Talk:Zumkeller numbers: Difference between revisions

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Alright, so I'm not seeing any overflow here. the variable d points to a vector of unsigned ints, stored in an array, so d.size() can become extremely large. I think the largest set I saw was 88 divisors, and the sum did not overflow. I also am still not seeing the bad outputs you did, so I'm not sure what's going on there, except for 99504. I use the condition odd|n divisors > 24 but I don't think that holds for large N if N is even. 99504 may be the first number that gets through. Given the problem description I didn't anticipate large even numbers to be evaluated; they get filtered before printing to console anyhow, so I think I wrote it that way for efficiency. I really don't remember. If you remove that condition the output looks fine through the first 100 000, but it will take a very long time. Probably, if you want to improve on this, there are a few handy properties of the sequence that could be used to bring time complexity down. But really, changing the data structure for d to make insertion faster and working with base 2 throughout instead of converting for no good reason would really speed up computation time. And there are lots of places to trade space for time, too.
--[[User:Mckann|Mckann]] ([[User talk:Mckann|talk]]) 23:38, 12 May 2021 (UTC)
::My real intention was to find a justification for <pre>or n has at least 24 divisors it's a zum!</pre>
:: There is no.<BR>In '[[oeis:A083207|OEIS:A083207 - Zumkeller numbers]] someone stated and checked <pre>All 205283 odd abundant numbers less than 10^8 that have even abundance are Zumkeller numbers. - T. D. Noe, Nov 14 2010</pre> something one can use.
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