Word search: Difference between revisions
m (→{{header|zkl}}: fiddle) |
m (→{{header|zkl}}: fiddle) |
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=={{header|zkl}}== |
=={{header|zkl}}== |
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Repeat words allowed |
Repeat words allowed |
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<lang zkl>fcn buildVectors(R,C){ //-->up to 8 vectors of wild |
<lang zkl>fcn buildVectors(R,C){ //-->up to 8 vectors of wild card strings |
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var [const] dirs=T(T(1,0), T(0,1), T(1,1), T(1,-1), T(-1,0),T(0,-1), T(-1,-1), T(-1,1)); |
var [const] dirs=T(T(1,0), T(0,1), T(1,1), T(1,-1), T(-1,0),T(0,-1), T(-1,-1), T(-1,1)); |
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vs,v:=List(),List(); |
vs,v:=List(),List(); |
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vs.filter(fcn(v){ v[0].len()>2 }).shuffle() |
vs.filter(fcn(v){ v[0].len()>2 }).shuffle() |
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} |
} |
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fcn findFit(vs,words){ //-->(n, word) ie (nth vector,word) |
fcn findFit(vs,words){ //-->(n, word) ie (nth vector,word), empty vs not seen |
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do(1000){ foreach n,v in (vs.enumerate()){ do(10){ // lots of ties |
do(1000){ foreach n,v in (vs.enumerate()){ do(10){ // lots of ties |
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word:=words[(0).random(nwds)]; |
word:=words[(0).random(nwds)]; |
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if(word.matches(v[0][0,word.len()])) return(word,n); |
if(word.matches(v[0][0,word.len()])) return(word,n); // "??" !match "a |
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}}} |
}}} |
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False |
False |
Revision as of 00:49, 27 March 2016
A word search puzzle typically consists of a grid of letters in which words are hidden.
There are many varieties of word search puzzles. For the task at hand we will use a rectangular grid in which the words may be placed horizontally, vertically, or diagonally. The words may also be spelled backwards.
The words are not allowed to zigzag, or wrap around. They may overlap but not be completely embedded in another word.
The task: create a 10 by 10 word search and fill it using words from the unixdict. Use only words that are longer than 2, and contain no non-alphabetic characters.
The cells not used by the hidden words should contain the message: Rosetta Code, read from left to right, top to bottom. These letters should be somewhat evenly distributed over the grid, not clumped together. The message should be in upper case, the hidden words in lower case. All cells should either contain letters from the hidden words or from the message.
Pack a minimum of 25 words into the grid.
Print the resulting grid and the solutions.
For instance:
0 1 2 3 4 5 6 7 8 9 0 n a y r y R e l m f 1 y O r e t s g n a g 2 t n e d i S k y h E 3 n o t n c p c w t T 4 a l s u u n T m a x 5 r o k p a r i s h h 6 a A c f p a e a c C 7 u b u t t t O l u n 8 g y h w a D h p m u 9 m i r p E h o g a n parish (3,5)(8,5) gangster (9,1)(2,1) paucity (4,6)(4,0) guaranty (0,8)(0,1) prim (3,9)(0,9) huckster (2,8)(2,1) plasm (7,8)(7,4) fancy (3,6)(7,2) hogan (5,9)(9,9) nolo (1,2)(1,5) under (3,4)(3,0) chatham (8,6)(8,0) ate (4,8)(6,6) nun (9,7)(9,9) butt (1,7)(4,7) hawk (9,5)(6,2) why (3,8)(1,8) ryan (3,0)(0,0) fay (9,0)(7,2) much (8,8)(8,5) tar (5,7)(5,5) elm (6,0)(8,0) max (7,4)(9,4) pup (5,3)(3,5) mph (8,8)(6,8)
J
Implementation:
<lang J>require'web/gethttp'
unixdict=:verb define
