Zebra puzzle: Difference between revisions

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m →‎{{header|C}}: make gcc -pedantic happy
Python entry
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Works with SWI-Prolog.
Works with SWI-Prolog.

=={{header|Python}}==
<lang python>from itertools import permutations
import psyco; psyco.full()

class Number:elems= "One Two Three Four Five".split()
class Color: elems= "Red Green Blue White Yellow".split()
class Drink: elems= "Milk Coffee Water Beer Tea".split()
class Smoke: elems= "PallMall Dunhill Blend BlueMaster Prince".split()
class Pet: elems= "Dog Cat Fish Horse Bird".split()
class Nation:elems= "British Swedish Danish Norvegian German".split()

for c in (Number, Color, Drink, Smoke, Pet, Nation):
for i, e in enumerate(c.elems):
exec "%s.%s = %d" % (c.__name__, e, i)

def is_possible(number, color, drink, smoke, pet):
if number and number[Nation.Norvegian] != Number.One:
return False
if color and color[Nation.British] != Color.Red:
return False
if drink and drink[Nation.Danish] != Drink.Tea:
return False
if smoke and smoke[Nation.German] != Smoke.Prince:
return False
if pet and pet[Nation.Swedish] != Pet.Dog:
return False

if not number or not color or not drink or not smoke or not pet:
return True

for i in xrange(5):
if color[i] == Color.Green and drink[i] != Drink.Coffee:
return False
if smoke[i] == Smoke.PallMall and pet[i] != Pet.Bird:
return False
if color[i] == Color.Yellow and smoke[i] != Smoke.Dunhill:
return False
if number[i] == Number.Three and drink[i] != Drink.Milk:
return False
if smoke[i] == Smoke.BlueMaster and drink[i] != Drink.Beer:
return False
if color[i] == Color.Blue and number[i] != Number.Two:
return False

for j in xrange(5):
if (color[i] == Color.Green and
color[j] == Color.White and
number[j] - number[i] != 1):
return False

diff = abs(number[i] - number[j])
if smoke[i] == Smoke.Blend and pet[j] == Pet.Cat and diff != 1:
return False
if pet[i]==Pet.Horse and smoke[j]==Smoke.Dunhill and diff != 1:
return False
if smoke[i]==Smoke.Blend and drink[j]==Drink.Water and diff!=1:
return False

return True

def show_row(t, data):
print "%6s: %12s%12s%12s%12s%12s" % (
t.__name__, t.elems[data[0]],
t.elems[data[1]], t.elems[data[2]],
t.elems[data[3]], t.elems[data[4]])

def main():
perms = list(permutations(range(5)))

for number in perms:
if is_possible(number, None, None, None, None):
for color in perms:
if is_possible(number, color, None, None, None):
for drink in perms:
if is_possible(number, color, drink, None, None):
for smoke in perms:
if is_possible(number, color, drink, smoke, None):
for pet in perms:
if is_possible(number, color, drink, smoke, pet):
print "Found a solution:"
show_row(Nation, range(5))
show_row(Number, number)
show_row(Color, color)
show_row(Drink, drink)
show_row(Smoke, smoke)
show_row(Pet, pet)
print

main()</lang>
Output:
<pre>Found a solution:
Nation: British Swedish Danish Norvegian German
Number: Three Five Two One Four
Color: Red White Blue Yellow Green
Drink: Milk Beer Tea Water Coffee
Smoke: PallMall BlueMaster Blend Dunhill Prince
Pet: Bird Dog Horse Cat Fish</pre>