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General FizzBuzz: Difference between revisions
→{{header|Python}}: Modified second example to use a generator; added another example.
m (→{{header|Python}}: Corrected mistake.) |
(→{{header|Python}}: Modified second example to use a generator; added another example.) |
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Line 1,483:
'''Alternative version - generator using counters instead of modulo'''
{{works with|Python|3.x}}
<lang Python>n = 100
Line 1,492:
def fizzbuzz(n=n, mods=mods):
cnts = {k:0 for k in mods.keys()}
for i in range(1,n+1):
for k,v in cnts.items():
v += 1
Line 1,502 ⟶ 1,501:
v = 0
res += mods[k]
wr = True▼
cnts[k] = v
if not wr:▼
▲ res += str(i)
if __name__ == '__main__':
n = int(input())
mods = { int(k): v for k,v in (input().split(maxsplit=1) for _ in range(3)) }
</lang>
'''Another version, using ranges with step 3, 5, etc.'''
<lang Python>from collections import defaultdict
def fizzbuzz(n=100, mods={3:'Fizz', 5:'Buzz'}):
res = defaultdict(str)
for num, name in mods.items():
for i in range(num, n+1, num):
return '\n'.join(res[i] or str(i) for i in range(1,n+1))
</lang>
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