Commatizing numbers: Difference between revisions
Added Go
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$-140,000±100 millions.
6/9/1946 was a good year for some.</pre>
=={{header|Go}}==
{{trans|Kotlin}}
<lang go>package main
import (
"fmt"
"regexp"
"strings"
)
var reg = regexp.MustCompile(`(\.[0-9]+|[1-9]([0-9]+)?(\.[0-9]+)?)`)
func reverse(s string) string {
r := []rune(s)
for i, j := 0, len(r)-1; i < len(r)/2; i, j = i+1, j-1 {
r[i], r[j] = r[j], r[i]
}
return string(r)
}
func commatize(s string, startIndex, period int, sep string) string {
if startIndex < 0 || startIndex >= len(s) || period < 1 || sep == "" {
return s
}
m := reg.FindString(s[startIndex:]) // this can only contain ASCII characters
if m == "" {
return s
}
splits := strings.Split(m, ".")
ip := splits[0]
if len(ip) > period {
pi := reverse(ip)
for i := (len(ip) - 1) / period * period; i >= period; i -= period {
pi = pi[:i] + sep + pi[i:]
}
ip = reverse(pi)
}
if strings.Contains(m, ".") {
dp := splits[1]
if len(dp) > period {
for i := (len(dp) - 1) / period * period; i >= period; i -= period {
dp = dp[:i] + sep + dp[i:]
}
}
ip += "." + dp
}
return s[:startIndex] + strings.Replace(s[startIndex:], m, ip, 1)
}
func main() {
tests := [...]string{
"123456789.123456789",
".123456789",
"57256.1D-4",
"pi=3.14159265358979323846264338327950288419716939937510582097494459231",
"The author has two Z$100000000000000 Zimbabwe notes (100 trillion).",
"-in Aus$+1411.8millions",
"===US$0017440 millions=== (in 2000 dollars)",
"123.e8000 is pretty big.",
"The land area of the earth is 57268900(29% of the surface) square miles.",
"Ain't no numbers in this here words, nohow, no way, Jose.",
"James was never known as 0000000007",
"Arthur Eddington wrote: I believe there are " +
"15747724136275002577605653961181555468044717914527116709366231425076185631031296" +
" protons in the universe.",
" $-140000±100 millions.",
"6/9/1946 was a good year for some.",
}
fmt.Println(commatize(tests[0], 0, 2, "*"))
fmt.Println(commatize(tests[1], 0, 3, "-"))
fmt.Println(commatize(tests[2], 0, 4, "__"))
fmt.Println(commatize(tests[3], 0, 5, " "))
fmt.Println(commatize(tests[4], 0, 3, "."))
for _, test := range tests[5:] {
fmt.Println(commatize(test, 0, 3, ","))
}
}</lang>
{{out}}
<pre>
1*23*45*67*89.12*34*56*78*9
.123-456-789
5__7256.1D-4
pi=3.14159 26535 89793 23846 26433 83279 50288 41971 69399 37510 58209 74944 59231
The author has two Z$100.000.000.000.000 Zimbabwe notes (100 trillion).
-in Aus$+1,411.8millions
===US$0017,440 millions=== (in 2000 dollars)
123.e8000 is pretty big.
The land area of the earth is 57,268,900(29% of the surface) square miles.
Ain't no numbers in this here words, nohow, no way, Jose.
James was never known as 0000000007
Arthur Eddington wrote: I believe there are 15,747,724,136,275,002,577,605,653,961,181,555,468,044,717,914,527,116,709,366,231,425,076,185,631,031,296 protons in the universe.
$-140,000±100 millions.
6/9/1946 was a good year for some.
</pre>
=={{header|J}}==
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