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Maze generation: Difference between revisions

Go solution
m (→‎{{header|Java}}: Use pre for output)
(Go solution)
Line 946:
| | |
+-+-+-+-+-+-+-+-+-+-+</pre>
=={{header|Go}}==
<lang go>package main
 
import (
"bytes"
"fmt"
"math/rand"
"time"
)
type maze struct {
c []byte // cell contents
h []byte // horizontal walls above cells
v []byte // vertical walls to the left of cells
c2 [][]byte // cells by row
h2 [][]byte // horizontal walls by row (ignore first row)
v2 [][]byte // vertical walls by row (ignore first of each column)
}
 
func newMaze(rows, cols int) *maze {
c := make([]byte, rows*cols) // all cells
h := bytes.Repeat([]byte{'-'}, rows*cols) // all horizontal walls
v := bytes.Repeat([]byte{'|'}, rows*cols) // all vertical walls
c2 := make([][]byte, rows) // cells by row
h2 := make([][]byte, rows) // horizontal walls by row
v2 := make([][]byte, rows) // vertical walls by row
for i := range h2 {
c2[i] = c[i*cols : (i+1)*cols]
h2[i] = h[i*cols : (i+1)*cols]
v2[i] = v[i*cols : (i+1)*cols]
}
return &maze{c, h, v, c2, h2, v2}
}
 
func (m *maze) String() string {
hWall := []byte("+---")
hOpen := []byte("+ ")
vWall := []byte("| ")
vOpen := []byte(" ")
rightCorner := []byte("+\n")
rightWall := []byte("|\n")
var b []byte
// for all rows
for r, hw := range m.h2 {
// draw h walls
for _, h := range hw {
if h == '-' || r == 0 {
b = append(b, hWall...)
} else {
b = append(b, hOpen...)
}
}
b = append(b, rightCorner...)
// draw v walls
for c, vw := range m.v2[r] {
if vw == '|' || c == 0 {
b = append(b, vWall...)
} else {
b = append(b, vOpen...)
}
// draw cell contents
if m.c2[r][c] != 0 {
b[len(b)-2] = m.c2[r][c]
}
}
b = append(b, rightWall...)
}
// draw bottom edge of maze
for _ = range m.h2[0] {
b = append(b, hWall...)
}
b = append(b, rightCorner...)
return string(b)
}
 
func (m *maze) gen() {
m.g2(rand.Intn(len(m.c2)), rand.Intn(len(m.c2[0])))
}
 
const (
up = iota
dn
rt
lf
)
 
func (m *maze) g2(r, c int) {
m.c2[r][c] = ' '
for _, dir := range rand.Perm(4) {
switch dir {
case up:
if r > 0 && m.c2[r-1][c] == 0 {
m.h2[r][c] = 0
m.g2(r-1, c)
}
case lf:
if c > 0 && m.c2[r][c-1] == 0 {
m.v2[r][c] = 0
m.g2(r, c-1)
}
case dn:
if r < len(m.c2)-1 && m.c2[r+1][c] == 0 {
m.h2[r+1][c] = 0
m.g2(r+1, c)
}
case rt:
if c < len(m.c2[0])-1 && m.c2[r][c+1] == 0 {
m.v2[r][c+1] = 0
m.g2(r, c+1)
}
}
}
}
 
func main() {
rand.Seed(time.Now().UnixNano())
m := newMaze(4, 6)
m.gen()
fmt.Print(m)
}</lang>
Output:
<pre>
+---+---+---+---+---+---+
| | | |
+ + + +---+ +---+
| | | | |
+ + +---+---+---+ +
| | | |
+ + + +---+---+ +
| | |
+---+---+---+---+---+---+
</pre>
 
=={{header|Haskell}}==
1,707

edits

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