a" }
{ "frog" "elephant" "thing" }
{ "walked" "treaded" "grows" }
{ "slowly" "quickly" }
}
: letters-match? ( str1 str2 -- ? ) [ last ] [ first ] bi* = ;
: sentence-match? ( seq -- ? ) dup rest [ letters-match? ] 2all? ;
: select ( seq -- seq' ) [ amb-lazy ] map ;
: search ( -- )
words select dup sentence-match? [ " " join ] [ fail ] if . ;
MAIN: search
Running it from the listener :
( scratchpad ) "amb" run "that thing grows slowly"
[edit] Haskell
Haskell's List monad returns all the possible choices. Use the "head" function on the result if you just want one.
import Control.Monad
amb = id
joins left right = last left == head right
example = do
w1 <- amb ["the", "that", "a"]
w2 <- amb ["frog", "elephant", "thing"]
w3 <- amb ["walked", "treaded", "grows"]
w4 <- amb ["slowly", "quickly"]
unless (joins w1 w2) (amb [])
unless (joins w2 w3) (amb [])
unless (joins w3 w4) (amb [])
return (unwords [w1, w2, w3, w4])
Note that "amb" is defined as a no-op and is written only to help show the analogy with other implementations; ordinary style is to write e.g. w1 <- ["the", "that", "a"].
[edit] haXe
class RosettaDemo
{
static var SetA : Array<String> = ['the', 'that', 'a'];
static var SetB : Array<String> = ['frog', 'elephant', 'thing'];
static var SetC : Array<String> = ['walked', 'treaded', 'grows'];
static var SetD : Array<String> = ['slowly', 'quickly'];
static public function main()
{
neko.Lib.print(AmbParse([ SetA, SetB, SetC, SetD ]).toString());
}
static function AmbParse(Sets : Array<Array<String>>)
{
var AmbData : Dynamic = Amb(Sets);
for (data in 0...AmbData.length)
{
var tmpData : String = parseIt(AmbData[data]);
var tmpArray : Array<String> = tmpData.split(' ');
tmpArray.pop();
if (tmpArray.length == Sets.length)
{
return tmpData;
}
}
return '';
}
static function Amb(?StartingWith : String = '', Sets : Array<Array<String>>)
{
if (Sets.length == 0 || Sets[0].length == 0) { return; }
var match : Dynamic = [];
for (Reference in 0...Sets[0].length)
{
if (StartingWith == '' || StartingWith == Sets[0][Reference].charAt(0))
{
if (Std.is(Amb(Sets[0][Reference].charAt(Sets[0][Reference].length-1), Sets.slice(1)), Array))
{
match.push([ Sets[0][Reference], Amb(Sets[0][Reference].charAt(Sets[0][Reference].length-1), Sets.slice(1))]);
}
else
{
match.push([ Sets[0][Reference] ]);
}
}
}
return match;
}
static function parseIt(data : Dynamic)
{
var retData : String = '';
if (Std.is(data, Array))
{
for (elements in 0...data.length)
{
if (Std.is(data[elements], Array))
{
retData = retData + parseIt(data[elements]);
}
else
{
retData = retData + data[elements] + ' ';
}
}
}
return retData;
}
}
[edit] J
amb=. ([ , ' ' , ])&>/&.>@:((({:@:[ = {.@:])&>/&> # ])@:,@:({@(,&<)))
>@(amb&.>/) ('the';'that';'a');('frog';'elephant';'thing');('walked';'treaded';'grows');(<'slowly';'quickly')
+-----------------------+
|that thing grows slowly|
+-----------------------+
amb is a dyadic verb:
('the';'that';'a') amb ('frog';'elephant';'thing') amb ('walked';'treaded';'grows') amb ('slowly';'quickly')
+-----------------------+
|that thing grows slowly|
+-----------------------+
A structured derivation of amb follows:
NB. Dynamic programming method...
o=. @: NB. Composing verbs
success=. {:o[ = {.o] NB. Is the last letter of the left word equal to the first of the right?
join=. [ , ' ' , ] NB. Joining the left and right words
cp=. {@(,&<) NB. Cartesian product
amb=. join&>/&.> o ((success&>/ &> # ]) o , o cp)f.
amb NB. Showing the point-free code...
