Sum multiples of 3 and 5: Difference between revisions

=={{header|Scala}}==

<lang scala>def sum35( max:BigInt ) : BigInt = max match {

// Simplest solution but limited to Ints only

case j if j < 100000 => (1 until j.toInt).filter( i => i % 3 == 0 || i % 5 == 0 ).sum