Text processing/Max licenses in use: Difference between revisions
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(mx { D) ,~ 'Maximum simultaneous license use is ' , ' at the following times:' ,~ ": {. mx { lu |
(mx { D) ,~ 'Maximum simultaneous license use is ' , ' at the following times:' ,~ ": {. mx { lu |
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2008/10/03_08:39:34 |
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=={{header|Python}}== |
=={{header|Python}}== |
Revision as of 02:54, 4 October 2008
You are encouraged to solve this task according to the task description, using any language you may know.
A company currently pays a fixed sum for the use of a particular licensed software package. In determining if it has a good deal it decides to calculate its maximum use of the software from its license management log file.
Assume the softwares file faithfully records a checkout event when a copy of the software starts and a checkin event when the software finishes. An example of checkout and checkin events are:
License OUT @ 2008/10/03_23:51:05 for job 4974 ... License IN @ 2008/10/04_00:18:22 for job 4974
Save the 10,000 line log file from here* into a local file then write a program to scan the file extracting both the maximum licenses that were out at any time, and the time(s) at which this occurs.
- Note: The page uses javascript to display a text file, so it may be best to cut-n-paste from a browser to a text file rather than downloading the URL.
J
NB. Verb to parse data cutf =: [: ({.~ _ , 43 >. {:@:$) (];._2~ =&LF) cut =: (<;.2~ '' ; 7 11 13 33 37 41 (i.@:] e. (,<:)) {:@:$)@:cutf NB. Parse data, select columns 'D J' =: 3 6 { |: cut CR -.~ 1!:1 ::(''"_) <'licenses.txt' NB. Calculate number of licenses used at any given time lu =: +/ ~:/\"1 = 0".J NB. Find the maxima mx =: (I.@:= >./) lu NB. Output results (mx { D) ,~ 'Maximum simultaneous license use is ' , ' at the following times:' ,~ ": {. mx { lu
2008/10/03_08:39:34 2008/10/03_08:40:40
Python
Python 2.6 <python>def max_out(logfile):
maxout = 0 maxouttimes = [] out = 0 for line in logfile: direction = line[8] time = line[14:33] if direction == 'O': out += 1 if out > maxout: maxout = out maxouttimes = [time] elif out == maxout: maxouttimes.append(time) else: out -=1 return maxout, maxouttimes
if __name__ == '__main__':
log = file('license_example_log.txt') maxout, maxouttimes = max_out(log) log.close() print "Maximum simultaneous license use is %i at the following times:\n %s" % ( maxout, '\n '.join(maxouttimes))</python>
Example output:
Maximum simultaneous license use is 99 at the following times: 2008/10/03_08:39:34 2008/10/03_08:40:40