([ , ' ' , ])&>/&.>@:((({:@:[ = {.@:])&>/&> # ])@:,@:({@(,&<)))
[edit] Lua
function amb (set)
local workset = {}
if (#set == 0) or (type(set) ~= 'table') then return end
if #set == 1 then return set end
if #set > 2 then
local first = table.remove(set,1)
set = amb(set)
for i,v in next,first do
for j,u in next,set do
if v:byte(#v) == u[1]:byte(1) then table.insert(workset, {v,unpack(u)}) end
end
end
return workset
end
for i,v in next,set[1] do
for j,u in next,set[2] do
if v:byte(#v) == u:byte(1) then table.insert(workset,{v,u}) end
end
end
return workset
end
Usage example:
result = amb({{'the','that','a'},{'frog','elephant','thing'},{'walked','treaded','grows'},{'slowly','quickly'}})
for i,v in next,result do
io.write (i,':\t')
for j,u in next,v do
io.write (u,' ')
end
io.write ('\n')
end
[edit] Mathematica
Make all the tuples of all the lists, then filter out the good ones:
CheckValid[i_List]:=If[Length[i]<=1,True,And@@(StringTake[#[[1]],-1]==StringTake[#[[2]],1]&/@Partition[i,2,1])]
sets={{"the","that","a"},{"frog","elephant","thing"},{"walked","treaded","grows"},{"slowly","quickly"}};
Select[Tuples[sets],CheckValid]
gives back:
{{"that", "thing", "grows", "slowly"}}
Note that it will return multiple values if multiple sentences match the requirement, that is why the returned value is a list of list (1 element, 4 elements).
Alternative algorithm (slightly faster on most data sets):
CheckValid2[i_List] := StringFreeQ[StringJoin[Riffle[i, ","]], a_ ~~ "," ~~ b_ /; a =!= b]
[edit] OCaml
There is no Amb operator in OCaml. So below are two solutions to solve the same task. The first one is the more idiomatic for OCaml (and is similar to the Haskell solution), it builds all possible combinations and then take the good result in it.
The second solution tries to be closer to the way of solving the problem of Amb. It does not build and accumulate the combinations, it iterates over these with a higher order function and it stops when it finds a solution that matches the predicate.
[edit] Filtering possible combinations
let set_1 = ["the"; "that"; "a"]
let set_2 = ["frog"; "elephant"; "thing"]
let set_3 = ["walked"; "treaded"; "grows"]
let set_4 = ["slowly"; "quickly"]
let combs ll =
let rec aux acc = function
| [] -> (List.map List.rev acc)
| hd::tl ->
let acc =
List.fold_left
(fun _ac l ->
List.fold_left (fun _ac v -> (v::l)::_ac) _ac hd
) [] acc
in
aux acc tl
in
aux [[]] ll
let last s = s.[pred(String.length s)]
let joined a b = (last a = b.[0])
let rec test = function
| a::b::tl -> (joined a b) && (test (b::tl))
| _ -> true
let print_set set =
List.iter (Printf.printf " %s") set;
print_newline();
;;
let () =
let sets = combs [set_1; set_2; set_3; set_4] in
let sets = List.filter test sets in
List.iter print_set sets;
;;
We can take all the good results with List.filter
or just take the first one with List.find.
[edit] Higher order function
Here the function comb_search replaces the function combs and uses arrays instead of lists. This function takes successively all the possible results by their indicies (with the array nx). When a result satisfies the predicate p, it is returned.
let set_1 = [| "the"; "that"; "a" |]
let set_2 = [| "frog"; "elephant"; "thing" |]
let set_3 = [| "walked"; "treaded"; "grows" |]
let set_4 = [| "slowly"; "quickly" |]
let comb_search p aa =
let nx = Array.make (Array.length aa) 0 in
let lx = Array.map Array.length aa in
let la = Array.length aa in
let rec loop() =
let res = Array.mapi (fun i j -> aa.(i).(j)) nx in
if p res then (res)
else
( nx.(0) <- nx.(0) + 1;
if nx.(0) < lx.(0)
then loop()
else
( nx.(0) <- 0;
let rec roll n =
if n >= la then raise Not_found
else
( nx.(n) <- nx.(n) + 1;
if nx.(n) >= lx.(n)
then ( nx.(n) <- 0; roll (n+1) )
else loop()
)
in
roll 1
)
)
in
loop()
let last s = s.[pred(String.length s)]
let joined a b = (last a = b.[0])
let rec test = function
| a::b::tl -> (joined a b) && (test (b::tl))
| _ -> true
let test r = test(Array.to_list r)
let print_set set =
Array.iter (Printf.printf " %s") set;
print_newline();
;;
let () =
let result = comb_search test [| set_1; set_2; set_3; set_4 |] in
print_set result;
;;
[edit] Oz
Oz is, among other things, a logic programming language and has a choice operator. Using recursion we can easily build an Amb operator with it.
