Count in octal: Difference between revisions
Added ALGOL-M example
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8r00000000020
8r00000000021
</pre>
=={(header|ALGOL-M}}==
<syntaxhighlight lang = "ALGOL">
begin
% display n on console in octal format %
procedure putoct(n);
integer n;
begin
integer digit, n8;
string(1) array octdig[0:7];
octdig[0] := "0"; octdig[1] := "1"; octdig[2] := "2";
octdig[3] := "3"; octdig[4] := "4"; octdig[5] := "5";
octdig[6] := "6"; octdig[7] := "7";
n8 := n / 8;
if n8 <> 0 then putoct(n8); % recursive call %
digit := n - (n / 8) * 8; % n mod 8 %
writeon(octdig[digit]);
end;
integer i, maxint;
i := 1;
maxint := 16383;
comment
Excercise the procedure by counting up in octal as
far as possible. In doing so, we have to take some
care, because integer variables are set to 1 on
overflow, and if that happens, the loop will simply
start over, and the program will run forever;
while i < maxint do % we need to stop one shy %
begin
write("");
putoct(i);
i := i + 1;
end;
% display the final value %
write("");
putoct(maxint);
end
</syntaxhighlight>
{{out}}
First and last 10 lines of output
<pre>
1
2
3
4
5
6
7
10
11
12
...
37766
37767
37770
37771
37772
37773
37774
37775
37776
37777
</pre>
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