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Knapsack problem/Continuous: Difference between revisions
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→version 1: commented about the program's pedigree.
m (→version 1: reduced clutter in some variable names, simplified the algorithm.) |
m (→version 1: commented about the program's pedigree.) |
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=={{header|REXX}}==
===version 1===
<br>Some amount of code was added to make the output pretty.
<lang rexx>/*REXX program solves the burglar's knapsack (continuous) problem. */
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