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Pangram checker: Difference between revisions
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Line 366:
// Convert to lower case.
transform(s.begin(), s.end(), s.begin(), ::tolower);
// Convert to a sorted sequence of (not necessarily unique) characters.
sort(s.begin(), s.end());
// Is the second sequence a subset of the first sequence?
// Repeated letters in "s" are okay, since it still "includes" the single letter
return includes(s.begin(), s.end(), alphabet.begin(), alphabet.end());
}</lang>
=={{header|Clojure}}==
<lang lisp>(defn pangram? [s]
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