Jump to content

Talk:Addition-chain exponentiation: Difference between revisions

Line 102:
::::: Never seen that error before. Blame windows. Anyway, output is<lang>[(23, 13, 10, 5, 3, 2, 1), (23, 14, 9, 5, 4, 2, 1),
(23, 18, 9, 5, 4, 2, 1), (23, 20, 10, 5, 3, 2, 1)]</lang> --[[User:Ledrug|Ledrug]] 21:11, 27 August 2011 (UTC)
:::::: Ok, yes, I have found 396 distinct ways of computing exponent 23 in six multiplications. I am going to need to read your code to see how you eliminate most of those possibilities. --[[User:Rdm|Rdm]] 21:45, 27 August 2011 (UTC)
6,962

edits

Cookies help us deliver our services. By using our services, you agree to our use of cookies.