Welch's t-test: Difference between revisions

<math> p=1-\frac{1}{2}\times\frac{\int_0^\frac{\nu}{t^2+\nu} r^{\frac{\nu}{2}-1}\,(1-r)^{-0.5}\,\mathrm{d}r}{\frac{exp((\ln(\Gamma(x)) + \frac{\nu}{2})ln(\Gamma(0.5y)}{)) - \ln(\Gamma(\frac{\nux+2}{2}y)))}} </math>

<math> p = 1-\frac{1}{2}\Gamma\left(\frac{\nu+2}{2}\right)times\frac{\int_0^\frac{\nu}{t^2+\nu} \frac{r^{\frac{\nu}{2}-1}}{\sqrt{1-r}}\,\mathrm{d}r}{ \exp((\ln(\Gamma(x)) + \frac{ln(\nu}{2}Gamma(y))) - \ln(\Gamma(0.5x+y))) }</math>