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Dijkstra's algorithm: Difference between revisions
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=={{header|Tcl}}==
This solution is incorrect. Since the path is directed and f is only a sink, f cannot be in the middle of a path.
Note that this code traverses the entire set of unrouted nodes at each step, as this is simpler than computing the subset that are reachable at each stage.
<lang tcl>proc dijkstra {graph origin} {
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