Anonymous user
FizzBuzz: Difference between revisions
added APL
m (→Second try) |
(added APL) |
||
Line 39:
Or simply:
FOR i TO 100 DO print(((i%*15=0|"FizzBuzz"|:i%*3=0|"Fizz"|:i%*5=0|"Buzz"|i),new line)) OD
=={{header|APL}}==
⎕IO←0
(L,'Fizz' 'Buzz' 'FizzBuzz')[¯1+(L×W=0)+W←(100×~0=W)+W←⊃+/1 2×0=3 5|⊂L←1+⍳100]
=={{header|AWK}}==
| |||