if. _1 -: fread 'unixdict.txt' do. (gethttp 'http://www.puzzlers.org/pub/wordlists/unixdict.txt') fwrite 'unixdict.txt' end. fread 'unixdict.txt'
)
words=:verb define
(#~ 1 - 0&e.@e.&'abcdefghijklmnopqrstuvwxyz'@>) (#~ [: (2&< * 10&>:) #@>) <;._2 unixdict
)
dirs=: 10#.0 0-.~>,{,~<i:1 lims=: _10+,"2 +/&>/"1 (0~:i:4)#>,{,~<<"1]1 10 1 +i."0]10*i:_1 dnms=: ;:'nw north ne west east sw south se'
genpuz=:verb define
words=. words fill=. 'ROSETTACODE' grid=. ,10 10$' ' inds=. ,i.10 10 patience=. -:#words key=. i.0 0 inuse=. i.0 2 while. (26>#key)+.0<cap=. (+/' '=grid)-#fill do. word=. >({~ ?@#) words dir=. ?@#dirs offs=. (inds#~(#word)<:inds{dir{lims)+/(i.#word)*/dir{dirs cool=. ' '=offs{grid sel=. */"1 cool+.(offs{grid)="1 word offs=. (sel*cap>:+/"1 cool)#offs if. (#offs) do. off=. ({~ ?@#) offs loc=. ({.off),dir if. -. loc e. inuse do. inuse=. inuse,loc grid=. word off} grid patience=. patience+1 key=. /:~ key,(10{.word),(3":1+10 10#:{.off),' ',dir{::dnms end. else. NB. grr... if. 0 > patience=. patience-1 do. inuse=.i.0 2 key=.i.0 0 grid=. ,10 10$' ' patience=. -:#words end. end. end. puz=. (_23{.":i.10),' ',1j1#"1(":i.10 1),.' ',.10 10$fill (I.grid=' ')} grid puz,' ',1 1}._1 _1}.":((</.~ <.) i.@# * 3%#)key
)</lang>
Notes:
While the result is square, we flatten our intermediate results to simplify the code.
dirs
are index offsets within the flattened grid for each of the eight cardinal directions.
lims
is, for each cardinal direction, and for each grid position, how long of a word can fit.
dnms
are names for each of the cardinal directions.
words
are the viable words from unixdict, and fill
is what we're going to leave in the puzzle for spaces not occupied by any of those words (and this could be made into a parameter).
grid
is our working copy of the text of the word search puzzle.
inds
are the indices into grid - we will use these as the starting positions when we place the words.
patience
is a guard variable, to avoid problems with infinite loops if we arbitrarily place words in a non-viable fashion.
key
lists the words we are placing, and where we placed them.
inuse
marks location+directions which already have a word (to prevent short words such as sal from being placed as prefixes of longer words such as sale).
Once we have these, we go into a loop where:
word
is picked arbitrarily from the viable words from unixdict.
dir
is picked arbitrarily from one of our eight cardinal directions.
offs
are places where we might place the word (initially limited only by geometry, but we then constrain this based on what's already been placed).
cool
marks where our word can be placed in unoccupied spaces (and also will be used later to count how many new spaces will be occupied by the word we pick.
sel
marks where our word can be placed such that it does not conflict with existing words.
If this leaves us with any way to place the word, we pick one of them as off
and combine the starting location with dir in loc
to see if a word has already been placed there and if we're good, we place the word and update our key. (It's extremely rare that loc matches an inuse location, so just ignoring that word works just fine).
Otherwise, we check if we're getting impatient (in which case we scrap the entire thing and start over).
Once we're done, we reshape our grid so it's square and attach the key. Here, puz
is the grid formatted for display (with a space between each column, and a numeric key for each row and column).
Example run:
<lang J> genpuz
0 1 2 3 4 5 6 7 8 9
0 t c b R g l m i r g 1 O u o v u a S t i b 2 t E f n a y n o u r 3 o d g t t s s d T T 4 a s o a r i t u e A 5 c C s b z e n b b r 6 c c e a b u m u e O 7 e h s c c s d i e w 8 d e a u d i n a r d 9 e n o s D a p E v t
