Talk:Long multiplication

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Revision as of 09:34, 26 February 2009 by rosettacode>NevilleDNZ (Agreed.)

BigNum

Wouldn't it be appropriate to replace this task with arbitrary-precision arithmetic implementation? I.e. long to long +, -, *, /, and long to short +, -, *, /. The divisions are to be implemented in a complete form (result + remainder).

Hi Dmitry-kazakov. Yes that makes sense. I'll switch it. NevilleDNZ 09:34, 26 February 2009 (UTC)

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