declare
fun {Amb Xs}
case Xs of nil then fail
[] [X] then X
[] X|Xr then
choice X
[] {Amb Xr}
end
end
end
fun {Example}
W1 = {Amb ["the" "that" "a"]}
W2 = {Amb ["frog" "elephant" "thing"]}
W3 = {Amb ["walked" "treaded" "grows"]}
W4 = {Amb ["slowly" "quickly"]}
in
{List.last W1 W2.1}
{List.last W2 W3.1}
{List.last W3 W4.1}
W1#" "#W2#" "#W3#" "#W4
end
in
{ForAll {SearchAll Example} System.showInfo}
In Oz, the programmer explicitly controls how a logic program is executed (search strategy, number of required solutions, laziness, which physical machines are used for the search process...). In this case we use the predefined function SearchAll to eagerly calculate all possible solution. All work is done within the current process.
[edit] Prolog
amb(E, [E|_]).
amb(E, [_|ES]) :- amb(E, ES).
joins(Left, Right) :-
append(_, [T], Left),
append([R], _, Right),
( T \= R -> amb(_, []) % (explicitly using amb fail as required)
; true ).
amb_example([Word1, Word2, Word3, Word4]) :-
amb(Word1, ["the","that","a"]),
amb(Word2, ["frog","elephant","thing"]),
amb(Word3, ["walked","treaded","grows"]),
amb(Word4, ["slowly","quickly"]),
joins(Word1, Word2),
joins(Word2, Word3),
joins(Word3, Word4).
[edit] Perl
Generates permutation of the sets with the glob function. Then, validate the combination with a regular expression.
$s1 = "the|,that|,a|";
$s2 = "frog|,elephant|,thing|";
$s3 = "walked|,treaded|,grows|";
$s4 = "slowly|,quickly|";
$sets = "{$s1}{$s2}{$s3}{$s4}";
print "$sets\n";
for( glob($sets) )
{
tr/|/ /;
print "$_\n" if(m/\w+?(\w) \1\w+?(\w) \2\w+?(\w) \3\w+/);
}
[edit] PureBasic
Procedure Words_Ok(String1.s, String2.s)
If Mid(String1,Len(String1),1)=Mid(String2,1,1)
ProcedureReturn #True
EndIf
ProcedureReturn #False
EndProcedure
Procedure.s Amb(Array A.s(1), Array B.s(1), Array C.s(1), Array D.s(1))
Protected a, b, c, d
For a=0 To ArraySize(A())
For b=0 To ArraySize(B())
For c=0 To ArraySize(C())
For d=0 To ArraySize(D())
If Words_Ok(A(a),B(b)) And Words_Ok(B(b),C(c)) And Words_Ok(C(c),D(d))
ProcedureReturn A(a)+" "+B(b)+" "+C(c)+" "+D(d)
EndIf
Next
Next
Next
Next
ProcedureReturn "" ; Empty string, e.g. fail
EndProcedure
If OpenConsole()
Define Text.s
Dim Set1.s(2)
Dim Set2.s(2)
Dim Set3.s(2)
Dim Set4.s(1)
Set1(0)="the": set1(1)="that": set1(2)="a"
Set2(0)="frog": set2(1)="elephant": set2(2)="thing"
Set3(0)="walked": set3(1)="treaded": set3(2)="grows"
Set4(0)="slowly": set4(1)="quickly"
text=Amb(set1(),set2(),Set3(),set4())
If Text<>""
PrintN("Correct sentence would be,"+#CRLF$+Text)
Else
PrintN("Failed to fine a correct sentence.")
