Sum of the digits of n is substring of n: Difference between revisions

{{out}}

<pre>0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919</pre>

=={{header|D}}==

{{trans|C++}}

<lang d>import std.algorithm;

import std.conv;

import std.stdio;

int digitSum(int n) {

int s = 0;

do {

s += n % 10;

} while (n /= 10);

return s;

}

void main() {

foreach (i; 0 .. 1000) {

if (i.to!string.canFind(digitSum(i).to!string)) {

write(i, ' ');

}

}

writeln;

}</lang>