Super-d numbers: Difference between revisions
→{{header|Go}}: Simplified somewhat, about 10% quicker than before.
(Added Fōrmulæ) |
(→{{header|Go}}: Simplified somewhat, about 10% quicker than before.) |
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=={{header|Go}}==
Simple brute force approach and so not particularly quick - about 2.
<lang go>package main
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"time"
)
p := new(big.Int).Set(b)▼
for i := 2; i <= exp; i++ {▼
func main() {
start := time.Now()
rd := []string{"22", "333", "4444", "55555", "666666", "7777777", "88888888", "999999999"}
fmt.Printf("First 10 super-%d numbers:\n", i)
k := new(big.Int)
count := 0
inner:
for j :=
k.
ix := strings.Index(k.String(), rd[ii-2])
if ix >= 0 {
count++
Line 121 ⟶ 115:
First 10 super-3 numbers:
261 462 471 481 558 753 1036 1046 1471 1645
found in
First 10 super-4 numbers:
1168 4972 7423 7752 8431 10267 11317 11487 11549 11680
found in
First 10 super-5 numbers:
4602 5517 7539 12955 14555 20137 20379 26629 32767 35689
found in
First 10 super-6 numbers:
27257 272570 302693 323576 364509 502785 513675 537771 676657 678146
found in
First 10 super-7 numbers:
140997 490996 1184321 1259609 1409970 1783166 1886654 1977538 2457756 2714763
found in
First 10 super-8 numbers:
185423 641519 1551728 1854230 6415190 12043464 12147605 15517280 16561735 18542300
found in
First 10 super-9 numbers:
17546133 32613656 93568867 107225764 109255734 113315082 121251742 175461330 180917907 182557181
found in
</pre>
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