Talk:Exponentiation order: Difference between revisions

→‎Functions: a - b - c can also be right associative
(→‎Functions: Existing examples show differences between languages)
(→‎Functions: a - b - c can also be right associative)
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::::"If that expression would be treated universally the same, there wouldn't be a need for this Rosetta Code task." Can you give an example of a place where it is not right associative? Because I precisely have trouble figuring out why there's need for this Rosetta Code task. --[[User:Spoon!|Spoon!]] ([[User talk:Spoon!|talk]]) 09:06, 19 March 2014 (UTC)
:::::The existing examples show a difference. The first Perl 6 example shows that 5**3**2 = 5**(3**2) and the REXX example shows that 5**3**2 = (5**3)**2. --[[User:Mwn3d|Mwn3d]] ([[User talk:Mwn3d|talk]]) 13:05, 19 March 2014 (UTC)
 
::::::Likewise, a - b - c is also "swimming in vagueness" if you might or might not be programming in an APL derivative, where pretty much everything is right associative, if I recall correctly. --[[User:TimToady|TimToady]] ([[User talk:TimToady|talk]]) 21:16, 19 March 2014 (UTC)
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