Pythagorean triples: Difference between revisions
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Note the cute trick of adding complex numbers to add two numbers in parallel. Also, it will continue on forever, so eventually when you get tired of thrashing (at about 100 million on my computer), you can just stop it. |
Note the cute trick of adding complex numbers to add two numbers in parallel. Also, it will continue on forever, so eventually when you get tired of thrashing (at about 100 million on my computer), you can just stop it. |
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Here is an alternate version that avoids naming any scalars that can be handled by vector processing instead: |
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<lang perl6>constant @coeff = [[+1, -2, +2], [+2, -1, +2], [+2, -2, +3]], |
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[[+1, +2, +2], [+2, +1, +2], [+2, +2, +3]], |
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[[-1, +2, +2], [-2, +1, +2], [-2, +2, +3]]; |
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sub triples($limit) { |
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sub oyako(@trippy) { |
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my $perim = [+] @trippy; |
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return if $perim > $limit; |
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take (1 + ($limit div $perim)i); |
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for @coeff -> @nine { |
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oyako (map -> @three { [+] @three »*« @trippy }, @nine); |
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} |
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return; |
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} |
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my $complex = 0i + [+] gather oyako([3,4,5]); |
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"$limit => ({$complex.re, $complex.im})"; |
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} |
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for 10,100,1000 ... * -> $limit { |
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say triples $limit; |
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}</lang> |
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=={{header|Python}}== |
=={{header|Python}}== |
Revision as of 17:14, 14 July 2011
A Pythagorean triple is defined as three positive integers where , and They are called primitive triples if are coprime, that is, if their pairwise greatest common divisors . Because of their relationship through the Pythagorean theorem, a, b, and c are coprime if a and b are coprime (). Each triple forms the length of the sides of a right triangle, whose perimeter is .
Task
The task is to determine how many Pythagorean triples there are with a perimeter no larger than 100 and the number of these that are primitive.
Extra credit: Deal with large values. Can your program handle a max perimeter of 1,000,000? What about 10,000,000? 100,000,000?
Note: the extra credit is not for you to demonstrate how fast your language is compared to others; you need a proper algorithm to solve them in a timely manner.
- Cf
Ada
Translation of efficient method from C, see the WP article. Compiles on gnat/gcc.
<lang Ada>with Ada.Text_IO;
procedure Pythagorean_Triples is
type Large_Natural is range 0 .. 2**63-1; -- this is the maximum for gnat
procedure New_Triangle(A, B, C: Large_Natural; Max_Perimeter: Large_Natural; Total_Cnt, Primitive_Cnt: in out Large_Natural) is Perimeter: constant Large_Natural := A + B + C; begin if Perimeter <= Max_Perimeter then Primitive_Cnt := Primitive_Cnt + 1; Total_Cnt := Total_Cnt + Max_Perimeter / Perimeter; New_Triangle(A-2*B+2*C, 2*A-B+2*C, 2*A-2*B+3*C, Max_Perimeter, Total_Cnt, Primitive_Cnt); New_Triangle(A+2*B+2*C, 2*A+B+2*C, 2*A+2*B+3*C, Max_Perimeter, Total_Cnt, Primitive_Cnt); New_Triangle(2*B+2*C-A, B+2*C-2*A, 2*B+3*C-2*A, Max_Perimeter, Total_Cnt, Primitive_Cnt); end if; end New_Triangle;
T_Cnt, P_Cnt: Large_Natural;
begin
for I in 1 .. 9 loop T_Cnt := 0; P_Cnt := 0; New_Triangle(3,4,5, 10**I, Total_Cnt => T_Cnt, Primitive_Cnt => P_Cnt); Ada.Text_IO.Put_Line("Up to 10 **" & Integer'Image(I) & " :" & Large_Natural'Image(T_Cnt) & " Triples," & Large_Natural'Image(P_Cnt) & " Primitives"); end loop;
end Pythagorean_Triples;</lang>
Output:
