Set: Difference between revisions

4,093 bytes added ,  3 years ago
add FreeBASIC
(Added Wren)
(add FreeBASIC)
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i{ 6 5 7 } i{ 5 6 7 } set= . -1 ok
</lang>
 
=={{header|FreeBASIC}}==
<lang freebasic>function is_in( N as integer, S() as integer ) as boolean
'test if the value N is in the set S
for i as integer = 0 to ubound(S)
if N=S(i) then return true
next i
return false
end function
 
sub add_to_set( N as integer, S() as integer )
'adds the element N to the set S
if is_in( N, S() ) then return
dim as integer k = ubound(S)
redim preserve S(0 to k+1)
S(k+1)=N
end sub
 
sub setunion( S() as integer, T() as integer, U() as integer )
'makes U() the union of the sets S and T
dim as integer k = ubound(S)
redim U(-1)
for i as integer = 0 to k
add_to_set( S(i), U() )
next i
k = ubound(T)
for i as integer = 0 to k
if not is_in( T(i), U() ) then
add_to_set( T(i), U() )
end if
next i
end sub
 
sub setintersect( S() as integer, T() as integer, U() as integer )
'makes U() the intersection of the sets S and T
dim as integer k = ubound(S)
redim U(-1)
for i as integer = 0 to k
if is_in(S(i), T()) then add_to_set( S(i), U() )
next i
end sub
 
sub setsubtract( S() as integer, T() as integer, U() as integer )
'makes U() the difference of the sets S and T
dim as integer k = ubound(S)
redim U(-1)
for i as integer = 0 to k
if not is_in(S(i), T()) then add_to_set( S(i), U() )
next i
end sub
 
function is_subset( S() as integer, T() as integer ) as boolean
for i as integer = 0 to ubound(S)
if not is_in( S(i), T() ) then return false
next i
return true
end function
 
function is_equal( S() as integer, T() as integer ) as boolean
if not is_subset( S(), T() ) then return false
if not is_subset( T(), S() ) then return false
return true
end function
 
function is_proper_subset( S() as integer, T() as integer ) as boolean
if not is_subset( S(), T() ) then return false
if is_equal( S(), T() ) then return false
return true
end function
 
sub show_set( L() as integer )
'display a set
dim as integer num = ubound(L)
if num=-1 then
print "[]"
return
end if
print "[";
for i as integer = 0 to num-1
print str(L(i))+", ";
next i
print str(L(num))+"]"
end sub
 
'sets are created by making an empty array
redim as integer S1(-1), S2(-1), S3(-1), S4(-1), S5(-1)
'and populated by adding elements one-by-one
add_to_set( 20, S1() ) : add_to_set( 30, S1() )
add_to_set( 40, S1() ) : add_to_set( 50, S1() )
add_to_set( 19, S2() ) : add_to_set( 20, S2() )
add_to_set( 21, S2() ) : add_to_set( 22, S2() )
add_to_set( 22, S3() ) : add_to_set( 21, S3() )
add_to_set( 19, S3() ) : add_to_set( 20, S3() )
add_to_set( 21, S3() ) ' attempt to add a number that's already in the set
add_to_set( 21, S4() )
print "S1 ",
show_set S1()
print "S2 ",
show_set S2()
print "S3 ",
show_set S3()
print "S4 ",
show_set S4()
print "S5 ",
show_set S5()
print "----"
redim as integer S_U(-1)
setunion S1(), S2(), S_U()
print "S1 U S2 ",
show_set S_U()
redim as integer S_U(-1)
setintersect S1(), S2(), S_U()
print "S1 n S2 ",
show_set S_U()
redim as integer S_U(-1)
setsubtract S1(), S2(), S_U()
print "S1 \ S2 ",
show_set S_U()
redim as integer S_U(-1)
setsubtract S3(), S1(), S_U()
print "S3 \ S1 ",
show_set S_U()
print "S4 in S3? ", is_subset(S4(), S3())
print "S3 in S4? ", is_subset(S3(), S4())
print "S5 in S3? ", is_subset(S5(), S3()) 'empty set is a subset of every set
print "S2 = S3? ", is_equal(S2(), S3())
print "S4 proper subset of S3? ", is_proper_subset( S4(), S3() )
print "S2 proper subset of S3? ", is_proper_subset( S2(), S3() )</lang>
{{out}}
<pre>
S1 [20, 30, 40, 50]
S2 [19, 20, 21, 22]
S3 [22, 21, 19, 20]
S4 [21]
S5 []
----
S1 U S2 [20, 30, 40, 50, 19, 21, 22]
S1 n S2 [20]
S1 \ S2 [30, 40, 50]
S3 \ S1 [22, 21, 19]
S4 in S3? true
S3 in S4? false
S5 in S3? true
S2 = S3? true
S4 proper subset of S3? true
S2 proper subset of S3? false</pre>
 
=={{header|Frink}}==
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