EndIf
PrintN(#CRLF$+#CRLF$+"Press ENTER to exit."): Input()
CloseConsole()
EndIf
[edit] Python
Python does not have the amb function, but, in the spirit of the task, here is an implementation in Python (version 2.6) that uses un-ordered sets of words; the itertools.product function to loop through all the word sets lazily; and a generator comprehension to lazily give the first answer:
>>> from itertools import product
>>> sets = [
set('the that a'.split()),
set('frog elephant thing'.split()),
set('walked treaded grows'.split()),
set('slowly quickly'.split())
]
>>> success = ( sentence for sentence in product(*sets)
if all(sentence[word][-1]==sentence[word+1][0]
for word in range(3))
)
>>> success.next()
('that', 'thing', 'grows', 'slowly')
>>>
The following is inspired by Haskell. For loops in a generator kind of act as an amb operator. Of course the indenting won't be right because for-blocks have to be indented. I will try to replicate the "amb with empty list" here faithfully but it is really awkward:.
def amb(*args): return args
def joins(left, right): return left[-1] == right[0]
def example():
for w1 in amb("the", "that", "a"):
for w2 in amb("frog", "elephant", "thing"):
for w3 in amb("walked", "treaded", "grows"):
for w4 in amb("slowly", "quickly"):
for _ in joins(w1,w2) and amb(42) or amb(): # this is really just "if joins(w1,w2):"
for _ in joins(w2,w3) and amb(42) or amb(): # this is really just "if joins(w2,w3):"
for _ in joins(w3,w4) and amb(42) or amb(): # this is really just "if joins(w3,w4):"
yield "%s %s %s %s" % (w1,w2,w3,w4)
>>> list(example())
['that thing grows slowly']
[edit] Ruby
class Amb
class ExhaustedError < RuntimeError; end
def initialize
@fail = proc { fail ExhaustedError, "amb tree exhausted" }
end
def choose(*choices)
prev_fail = @fail
callcc { |sk|
choices.each { |choice|
callcc { |fk|
@fail = proc {
@fail = prev_fail
fk.call(:fail)
}
if choice.respond_to? :call
sk.call(choice.call)
else
sk.call(choice)
end
}
}
@fail.call
}
end
def failure
choose
end
def assert(cond)
failure unless cond
end
end
A = Amb.new
w1 = A.choose("the", "that", "a")
w2 = A.choose("frog", "elephant", "thing")
w3 = A.choose("walked", "treaded", "grows")
w4 = A.choose("slowly", "quickly")
A.choose() if not w1[-1] == w2[0]
A.choose() if not w2[-1] == w3[0]
A.choose() if not w3[-1] == w4[0]
puts w1, w2, w3, w4
[edit] Scala
object Amb {
def amb(wss: List[List[String]]): Option[String] = {
def _amb(ws: List[String], wss: List[List[String]]): Option[String] = wss match {
case Nil => ((Some(ws.head): Option[String]) /: ws.tail)((a, w) => a match {
case Some(x) => if (x.last == w.head) Some(x + " " + w) else None
case None => None
})
case ws1 :: wss1 => ws1.flatMap(w => _amb(w :: ws, wss1)).headOption
}
_amb(Nil, wss.reverse)
}
def main(args: Array[String]) {
println(amb(List(List("the", "that", "a"), List("frog", "elephant", "thing"), List("walked", "treaded", "grows"), List("slowly", "quickly"))))
}
}
[edit] Scheme
(define fail
(lambda ()
(error "Amb tree exhausted")))
(define-syntax amb
(syntax-rules ()
((AMB) (FAIL)) ; Two shortcuts.
((AMB expression) expression)
((AMB expression ...)
(LET ((FAIL-SAVE FAIL))
((CALL-WITH-CURRENT-CONTINUATION ; Capture a continuation to
(LAMBDA (K-SUCCESS) ; which we return possibles.
(CALL-WITH-CURRENT-CONTINUATION
(LAMBDA (K-FAILURE) ; K-FAILURE will try the next
(SET! FAIL K-FAILURE) ; possible expression.
(K-SUCCESS ; Note that the expression is
(LAMBDA () ; evaluated in tail position
expression)))) ; with respect to AMB.
...
(SET! FAIL FAIL-SAVE) ; Finally, if this is reached,
FAIL-SAVE))))))) ; we restore the saved FAIL.