aba 7 4 north│continued 1 2 se │rein 6 10 sw abacus 5 4 south│din 9 5 east │soar 5 2 east accede 5 1 south│dobbs 4 2 se │trimer 10 10 nw ani 10 6 ne │gander 1 5 se │tub 3 1 ne beer 6 9 south│grim 1 10 west │tuft 1 1 se bit 2 10 west │lung 1 6 sw │vaduz 10 9 nw bud 6 8 north│oases 10 3 north│vast 2 4 se busy 6 9 nw │our 3 8 east │web 8 10 nw chen 7 2 south│picasso 10 7 nw │ </lang>
Java
<lang java>import java.io.*; import static java.lang.String.format; import java.util.*;
public class WordSearch {
static class Grid { int numAttempts; char[][] cells = new char[nRows][nCols]; List<String> solutions = new ArrayList<>(); }
final static int[][] dirs = {{1, 0}, {0, 1}, {1, 1}, {1, -1}, {-1, 0}, {0, -1}, {-1, -1}, {-1, 1}};
final static int nRows = 10; final static int nCols = 10; final static int gridSize = nRows * nCols; final static int minWords = 25;
final static Random rand = new Random();
public static void main(String[] args) { printResult(createWordSearch(readWords("unixdict.txt"))); }
static List<String> readWords(String filename) { List<String> words = new ArrayList<>(); try (Scanner sc = new Scanner(new FileReader(filename))) { while (sc.hasNext()) { String s = sc.next().trim().toLowerCase(); if (s.matches("^[a-z]{3,}$")) words.add(s); } } catch (FileNotFoundException e) { System.out.println(e); } return words; }
static Grid createWordSearch(List<String> words) { Grid grid = null; int numAttempts = 0;
outer: while (++numAttempts < 100) { Collections.shuffle(words);
grid = new Grid(); int messageLen = placeMessage(grid, "Rosetta Code"); int target = gridSize - messageLen;
int cellsFilled = 0; for (String word : words) { cellsFilled += tryPlaceWord(grid, word); if (cellsFilled == target && grid.solutions.size() >= minWords) { grid.numAttempts = numAttempts; break outer; } } }
return grid; }
static int placeMessage(Grid grid, String msg) { msg = msg.toUpperCase().replaceAll("[^A-Z]", "");
int messageLen = msg.length(); if (messageLen > 0 && messageLen < gridSize) { int gapSize = gridSize / messageLen;
for (int i = 0; i < messageLen; i++) { int pos = i * gapSize + rand.nextInt(gapSize); grid.cells[pos / nCols][pos % nCols] = msg.charAt(i); } } return messageLen; }
static int tryPlaceWord(Grid grid, String word) { int randDir = rand.nextInt(dirs.length); int randPos = rand.nextInt(gridSize);
for (int dir = 0; dir < dirs.length; dir++) { dir = (dir + randDir) % dirs.length;
for (int pos = 0; pos < gridSize; pos++) { pos = (pos + randPos) % gridSize;
int lettersPlaced = tryLocation(grid, word, dir, pos); if (lettersPlaced > 0) return lettersPlaced; } } return 0; }
static int tryLocation(Grid grid, String word, int dir, int pos) {
int r = pos / nCols; int c = pos % nCols; int len = word.length();
// check bounds if ((dirs[dir][0] == 1 && (len + c) > nCols) || (dirs[dir][0] == -1 && (len - 1) > c) || (dirs[dir][1] == 1 && (len + r) > nRows) || (dirs[dir][1] == -1 && (len - 1) > r)) return 0;
int rr, cc, i, overlaps = 0;
// check cells for (i = 0, rr = r, cc = c; i < len; i++) { if (grid.cells[rr][cc] != 0 && grid.cells[rr][cc] != word.charAt(i)) return 0; cc += dirs[dir][0]; rr += dirs[dir][1]; }
// place for (i = 0, rr = r, cc = c; i < len; i++) { if (grid.cells[rr][cc] == word.charAt(i)) overlaps++; else grid.cells[rr][cc] = word.charAt(i);
if (i < len - 1) { cc += dirs[dir][0]; rr += dirs[dir][1]; } }
int lettersPlaced = len - overlaps; if (lettersPlaced > 0) { grid.solutions.add(format("%-10s (%d,%d)(%d,%d)", word, c, r, cc, rr)); }
return lettersPlaced; }
static void printResult(Grid grid) { if (grid == null || grid.numAttempts == 0) { System.out.println("No grid to display"); return; } int size = grid.solutions.size();
System.out.println("Attempts: " + grid.numAttempts); System.out.println("Number of words: " + size);