Up to 10 ** 1 : 0 Triples, 0 Primitives Up to 10 ** 2 : 17 Triples, 7 Primitives Up to 10 ** 3 : 325 Triples, 70 Primitives Up to 10 ** 4 : 4858 Triples, 703 Primitives Up to 10 ** 5 : 64741 Triples, 7026 Primitives Up to 10 ** 6 : 808950 Triples, 70229 Primitives Up to 10 ** 7 : 9706567 Triples, 702309 Primitives Up to 10 ** 8 : 113236940 Triples, 7023027 Primitives Up to 10 ** 9 : 1294080089 Triples, 70230484 Primitives
C
Sample implemention; naive method, patentedly won't scale to larger numbers, despite the attempt to optimize it. Calculating up to 10000 is already a test of patience. <lang C>#include <stdio.h>
- include <stdlib.h>
typedef unsigned long long xint; typedef unsigned long ulong;
inline ulong gcd(ulong m, ulong n) { ulong t; while (n) { t = n; n = m % n; m = t; } return m; }
int main() { ulong a, b, c, pytha = 0, prim = 0, max_p = 100; xint aa, bb, cc;
for (a = 1; a <= max_p / 3; a++) { aa = (xint)a * a; printf("a = %lu\r", a); /* show that we are working */ fflush(stdout);
/* max_p/2: valid limit, because one side of triangle * must be less than the sum of the other two */ for (b = a + 1; b < max_p/2; b++) { bb = (xint)b * b; for (c = b + 1; c < max_p/2; c++) { cc = (xint)c * c; if (aa + bb < cc) break; if (a + b + c > max_p) break;
if (aa + bb == cc) { pytha++; if (gcd(a, b) == 1) prim++; } } } }
printf("Up to %lu, there are %lu triples, of which %lu are primitive\n", max_p, pytha, prim);
return 0; }</lang>output:<lang>Up to 100, there are 17 triples, of which 7 are primitive</lang> Efficient method, generating primitive triples only as described in the same WP article:<lang C>#include <stdio.h>
- include <stdlib.h>
- include <stdint.h>
/* should be 64-bit integers if going over 1 billion */ typedef unsigned long xint;
- define FMT "%lu"
xint total, prim, max_peri; xint U[][9] = {{ 1, -2, 2, 2, -1, 2, 2, -2, 3}, { 1, 2, 2, 2, 1, 2, 2, 2, 3}, {-1, 2, 2, -2, 1, 2, -2, 2, 3}};
void new_tri(xint in[]) { int i; xint t[3], p = in[0] + in[1] + in[2];
if (p > max_peri) return;
prim ++;
/* for every primitive triangle, its multiples would be right-angled too; * count them up to the max perimeter */ total += max_peri / p;
/* recursively produce next tier by multiplying the matrices */ for (i = 0; i < 3; i++) { t[0] = U[i][0] * in[0] + U[i][1] * in[1] + U[i][2] * in[2]; t[1] = U[i][3] * in[0] + U[i][4] * in[1] + U[i][5] * in[2]; t[2] = U[i][6] * in[0] + U[i][7] * in[1] + U[i][8] * in[2]; new_tri(t); } }
int main() { xint seed[3] = {3, 4, 5};
for (max_peri = 10; max_peri <= 100000000; max_peri *= 10) { total = prim = 0; new_tri(seed);
printf( "Up to "FMT": "FMT" triples, "FMT" primitives.\n", max_peri, total, prim); } return 0; }</lang>Output<lang>Up to 10: 0 triples, 0 primitives. Up to 100: 17 triples, 7 primitives. Up to 1000: 325 triples, 70 primitives. Up to 10000: 4858 triples, 703 primitives. Up to 100000: 64741 triples, 7026 primitives. Up to 1000000: 808950 triples, 70229 primitives. Up to 10000000: 9706567 triples, 702309 primitives. Up to 100000000: 113236940 triples, 7023027 primitives.</lang>
Icon and Unicon
This uses the elegant formula (#IV) from Formulas for generating Pythagorean triples
<lang Icon> link numbers link printf
procedure main(A) # P-triples
plimit := (0 < integer(\A[1])) | 100 # get perimiter limit nonprimitiveS := set() # record unique non-primitives triples primitiveS := set() # record unique primitive triples u := 0 while (g := (u +:= 1)^2) + 3 * u + 2 < plimit / 2 do { every v := seq(1) do { a := g + (i := 2*u*v) b := (h := 2*v^2) + i c := g + h + i if (p := a + b + c) > plimit then break insert( (gcd(u,v)=1 & u%2=1, primitiveS) | nonprimitiveS, memo(a,b,c)) every k := seq(2) do { # k is for larger non-primitives if k*p > plimit then break insert(nonprimitiveS,memo(a*k,b*k,c*k) ) } } }
printf("Under perimiter=%d: Pythagorean Triples=%d including primitives=%d\n",
plimit,*nonprimitiveS+*primitiveS,*primitiveS)
every put(gcol := [] , &collections) printf("Time=%d, Collections: total=%d string=%d block=%d",&time,gcol[1],gcol[3],gcol[4]) end
procedure memo(x[]) #: return a csv string of arguments in sorted order
every (s := "") ||:= !sort(x) do s ||:= ","
return s[1:-1]
end</lang>
numbers.icn provides gcd printf.icn provides printf
The output from some sample runs with BLKSIZE=500000000 and STRSIZE=50000000 is below. It starts getting very slow after 10M at about 9 minutes (times are shown in ms. I suspect there may be faster gcd algorithms that would speed this up.
