Talk:De Polignac numbers: Difference between revisions
→Efficient algorithm
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Simply find the powers of 2 less than N, subtract each from N, and check if any remainder is a prime. If any is, it is '''not''' a de Polignac number. Short circuit and move on. --[[User:Thundergnat|Thundergnat]] ([[User talk:Thundergnat|talk]]) 22:04, 27 September 2022 (UTC)
:2nd sentence reads better if you delete "test" and replace "with" with "to". 3rd & 4th sentences would make a wonderful comment for the Raku entry 😉 --[[User:Petelomax|Petelomax]] ([[User talk:Petelomax|talk]]) 11:54, 28 September 2022 (UTC)
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