System.out.println("\n 0 1 2 3 4 5 6 7 8 9"); System.out.print(""); for (int r = 0; r < nRows; r++) { System.out.printf("%n%d ", r); for (int c = 0; c < nCols; c++) System.out.printf(" %c ", grid.cells[r][c]); }
System.out.println("\n");
for (int i = 0; i < size - 1; i += 2) { System.out.printf("%s %s%n", grid.solutions.get(i), grid.solutions.get(i + 1)); } if (size % 2 == 1) System.out.println(grid.solutions.get(size - 1)); }
}</lang>
Attempts: 2 Number of words: 27 0 1 2 3 4 5 6 7 8 9 0 R p d i o r o t r a 1 O a o e s b l o c S 2 m s t l f e t l a y 3 E t e i y o t s T i 4 e y l b t g r s p l 5 r l T i A h o e e l 6 o e l h t j c n s C 7 z l o u a a O t a t 8 u k r g c n D z i l 9 o t r a v e l E v w rototill (8,0)(1,7) polygonal (1,0)(9,8) fill (4,2)(1,5) goer (3,8)(0,5) travel (1,9)(6,9) deforest (2,0)(9,7) toroid (7,0)(2,0) truth (1,9)(5,5) estes (8,5)(4,1) ipecac (9,3)(4,8) ouzo (0,9)(0,6) pasty (1,0)(1,4) dote (2,0)(2,3) lay (7,2)(9,2) witch (9,9)(5,5) han (3,6)(5,8) bloc (5,1)(8,1) ill (9,3)(9,5) slot (7,3)(7,0) art (9,0)(7,0) ore (0,6)(0,4) bye (3,4)(5,2) elk (1,6)(1,8) jan (5,6)(5,8) liz (9,8)(7,8) dam (2,0)(0,2) via (8,9)(8,7)
zkl
Repeat words allowed <lang zkl>fcn buildVectors(R,C){ //-->up to 8 vectors of wild card strings
var [const] dirs=T(T(1,0), T(0,1), T(1,1), T(1,-1), T(-1,0),T(0,-1), T(-1,-1), T(-1,1)); vs,v:=List(),List(); foreach dr,dc in (dirs){ v.clear(); r,c:=R,C; while( (0<=r<10) and (0<=c<10) ){ v.append(grid[r][c]); r+=dr; c+=dc; } vs.append(T(v.concat(), // eg "???e??????" would match "cohen" or "mineral" dr,dc)); } vs.filter(fcn(v){ v[0].len()>2 }).shuffle()
} fcn findFit(vs,words){ //-->(n, word) ie (nth vector,word), empty vs not seen
do(1000){ foreach n,v in (vs.enumerate()){ do(10){ // lots of ties word:=words[(0).random(nwds)]; if(word.matches(v[0][0,word.len()])) return(word,n); // "??" !match "a }}} False
} fcn pasteWord(r,c, dr,dc, word) // jam word into grid along vector
{ foreach char in (word){ grid[r][c]=char; r+=dr; c+=dc; } }
fcn printGrid{
println(" 0 1 2 3 4 5 6 7 8 9"); foreach n,line in (grid.enumerate()){ println(n," ",line.concat(" ")) }
} fcn stuff(msg){ msg=msg.toUpper() : Utils.Helpers.cycle(_);
foreach r,c in (10,10){ if(grid[r][c]=="?") grid[r][c]=msg.next() }
}</lang>
<lang zkl>validWord:=RegExp(0'|[A-Za-z]+\n|).matches; File("unixdict.txt").read(*) // dictionary file to blob, copied from web
// blob to list of valid words .filter('wrap(w){ (3<w.len()<=10) and validWord(w) }) // "word\n" .howza(11).pump(List,"toLower") // convert blob to list of words, removing \n : words:=(_);
reg fitted; do{
var nwds=words.len(),grid=(10).pump(List(),(10).pump(List(),"?".copy).copy); fitted=List(); do(100){ r,c:=(0).random(10), (0).random(10); if(grid[r][c]=="?"){
vs,wn:=buildVectors(r,c), findFit(vs,words); if(wn){ w,n:=wn; pasteWord(r,c,vs[n][1,*].xplode(),w); fitted.append(T(r,c,w)); }
}}
}while(fitted.len()<25);
stuff("RosettaCode"); printGrid(); println(fitted.len()," words fitted"); fitted.pump(Console.println, T(Void.Read,3,False),
fcn(ss){ vm.arglist.pump(String, fcn([(r,c,w)]){ "%-19s".fmt("[%d,%d]: %s ".fmt(r,c,w)) }) }
);</lang>
- Output:
0 1 2 3 4 5 6 7 8 9 0 n a n n a o r g d c 1 z i R n n a s d n a 2 p e s e y O w s o n 3 o S n e l h e a p o 4 t w b b l a e n m g 5 i n a a a l n m u a 6 o b o n n o e u t e 7 n h r o i g y n a n 8 s t e r n e l g n a 9 f r o n t n E e t l 26 words fitted [3,5]: halogen [0,4]: anna [2,0]: potion [9,2]: orion [5,4]: allyn [4,8]: mutant [5,7]: mung [4,1]: wan [1,6]: sweeney [7,1]: hen [3,8]: pond [2,7]: san [6,1]: bonn [1,0]: zen [0,9]: canoga [9,0]: front [4,2]: bangle [0,7]: groan [4,3]: been [9,9]: lane [2,2]: sin [1,7]: dna [8,4]: noon [8,0]: stern