Output:
Under perimiter=10: Pythagorean Triples=0 including primitives=0 Time=3, Collections: total=0 string=0 block=0 Under perimiter=100: Pythagorean Triples=17 including primitives=7 Time=3, Collections: total=0 string=0 block=0 Under perimiter=1000: Pythagorean Triples=325 including primitives=70 Time=6, Collections: total=0 string=0 block=0 Under perimiter=10000: Pythagorean Triples=4858 including primitives=703 Time=57, Collections: total=0 string=0 block=0 Under perimiter=100000: Pythagorean Triples=64741 including primitives=7026 Time=738, Collections: total=0 string=0 block=0 Under perimiter=1000000: Pythagorean Triples=808950 including primitives=70229 Time=12454, Collections: total=0 string=0 block=0 Under perimiter=10000000: Pythagorean Triples=9706567 including primitives=702309 Time=560625, Collections: total=16 string=8 block=8
J
Brute force approach:
<lang j>pytr=: 3 :0
r=. i. 0 3 for_a. 1 + i. <.(y-1)%3 do. b=. 1 + a + i. <.(y%2)-3*a%2 c=. a +&.*: b keep=. (c = <.c) *. y >: a+b+c if. 1 e. keep do. r=. r, a,.b ,.&(keep&#) c end. end. (,.~ prim"1)r
)
prim=: 1 = 2 +./@{. |:</lang>
Example use:
First column indicates whether the triple is primitive, and the remaining three columns are a, b and c.
<lang j> pytr 100 1 3 4 5 1 5 12 13 0 6 8 10 1 7 24 25 1 8 15 17 0 9 12 15 1 9 40 41 0 10 24 26 0 12 16 20 1 12 35 37 0 15 20 25 0 15 36 39 0 16 30 34 0 18 24 30 1 20 21 29 0 21 28 35 0 24 32 40
(# , [: {. +/) pytr 10
0 0
(# , [: {. +/) pytr 100
17 7
(# , [: {. +/) pytr 1000
325 70
(# , [: {. +/) pytr 10000
4858 703</lang>
pytr 10000 takes 4 seconds on this laptop, and time to complete grows with square of perimeter, so pytr 1e6 should take something like 11 hours using this algorithm on this machine.
A slightly smarter approach:
<lang j>trips=:3 :0
'm n'=. |:(#~ 1 = 2 | +/"1)(#~ >/"1) ,/ ,"0/~ }. i. <. %: y prim=. (#~ 1 = 2 +./@{. |:) (#~ y >: +/"1)m (-&*: ,. +:@* ,. +&*:) n /:~ ; <@(,.~ # {. 1:)@(*/~ 1 + y i.@<.@% +/)"1 prim
)</lang>
usage for trips is the same as for pytr. Thus:
<lang j> (# , 1 {. +/) trips 10 0 0
(# , 1 {. +/) trips 100
17 7
(# , 1 {. +/) trips 1000
325 70
(# , 1 {. +/) trips 10000
4858 703
(# , 1 {. +/) trips 100000
64741 7026
(# , 1 {. +/) trips 1000000
808950 70229
(# , 1 {. +/) trips 10000000
9706567 702309</lang>
The last line took about 16 seconds.
That said, we do not actually have to generate all the triples, we just need to count them. Thus:
<lang j>trc=:3 :0
'm n'=. |:(#~ 1 = 2 | +/"1)(#~ >/"1) ,/ ,"0/~ }. i. <. %: y <.y%+/"1 (#~ 1 = 2 +./@{. |:) (#~ y >: +/"1)m (-&*: ,. +:@* ,. +&*:) n
)</lang>
The result is a list of positive integers, one number for each primitive triple which fits within the limit, giving the number of triples which are multiples of that primitive triple whose perimeter is no greater than the limiting perimeter.
