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Pascal's triangle/Puzzle: Difference between revisions
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=={{header|Ada}}==
The solution makes an upward run symbolically, though excluding Z. After that two blocks (1,1) and (3,1) being known yield a 2x2 linear system, from which X and Y are determined. Finally each block is revisited and printed.
<lang ada>
with Ada.Text_IO; use Ada.Text_IO;
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end loop;
end Pyramid_of_Numbers;
</
Sample output:
<pre>
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=={{header|Python}}==
{{works with|Python|2.4+}}
<
# [151]
# [ ] [ ]
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addlConstraint = { 'X':1, 'Y':-1, 'Z':1, '1':0 }
SolvePyramid( p, addlConstraint)
</
Output:
<pre>Constraint Equations:
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