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Talk:Combinations: Difference between revisions
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Thanked Nigel Galloway for answering my question.
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Strictlly speaking, combinations with repetiotions 5 of 5 give you 126 variants, just combinations give you just 1 variant
Formula for comb. with repet: http://hijos.ru/wp-content/ql-cache/quicklatex-7f6e17e6e05e9a62c1188bd95ff7e8ad.gif
Also, we should distinguish third thing - when we have a deal with combinations with repetitions with additional condition.
Sorry for this sentence looking like folk verses.
With respect to you, Ivan Gavryushin (dcc0@).
== PARI/GP ==
The function definition is:<br />
c(n,k,r,d)
c = combinations<br />
n = number of objects<br />
k = sample size<br />
r = ?<br />
d = ?
What are r and d? [[User:Chuck Coker|Chuck Coker]] ([[User talk:Chuck Coker|talk]]) 02:00, 31 July 2019 (UTC)
:You may not be familiar with recursive patterns. The function c is recursive. d is a count of the current depth, r is sort of an accumulator keeping the permutation thus far. So when d=k the combination is complete and r is printed.--[[User:Nigel Galloway|Nigel Galloway]] ([[User talk:Nigel Galloway|talk]]) 11:16, 31 July 2019 (UTC)
:: Thanks for the info. [[User:Chuck Coker|Chuck Coker]] ([[User talk:Chuck Coker|talk]]) 12:30, 31 July 2019 (UTC)
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