<lang> (#,+/)trc 1e8 7023027 113236940</lang>
But note that J's memory footprint reached 6.7GB during the computation, so to compute larger values the computation would have to be broken up into reasonable sized blocks.
Java
Theoretically, this can go "forever", but it takes a while, so only the minimum is shown. Luckily, BigInteger
has a GCD method built in.
<lang java> import java.math.BigInteger; import static java.math.BigInteger.ONE;
public class PythTrip{
public static void main(String[] args){ long tripCount = 0, primCount = 0;
//change this to whatever perimeter limit you want;the RAM's the limit BigInteger periLimit = BigInteger.valueOf(100), peri2 = periLimit.divide(BigInteger.valueOf(2)), peri3 = periLimit.divide(BigInteger.valueOf(3));
for(BigInteger a = ONE; a.compareTo(peri3) < 0; a = a.add(ONE)){ BigInteger aa = a.multiply(a); for(BigInteger b = a.add(ONE); b.compareTo(peri2) < 0; b = b.add(ONE)){ BigInteger bb = b.multiply(b); BigInteger ab = a.add(b); BigInteger aabb = aa.add(bb); for(BigInteger c = b.add(ONE); c.compareTo(peri2) < 0; c = c.add(ONE)){
int compare = aabb.compareTo(c.multiply(c)); //if a+b+c > periLimit if(ab.add(c).compareTo(periLimit) > 0){ break; } //if a^2 + b^2 != c^2 if(compare < 0){ break; }else if (compare == 0){ tripCount++; System.out.print(a + ", " + b + ", " + c);
//does binary GCD under the hood if(a.gcd(b).equals(ONE)){ System.out.print(" primitive"); primCount++; } System.out.println(); } } } } System.out.println("Up to a perimeter of " + periLimit + ", there are " + tripCount + " triples, of which " + primCount + " are primitive."); }
}</lang> Output:
3, 4, 5 primitive 5, 12, 13 primitive 6, 8, 10 7, 24, 25 primitive 8, 15, 17 primitive 9, 12, 15 9, 40, 41 primitive 10, 24, 26 12, 16, 20 12, 35, 37 primitive 15, 20, 25 15, 36, 39 16, 30, 34 18, 24, 30 20, 21, 29 primitive 21, 28, 35 24, 32, 40 Up to a perimeter of 100, there are 17 triples, of which 7 are primitive.
Perl 6
This is a fairly naive brute force implementation that is not really practical for large perimeter limits. 100 is no problem. 1000 is slow. 10000 is glacial.
Works with Rakudo 11.06.
<lang perl6>my %trips; my $limit = 100;
for 3 .. $limit/2 -> $c {
for 1 .. $c-1 -> $a { my $b = ($c ** 2 - $a **2).sqrt; last if $c + $a + $b > $limit; if $b == $b.Int { my $key = ~($a, $b, $c).sort; next if %trips.exists($key); %trips{$key} = ([gcd] $c, $a, $b.Int) > 1 ?? 0 !! 1; } }
}
say "There are {+%trips} Pythagorean Triples with a perimeter less than $limit,"
~" of which {[+] %trips.values} are primitive.";
for %trips.keys.sort( {$^a.lc.subst(/(\d+)/,->$/{0~$0.chars.chr~$0},:g)} ) -> $k {
say $k.fmt("%14s"), %trips{$k} ?? ' - primitive' !! ;
}</lang>
There are 17 Pythagorean Triples with a perimeter less than 100, of which 7 are primitive. 3 4 5 - primitive 5 12 13 - primitive 6 8 10 7 24 25 - primitive 8 15 17 - primitive 9 12 15 9 40 41 - primitive 10 24 26 12 16 20 12 35 37 - primitive 15 20 25 15 36 39 16 30 34 18 24 30 20 21 29 - primitive 21 28 35 24 32 40
Here's a much faster version. Hint, "oyako" is Japanese for "parent/child". :-)
<lang perl6>sub triples($limit) {
sub oyako($a, $b, $c) { my $perim = $a + $b + $c; return if $perim > $limit; take 1 + ($limit div $perim)i; oyako( $a - 2*$b + 2*$c, 2*$a - $b + 2*$c, 2*$a - 2*$b + 3*$c); oyako( $a + 2*$b + 2*$c, 2*$a + $b + 2*$c, 2*$a + 2*$b + 3*$c); oyako(-$a + 2*$b + 2*$c, -2*$a + $b + 2*$c, -2*$a + 2*$b + 3*$c); }
my $complex = 0i + [+] gather oyako(3,4,5); "$limit => ({$complex.re, $complex.im})";
}
for 10,100,1000 ... * -> $limit {
say triples $limit;</lang>
Output:
10 => (0 0) 100 => (7 17) 1000 => (70 325) 10000 => (703 4858) 100000 => (7026 64741) 1000000 => (70229 808950) 10000000 => (702309 9706567) ^C
Note the cute trick of adding complex numbers to add two numbers in parallel. Also, it will continue on forever, so eventually when you get tired of thrashing (at about 100 million on my computer), you can just stop it.
