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Sum of Array: Difference between revisions
Undo revision 8210 by Special:Contributions/LpvHw9 (User talk:LpvHw9)
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(Undo revision 8210 by Special:Contributions/LpvHw9 (User talk:LpvHw9)) |
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{{task}}
Compute the sum of the elements of an Array
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$var:=0
For ($i;1;Size of array($list))
$var:=$var
End for
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Sum : Integer := 0;
for I in Int_Array'range loop
Sum := Sum
end loop;
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repeat with i in array
-- very important -- list index starts at 1 not 0
set product to product
end repeat
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50 REM Find the sum of elements in the array
60 SUM = 0
70 FOR I = 1 TO 5: SUM = SUM
80 PRINT "The sum is ";SUM
==[[C plus plus|C
[[Category:C plus plus]]
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int list[] = { 1, 2, 3 } ;
int sum = 0 ;
for( int i = 0 ; i < 3 ; i
{
sum
}
}
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{
int list[] = { 1, 2, 3 } ;
std::accumulate(list, list
return 0;
}
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{
T accum = 0;
for (unsigned i=0; i<n; i
accum
return accum;
}
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int arg_length = arg.Length;
for( int i = 0; i < arg_length; i
value
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int sum = 0;
int[] arg = { 1, 2, 3, 4, 5 };
foreach (int value in arg) sum
==[[Clean]]==
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(defparameter *data* #(1 2 3 4 5))
(reduce #'
==[[Delphi]]==
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pragma.enable("accumulator")
accum 0 for x in [1,2,3,4,5] { _
==[[Erlang]]==
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0;
sum_rec([Head|Tail]) ->
Head
% tail-recursive definition:
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Acc;
sum_tail([Head|Tail], Acc) ->
sum_tail(Tail, Head
==[[Forth]]==
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: sum ( addr cnt -- n )
0 -rot
cells bounds do i @
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dim sum as integer = 0
for index as integer = lbound(array) to ubound(array)
sum
next
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let values = [1..10]
sum values -- the easy way
foldl (
==[[IDL]]==
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int[] arg = new int[] { 1,2,3,4,5 };
for (int i: arg)
value
==[[JavaScript]]==
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var sum = 0;
for(var i in array)
sum
==[[Perl]]==
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my $var;
my @list = (1, 2, 3);
$var
Alternate
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my $acc = 0;
my @list = qw(1 2 3)
map { $acc
==[[PHP]]==
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lvars i, sum = 0, ar = {1 2 3 4 5 6 7 8 9};
for i from 1 to length(ar) do
ar(i)
endfor;
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lvars sum = 0, ar = {1 2 3 4 5 6 7 8 9};
appdata(ar, procedure(x); x
==[[Prolog]]==
[[Category:Prolog]]
sum([],0).
sum([H|T],X) :- sum(T,Y), X is H
test
:- sum([1,2,3,4,5,6,7,8,9],X).
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ary = [1,2,3,4,5]
sum = ary.inject{|currentSum,element|currentSum
# => 15
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[[Category:Scala]]
val array = Array(1,2,3,4,5)
val sum = array.foldLeft(0)(_
This is a shortcut for
val sum = array.foldLeft(0){(currentSum, element) => currentSum
==[[Seed7]]==
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begin
for value range valueArray do
sum
end for;
end func;
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val array = [1,2,3,4,5];
foldl op
==[[Tcl]]==
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Assuming the values are in a list named <tt>listname</tt>:
set result [expr [join $listname
==[[Toka]]==
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[ ( array size -- sum )
>r 0 r> [ over i swap get-element
==[[UNIX Shell]]==
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list="1 2 3"
for n in $list
do sum="$(($sum
done
echo $sum
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sum=0
for n
do sum="$(($sum
done
echo $sum
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sum=0
while read n
do sum="$(($sum
done
echo $sum
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SUM=0;
for i in $LIST; do
SUM=$[$SUM
done;
echo $SUM
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