Talk:Stair-climbing puzzle: Difference between revisions
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The problem is ambiguous as stated. It says to climb one step up, not climb up one step up from the starting position. Thus the original C# code that was there solved the 'climb one step up'. <span style="font-size: smaller;" class="autosigned">—Preceding unsigned comment added by [[Special:Contributions/71.59.209.100|71.59.209.100]]</span> |
The problem is ambiguous as stated. It says to climb one step up, not climb up one step up from the starting position. Thus the original C# code that was there solved the 'climb one step up'. <span style="font-size: smaller;" class="autosigned">—Preceding unsigned comment added by [[Special:Contributions/71.59.209.100|71.59.209.100]]</span> |
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:Okay, I've made it more explicit. —[[User:Underscore|Underscore]] 00:30, 7 November 2009 (UTC) |
:Okay, I've made it more explicit. —[[User:Underscore|Underscore]] 00:30, 7 November 2009 (UTC) |
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Am I wrong or recursion can be simply avoided since the "action" is done indeed into step? So the following C code |
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<lang c> |
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void step_up() |
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{ |
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while ( !step() ) ; |
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} |
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</lang> |
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would work? Why is used recursion if indeed <tt>step_up</tt> does nothing more? ... --[[User:ShinTakezou|ShinTakezou]] 10:30, 7 November 2009 (UTC) |
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Revision as of 10:30, 7 November 2009
Problem statement
The problem is ambiguous as stated. It says to climb one step up, not climb up one step up from the starting position. Thus the original C# code that was there solved the 'climb one step up'. —Preceding unsigned comment added by 71.59.209.100
- Okay, I've made it more explicit. —Underscore 00:30, 7 November 2009 (UTC)
Am I wrong or recursion can be simply avoided since the "action" is done indeed into step? So the following C code <lang c> void step_up() {
while ( !step() ) ;
} </lang> would work? Why is used recursion if indeed step_up does nothing more? ... --ShinTakezou 10:30, 7 November 2009 (UTC)