Mind boggling card trick: Difference between revisions
Added Easylang
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Drumroll...
There were 7!
</pre>
=={{header|EasyLang}}==
{{trans|Wren}}
<syntaxhighlight>
proc shuffle . a[] .
for i = len a[] downto 2
r = randint i
swap a[r] a[i]
.
.
func$ a2str a[] .
for v in a[]
r$ &= strchar v & " "
.
return r$
.
R = strcode "R"
B = strcode "B"
for i to 26
pack[] &= R
pack[] &= B
.
shuffle pack[]
#
for i = 1 step 2 to 51
if pack[i] = B
black[] &= pack[i + 1]
else
red[] &= pack[i + 1]
.
discard[] &= pack[i]
.
print "After dealing the cards the state of the stacks is:"
print " Red : " & a2str red[]
print " Black : " & a2str black[]
print " Discard: " & a2str discard[]
for i to len red[]
rp[] &= i
.
for i to len black[]
bp[] &= i
.
shuffle rp[]
shuffle bp[]
n = randint lower len red[] len black[]
len rp[] n
len bp[] n
#
for i to n
h = red[rp[i]]
red[rp[i]] = black[bp[i]]
black[bp[i]] = h
.
print ""
print "After swapping " & n & " cards the state of the stacks is:"
print " Red : " & a2str red[]
print " Black : " & a2str black[]
#
for c in red[]
red += if c = R
.
for c in black[]
black += if c = B
.
print ""
print "The number of red cards in the red stack = " & red
print "The number of black cards in the black stack = " & black
if red = black
print "So the asssertion is correct!"
.
</syntaxhighlight>
{{out}}
<pre>
After dealing the cards the state of the stacks is:
Red : B B B R B B B R R R R R R B
Black : B B B R R B R B B R R B
Discard: R B R B B R B R R B B R R R R R R R R B B B B B R B
After swapping 7 cards the state of the stacks is:
Red : R R B R R B B R B R B R R B
Black : B B R B R B B B R B R B
The number of red cards in the red stack = 8
The number of black cards in the black stack = 8
So the asssertion is correct!
</pre>
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