Tree from nesting levels: Difference between revisions

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[[[3, 3, 3]], 1, 1, [[3, 3, 3]]]
</pre>
 
=={{header|Delphi}}==
{{works with|Delphi|6.0}}
{{libheader|SysUtils,StdCtrls}}
 
 
<syntaxhighlight lang="Delphi">
 
 
const TreeData1: array [0..0] of integer = (0);
const TreeData2: array [0..2] of integer = (1, 2, 4);
const TreeData3: array [0..3] of integer = (3, 1, 3, 1);
const TreeData4: array [0..3] of integer = (1, 2, 3, 1);
const TreeData5: array [0..3] of integer = (3, 2, 1, 3);
const TreeData6: array [0..7] of integer = (3, 3, 3, 1, 1, 3, 3, 3);
 
 
function GetDataString(Data: array of integer): string;
var I: integer;
begin
Result:='[';
for I:=0 to High(Data) do
begin
if I<>0 then Result:=Result+', ';
Result:=Result+IntToStr(Data[I]);
end;
Result:=Result+']';
end;
 
 
function GetNestingLevel(Data: array of integer): string;
var Level,Level2: integer;
var I,J,HLen: integer;
begin
Level:=0;
Result:='';
for I:=0 to High(Data) do
begin
Level2:=Data[I];
if Level2>Level then for J:=Level to Level2-1 do Result:=Result+'['
else if Level2<Level then
begin
for J:=Level-1 downto Level2 do Result:=Result+']';
Result:=Result+', ';
end
else if Level2=0 then
begin
Result:='[]';
break;
end
else Result:=Result+', ';
Result:=Result+IntToStr(Level2);
Level:=Level2;
if (I<High(Data)) and (Level<Data[I+1]) then Result:=Result+', ';
end;
for J:=Level downto 1 do Result:=Result+']';
end;
 
 
procedure ShowNestData(Memo: TMemo; Data: array of integer);
begin
Memo.Lines.Add(GetDataString(Data)+' Nests to: ');
Memo.Lines.Add(GetNestingLevel(Data));
Memo.Lines.Add('');
end;
 
procedure ShowNestingLevels(Memo: TMemo);
var S: string;
begin
ShowNestData(Memo,TreeData1);
ShowNestData(Memo,TreeData2);
ShowNestData(Memo,TreeData3);
ShowNestData(Memo,TreeData4);
ShowNestData(Memo,TreeData5);
ShowNestData(Memo,TreeData6);
end;
 
 
 
</syntaxhighlight>
{{out}}
<pre>
[0] Nests to:
[]
 
[1, 2, 4] Nests to:
[1, [2, [[4]]]]
 
[3, 1, 3, 1] Nests to:
[[[3]], 1, [[3]], 1]
 
[1, 2, 3, 1] Nests to:
[1, [2, [3]], 1]
 
[3, 2, 1, 3] Nests to:
[[[3], 2], 1, [[3]]]
 
[3, 3, 3, 1, 1, 3, 3, 3] Nests to:
[[[3, 3, 3]], 1, 1, [[3, 3, 3]]]
 
 
Elapsed Time: 21.513 ms.
 
</pre>
 
 
=={{header|Fōrmulæ}}==
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