Total circles area: Difference between revisions

+ C entry
(+ comment efficiency in Python entry)
(+ C entry)
Line 40:
See also (idea originally from Steve132):
http://www.reddit.com/r/dailyprogrammer/comments/zff9o/9062012_challenge_96_difficult_water_droplets/
 
=={{header|C}}==
This program uses a Montecarlo sampling. For this problem this is less efficient (converges more slowly) than a regular grid sampling, like in the Python entry.
<lang c>#include <stdio.h>
#include <stdlib.h>
 
typedef struct { double x, y, r; } Circle;
 
const Circle circles[] = {
{ 1.6417233788, 1.6121789534, 0.0848270516},
{-1.4944608174, 1.2077959613, 1.1039549836},
{ 0.6110294452, -0.6907087527, 0.9089162485},
{ 0.3844862411, 0.2923344616, 0.2375743054},
{-0.2495892950, -0.3832854473, 1.0845181219},
{ 1.7813504266, 1.6178237031, 0.8162655711},
{-0.1985249206, -0.8343333301, 0.0538864941},
{-1.7011985145, -0.1263820964, 0.4776976918},
{-0.4319462812, 1.4104420482, 0.7886291537},
{ 0.2178372997, -0.9499557344, 0.0357871187},
{-0.6294854565, -1.3078893852, 0.7653357688},
{ 1.7952608455, 0.6281269104, 0.2727652452},
{ 1.4168575317, 1.0683357171, 1.1016025378},
{ 1.4637371396, 0.9463877418, 1.1846214562},
{-0.5263668798, 1.7315156631, 1.4428514068},
{-1.2197352481, 0.9144146579, 1.0727263474},
{-0.1389358881, 0.1092805780, 0.7350208828},
{ 1.5293954595, 0.0030278255, 1.2472867347},
{-0.5258728625, 1.3782633069, 1.3495508831},
{-0.1403562064, 0.2437382535, 1.3804956588},
{ 0.8055826339, -0.0482092025, 0.3327165165},
{-0.6311979224, 0.7184578971, 0.2491045282},
{ 1.4685857879, -0.8347049536, 1.3670667538},
{-0.6855727502, 1.6465021616, 1.0593087096},
{ 0.0152957411, 0.0638919221, 0.9771215985}};
 
double min(const double a, const double b) { return a <= b ? a : b; }
 
double max(const double a, const double b) { return a >= b ? a : b; }
 
double uniform(const double a, const double b) {
const double r01 = rand() / (double)RAND_MAX;
return a + (b - a) * r01;
}
 
int main() {
const size_t n_circles = sizeof(circles) / sizeof(Circle);
 
// Initialize the bounding box of the circles.
double x_min = 1e100;
double x_max = -1e100;
double y_min = 1e100;
double y_max = -1e100;
 
// Compute the bounding box of the circles.
for (size_t i = 0; i < n_circles; i++) {
const Circle c = circles[i];
x_min = min(x_min, c.x - c.r);
x_max = max(x_max, c.x + c.r);
y_min = min(y_min, c.y - c.r);
y_max = max(y_max, c.y + c.r);
}
 
// Montecarlo sampling.
srand(1);
const size_t n_samples = 100 * 1000 * 1000;
 
size_t hits = 0;
 
for (size_t i = 0; i < n_samples; i++) {
const double x = uniform(x_min, x_max);
const double y = uniform(y_min, y_max);
for (size_t j = 0; j < n_circles; j++) {
const double dx = x - circles[j].x;
const double dy = y - circles[j].y;
if ((dx * dx + dy * dy) <= (circles[j].r * circles[j].r)) {
hits++;
break;
}
}
}
 
printf("Approximated area: %.8f\n",
(double)(x_max - x_min) *
(double)(y_max - y_min) *
((double)hits / n_samples));
 
return 0;
}</lang>
{{out}}
<pre>Approximated area: 21.56262288</pre>
 
=={{header|Python}}==