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Vampire number: Difference between revisions

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→‎{{header|REXX}}: changed some comments and whitespace.
m (→‎{{header|REXX}}: changed some comments and whitespace.)
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if N>0 then do j=1260 until # >= N /*search until N vampire numbers found.*/
if length(j) // 2 then do; j=j*10 - 1; iterate; end /*adjust J*/
_=right(Jj,1); if j<!._ then iterate /*is number tenable based on last dig? */
f=vampire(j); if f=='' then iterate /*Are fangs null? Yes, not vampire. */
#=#+1 /*bump the vampire count, Vlad. */
say 'vampire number' right(#,length(N)) "is: " j', fangs=' f
end /*j*/ /* [↑] process a range of numbers. */
else do; N=abs(N); f=vampire(N) /* [↓] process onea number; getobtain fangs.*/
if f=='' then say N " isn't a vampire number."
else say N " is a vampire number, fangs=" f
end
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
vampire: procedure; parse arg ?,, $. !! bot; L=length(?); if L//2 then return !!
w=if L%//2 then return !! /* [↑]Is L an odd length? Then ¬vampire.*/
do k=1 for L; _=substr(?,k,1); $._=$._ || _; end /*k*/
do m=0 for 10; bot=bot || $.m; end /*m*/
w=L % 2
top=left( reverse(bot), w); bot=left(bot, w) /*determine limits of search*/
inc=?//2 + 1 /*? is odd? INC=2. No? INC=1*/
startbeg=max(bot, 10**(w-1)); if inc=2 then if startbeg//2==0 then startbeg=startbeg + 1
/* [↑] odd START BEG if odd INC*/
do d=startbeg to min(top, 10**w - 1) by inc
if ? // d \==0 then iterate
if verify(d, ?) \==0 then iterate
q=? % d; if d>q then iterate
if q*d//9 \== (q+d)//9 then iterate /*modulo 9 congruence test. */
if verify(q, ?) \==0 then iterate
if right(q, 1) ==0 then if right(d, 1)==0 then iterate
if length(q) \== w then iterate
dq=d || q; t=?
do i=1 for L; p=pos( substr(dq, i, 1), t)
if p==0 then iterate d; t=delstr(t, p, 1)
end /*i*/
!!=!! '['d"∙"q']'
end /*d*/
return !!</lang>
'''output''' when using the default input:
<pre>
<pre style="height:50ex">
vampire number 1 is: 1260, fangs= [21∙60]
vampire number 2 is: 1395, fangs= [15∙93]
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