Catalan numbers: Difference between revisions

m
Line 2,310:
=={{header|EasyLang}}==
<syntaxhighlight lang="text">
procfunc catalan n . ans .
if n = 0
ans = return 1
else .
return call2 * (2 * n - 1) * catalan (n - 1) hdiv (1 + n)
ans = 2 * (2 * n - 1) * h div (1 + n)
.
.
for i = 0 to 14
call catalan i h
print h
.
</syntaxhighlight>
{{out}}
<pre>
1
1
2
5
14
42
132
429
1430
4862
16796
58786
208012
742900
2674440
</pre>
 
=={{header|EchoLisp}}==
2,078

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