Here is an alternate version that avoids naming any scalars that can be handled by vector processing instead: <lang perl6>constant @coeff = [[+1, -2, +2], [+2, -1, +2], [+2, -2, +3]],
[[+1, +2, +2], [+2, +1, +2], [+2, +2, +3]], [[-1, +2, +2], [-2, +1, +2], [-2, +2, +3]];
sub triples($limit) {
sub oyako(@trippy) { my $perim = [+] @trippy; return if $perim > $limit; take (1 + ($limit div $perim)i); for @coeff -> @nine { oyako (map -> @three { [+] @three »*« @trippy }, @nine); } return; }
my $complex = 0i + [+] gather oyako([3,4,5]); "$limit => ({$complex.re, $complex.im})";
}
for 10,100,1000 ... * -> $limit {
say triples $limit;
}</lang>
Python
Two methods, the second of which is much faster <lang python>from fractions import gcd
def pt1(maxperimeter=100):
- Naive method
trips = [] for a in range(1, maxperimeter): aa = a*a for b in range(a, maxperimeter-a+1): bb = b*b for c in range(b, maxperimeter-b-a+1): cc = c*c if a+b+c > maxperimeter or cc > aa + bb: break if aa + bb == cc: trips.append((a,b,c, gcd(a, b) == 1)) return trips
def pytrip(trip=(3,4,5),perim=100, prim=1):
a0, b0, c0 = a, b, c = sorted(trip) t, firstprim = set(), prim>0 while a + b + c <= perim: t.add((a, b, c, firstprim>0)) a, b, c, firstprim = a+a0, b+b0, c+c0, False # t2 = set() for a, b, c, firstprim in t: a2, a5, b2, b5, c2, c3, c7 = a*2, a*5, b*2, b*5, c*2, c*3, c*7 if a5 - b5 + c7 <= perim: t2 |= pytrip(( a - b2 + c2, a2 - b + c2, a2 - b2 + c3), perim, firstprim) if a5 + b5 + c7 <= perim: t2 |= pytrip(( a + b2 + c2, a2 + b + c2, a2 + b2 + c3), perim, firstprim) if -a5 + b5 + c7 <= perim: t2 |= pytrip((-a + b2 + c2, -a2 + b + c2, -a2 + b2 + c3), perim, firstprim) return t | t2
def pt2(maxperimeter=100):
- Parent/child relationship method:
- http://en.wikipedia.org/wiki/Formulas_for_generating_Pythagorean_triples#XI.
