Anonymous user
Sudan function: Difference between revisions
add ruby implementation
(Added Phix,moved PHP into order) |
(add ruby implementation) |
||
Line 446:
[1] "F(1,3,3) = 35"
</pre>
=={{header|Ruby}}==
<lang ruby>
def sudan(n, x, y)
return x + y if n == 0
return x if y == 0
sudan(n - 1, sudan(n, x, y - 1), sudan(n, x, y - 1) + y)
end
</lang>
Output
<pre>
puts sudan(1, 3, 3)
> 35
</pre>
=={{header|Vlang}}==
| |||