(let ((w-1 (amb "the" "that" "a"))
(w-2 (amb "frog" "elephant" "thing"))
(w-3 (amb "walked" "treaded" "grows"))
(w-4 (amb "slowly" "quickly")))
(define (joins? left right)
(equal? (string-ref left (- (string-length left) 1)) (string-ref right 0)))
(if (joins? w-1 w-2) '() (amb))
(if (joins? w-2 w-3) '() (amb))
(if (joins? w-3 w-4) '() (amb))
(list w-1 w-2 w-3 w-4))
[edit] SETL
program amb;
sets := unstr('[{the that a} {frog elephant thing} {walked treaded grows} {slowly quickly}]');
words := [amb(words): words in sets];
if exists lWord = words(i), rWord in {words(i+1)} |
lWord(#lWord) /= rWord(1) then
fail;
end if;
proc amb(words);
return arb {word in words | ok};
end proc;
end program;
Sadly ok and fail were only ever implemented in CIMS SETL, and are not in any compiler or interpreter that is available today, so this is not very useful as it stands.
[edit] Alternate version (avoids backtracking)
program amb;
sets := unstr('[{the that a} {frog elephant thing} {walked treaded grows} {slowly quickly}]');
print(amb(sets));
proc amb(sets);
return amb1([], {}, sets);
end proc;
proc amb1(prev, mbLast, sets);
if sets = [] then
return prev;
else
words fromb sets;
if exists word in words |
(forall last in mbLast |
last(#last) = word(1)) and
(exists sentence in {amb1(prev with word, {word}, sets)} |
true) then
return sentence;
end if;
end if;
end proc;
end program;
We cheat a bit here - this version of amb must be given the whole list of word sets, and that list is consumed recursively. It can't pick a word from an individual list.
[edit] Tcl
[edit] Brute Force
Brute force, with quick kill of failing attempts:
set amb {
{the that a}
{frog elephant thing}
{walked treaded grows}
{slowly quickly}
}
proc joins {a b} {
expr {[string index $a end] eq [string index $b 0]}
}
foreach i [lindex $amb 0] {
foreach j [lindex $amb 1] {
if ![joins $i $j] continue
foreach k [lindex $amb 2] {
if ![joins $j $k] continue
foreach l [lindex $amb 3] {
if [joins $k $l] {
puts [list $i $j $k $l]
}
}
}
}
}
[edit] With Coroutines
A more sophisticated using Tcl 8.6's coroutine facility that avoids the assumption of what the problem is in the code structure:
package require Tcl 8.6
proc cp {args} {
coroutine cp.[incr ::cps] apply {{list args} {
yield [info coroutine]
foreach item $list {
if {[llength $args]} {
set c [cp {*}$args]
while 1 { yield [list $item {*}[$c]] }
} else { yield $item }
}
return -code break
}} {*}$args
}
proc amb {name filter args} {
coroutine $name apply {{filter args} {
set c [cp {*}$args]
yield [info coroutine]
while 1 {
set value [$c]
if {[{*}$filter $value]} { yield $value }
}
return -code break
}} $filter {*}$args
}
proc joins {a b} {
expr {[string index $a end] eq [string index $b 0]}
}
proc joins* list {
foreach a [lrange $list 0 end-1] b [lrange $list 1 end] {
if {![joins $a $b]} {return 0}
}
return 1
}
amb words joins* \
{the that a} \
{frog elephant thing} \
{walked treaded grows} \
{slowly quickly}
while 1 { puts [words] }
[edit] VBScript
[edit] Implementation
class ambiguous
dim sRule
public property let rule( x )
sRule = x
end property
public default function amb(p1, p2)
amb = eval(sRule)
end function
end class
[edit] Invocation
dim amb
set amb = new ambiguous
amb.rule = "right(p1,1)=left(p2,1)"
dim w1, w2, w3, w4
for each w1 in split("the that a", " ")
for each w2 in split("frog elephant thing", " ")
for each w3 in split("walked treaded grows", " ")
for each w4 in split("slowly quickly", " ")
if amb(w1, w2) and amb(w2, w3) and amb(w3, w4) then
wscript.echo w1, w2, w3, w4
end if
next
next
next
next
[edit] Output
that thing grows slowly
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