trips = pytrip((3,4,5), maxperimeter, 1) return trips
def printit(maxperimeter=100, pt=pt1):
trips = pt(maxperimeter) print(" Up to a perimeter of %i there are %i triples, of which %i are primitive" % (maxperimeter, len(trips), len([prim for a,b,c,prim in trips if prim])))
for algo, mn, mx in ((pt1, 250, 2500), (pt2, 500, 20000)):
print(algo.__doc__) for maxperimeter in range(mn, mx+1, mn): printit(maxperimeter, algo)
</lang>
- Output
# Naive method Up to a perimeter of 250 there are 56 triples, of which 18 are primitive Up to a perimeter of 500 there are 137 triples, of which 35 are primitive Up to a perimeter of 750 there are 227 triples, of which 52 are primitive Up to a perimeter of 1000 there are 325 triples, of which 70 are primitive Up to a perimeter of 1250 there are 425 triples, of which 88 are primitive Up to a perimeter of 1500 there are 527 triples, of which 104 are primitive Up to a perimeter of 1750 there are 637 triples, of which 123 are primitive Up to a perimeter of 2000 there are 744 triples, of which 140 are primitive Up to a perimeter of 2250 there are 858 triples, of which 156 are primitive Up to a perimeter of 2500 there are 969 triples, of which 175 are primitive # Parent/child relationship method: # http://en.wikipedia.org/wiki/Formulas_for_generating_Pythagorean_triples#XI. Up to a perimeter of 500 there are 137 triples, of which 35 are primitive Up to a perimeter of 1000 there are 325 triples, of which 70 are primitive Up to a perimeter of 1500 there are 527 triples, of which 104 are primitive Up to a perimeter of 2000 there are 744 triples, of which 140 are primitive Up to a perimeter of 2500 there are 969 triples, of which 175 are primitive Up to a perimeter of 3000 there are 1204 triples, of which 211 are primitive Up to a perimeter of 3500 there are 1443 triples, of which 245 are primitive Up to a perimeter of 4000 there are 1687 triples, of which 280 are primitive Up to a perimeter of 4500 there are 1931 triples, of which 314 are primitive Up to a perimeter of 5000 there are 2184 triples, of which 349 are primitive Up to a perimeter of 5500 there are 2442 triples, of which 385 are primitive Up to a perimeter of 6000 there are 2701 triples, of which 422 are primitive Up to a perimeter of 6500 there are 2963 triples, of which 457 are primitive Up to a perimeter of 7000 there are 3224 triples, of which 492 are primitive Up to a perimeter of 7500 there are 3491 triples, of which 527 are primitive Up to a perimeter of 8000 there are 3763 triples, of which 560 are primitive Up to a perimeter of 8500 there are 4029 triples, of which 597 are primitive Up to a perimeter of 9000 there are 4304 triples, of which 631 are primitive Up to a perimeter of 9500 there are 4577 triples, of which 667 are primitive Up to a perimeter of 10000 there are 4858 triples, of which 703 are primitive Up to a perimeter of 10500 there are 5138 triples, of which 736 are primitive Up to a perimeter of 11000 there are 5414 triples, of which 770 are primitive Up to a perimeter of 11500 there are 5699 triples, of which 804 are primitive Up to a perimeter of 12000 there are 5980 triples, of which 839 are primitive Up to a perimeter of 12500 there are 6263 triples, of which 877 are primitive Up to a perimeter of 13000 there are 6559 triples, of which 913 are primitive Up to a perimeter of 13500 there are 6843 triples, of which 949 are primitive Up to a perimeter of 14000 there are 7129 triples, of which 983 are primitive Up to a perimeter of 14500 there are 7420 triples, of which 1019 are primitive Up to a perimeter of 15000 there are 7714 triples, of which 1055 are primitive Up to a perimeter of 15500 there are 8004 triples, of which 1089 are primitive Up to a perimeter of 16000 there are 8304 triples, of which 1127 are primitive Up to a perimeter of 16500 there are 8595 triples, of which 1159 are primitive Up to a perimeter of 17000 there are 8884 triples, of which 1192 are primitive Up to a perimeter of 17500 there are 9189 triples, of which 1228 are primitive Up to a perimeter of 18000 there are 9484 triples, of which 1264 are primitive Up to a perimeter of 18500 there are 9791 triples, of which 1301 are primitive Up to a perimeter of 19000 there are 10088 triples, of which 1336 are primitive Up to a perimeter of 19500 there are 10388 triples, of which 1373 are primitive Up to a perimeter of 20000 there are 10689 triples, of which 1408 are primitive
Barebone minimum for this task:<lang Python>from sys import setrecursionlimit setrecursionlimit(2000) # 2000 ought to be big enough for everybody
def triples(lim, a = 3, b = 4, c = 5): l = a + b + c if l > lim: return (0, 0) return reduce(lambda x, y: (x[0] + y[0], x[1] + y[1]), [ (1, lim / l), triples(lim, a - 2*b + 2*c, 2*a - b + 2*c, 2*a - 2*b + 3*c), triples(lim, a + 2*b + 2*c, 2*a + b + 2*c, 2*a + 2*b + 3*c), triples(lim, -a + 2*b + 2*c, -2*a + b + 2*c, -2*a + 2*b + 3*c) ])
for peri in [10 ** e for e in range(1, 8)]: print peri, triples(peri)</lang>Output:<lang>10 (0, 0) 100 (7, 17) 1000 (70, 325) 10000 (703, 4858) 100000 (7026, 64741) 1000000 (70229, 808950) 10000000 (702309, 9706567)</lang>